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1370 LearnersLast updated on November 25, 2025

Permutations refer to different ways of arranging objects in a specific order. It is the rearrangement of a set of items in a specific linear order. The symbol nPr is used to indicate the number of permutations of n distinct objects, taken r at a time. In this topic, let's learn about permutations in detail.
A permutation is an arrangement in which the order of the items matters.
Consider an example in which five chairs are available, and three people need to be seated.
So, the total number of ways to arrange three people in 5 chairs is:
5 × 4 × 3 = 60 ways
Notice that this multiplication can be written using factorials:
\(5 \times 4 \times 3 = \frac{5!}{2!} = \frac{5!}{(5-3)!}\)
In general, when arranging r people in n chairs, the number of permutations is given by:
\(nP_r = \frac{n!}{(n-r)!}\)
Here, let’s see how we can find permutations. The general formula we use to find permutations is:
P(n, r) = n! / (n − r)!
Here, n is the total number of elements in the data set.
r is the total number of selected elements in a specific order.
! is the factorial.
For instance, let's say we have 10 different books and want to select and arrange 2 of them. We can calculate the number of ways to do it using permutations.
Without repetition:
The formula is: nPr = 10! / (10 − 2)! = 10! / 8! = (10 × 9 × 8!) / 8! = 90
So, there are 90 unique ways to arrange 2 books from a set of 10.
With repetition, the formula is:
10\(^2\) = 10 × 10 = 100
Hence, there are 100 ways (with repetition) to arrange 2 books from a set of 10.
Another key concept is factorials, and they are useful in permutations.
For example, the factorial of 8 = 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320.
Permutations has a different form depending on the rules for arranging the object. To understand how arrangements work in various situations, permutations are classified into three main types. Each type follows a different condition about repetition and the uniqueness of objects.
1. Permutation Without Repetition
All objects are different, and no object is used more than once. Each time you choose an object, the number of choices decreases.
The formula is:
\(P(n, r) = n \times (n - 1) \times (n - 2) \times (n - r + 1)\)
This means we are arranging r objects from n distinct objects, and order matters.
2. Permutation With Repetition
Objects can be used again and again. Since repetition is allowed, the number of choices stays the same each time.
The formula is:
\(P_{\text{repetition}}(n, r) = n^r\)
This means each of the r positions can be filled in n ways.
3. Permutation of Multisets
In this type, some objects are repeated or identical. Since some items look the same, we adjust the count to avoid repeating the same arrangement.
A multiset has groups of identical items, and the formula ensures only unique arrangements are counted.
To understand permutations better, it helps to know a few important properties. These properties show how permutation values behave and how they can be simplified or related to each other.
Here are the commonly used properties of permutations:
Permutations and combinations are methods used to determine the number of possible arrangements of elements. So, let's see how they differ from each other.
| Permutation | Combination |
| In permutation, the order of the data is considered. | In combinations, the order of data is not considered. |
| In permutations, elements are selected from a list. | In combination, the data is chosen from a group. |
| The data is specifically arranged. | Here there is a selection of data. |
Understanding permutations that become easier when the ideas are explained using the simple language and real-life examples. These tips help make the concept clearer, more interactive, and easier to apply in different situations.
Students tend to make mistakes when learning inter-related concepts like permutations and combinations. So let’s check out some common mistakes and ways to avoid them when learning permutation.
Now let’s learn how we use permutations in the real world.
In how many ways can 5 different books be arranged on a shelf?
120
To find the permutations, we use the formula n!
Here, n = 5
So n! \(= 5! = 5 × 4 × 3 × 2 × 1 = 120\)
So, we can arrange the books in 120 ways.
How many 3-letter words (with distinct letters) can be formed using the letters A, B, C, D, and E?
Here, we can arrange the given letters into 60 different three-letter words.
To find the number of possibilities of 3-letter arrangements, we find the permutation using the formula:
\(P(n, k) = \frac{n!}{(n - k)!}\)
Here, n = 5 and k = 3
\(P(5, 3) = \frac{5!}{(5-3)!} = \frac{5!}{2!}\)
\(= \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1}\)
Next, cancel out the common terms (2 × 1):
So, \(5 × 4 × 3 = 60 \)
In how many ways can the letters in the word 'GOLD' be arranged?
The word 'gold' can be arranged in 24 different ways.
The word 'GOLD' can be arranged in n! ways.
Here, n = 4 (the word 'GOLD' consists of 4 letters).
So we start with 4 and then multiply 4 by the next smallest number, 3.
\(4 × 3 = 12\)
Again, multiply the result by 2:
\(12 × 2 = 24 \)
Finally, multiply 24 by 1.
\(24 × 1 = 24. \)
So, \(n! = 4! = 4 × 3 × 2 × 1 = 24\)
So, the word 'GOLD' can be arranged in 24 different ways.
In how many ways can 8 athletes be assigned 3 distinct positions in a relay race?
There are 336 ways for 8 athletes to try 3 distinct positions in a relay race.
We use the permutation formula,
\(P(n, k) = \frac{n!}{(n - k)!}\)
Here, n = 8 and k = 3
So, \(P(8, 3) = \frac{8!}{(8-3)!} = \frac{8!}{5!}\)
\(= \frac{8 \times 7 \times 6 \times 5!}{5!}\)
\(= 8 \times 7 \times 6 = 336\)
A locker password consists of 5 distinct digits chosen from 1 to 9. How many passwords can be created?
15,120 passwords can be created.
We use the permutation formula,
\(P(n, k) = \frac{n!}{(n - k)!}\)
Here, n = 9 and k = 5
So, \(P(9, 5) = \frac{9!}{(9-5)!} = \frac{9!}{4!}\)
\(= \frac{9 \times 8 \times 7 \times 6 \times 5 \times 4!}{4!}\)
\(= 9 × 8 × 7 × 6 × 5 = 15,120.\)
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!






