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1250 LearnersLast updated on November 28, 2025

The mode is a measure of central tendency. The mode of grouped data is the most frequently occurring value within a dataset, which is grouped as class intervals. Since individual data points are not available, the mode is estimated using the modal class. This method provides an appropriate mode, offering insights into the most common data range. We will learn more about the mode of grouped data in this article.
The mode of grouped data is the most frequently occurring value within class intervals, estimated using interpolation. It lies in the modal class and is calculated using the following formula:
When we look for the mode in grouped data, we are essentially trying to pinpoint exactly where the "peak" of the histogram is. Since the data is grouped into buckets (intervals), we know which bucket is the highest, but we need a formula to find the specific number inside that bucket.
Let us see how to calculate the mode of grouped data using an example
Scenario: We have test scores for 50 students. We want to find the most common score trend.
| Marks (Class Interval) | Students (Frequency) | Role |
| 10 - 20 | 8 | \(f_0\) (Previous) |
| 20 - 30 | 12 | \(f_1\) (The Peak) |
| 30 - 40 | 7 | \(f_2\) (Next) |
(Note: There are other groups, but these are the only three that matter for the mode!)
Step 1: Find the "Popular" Group (Modal Class)
First, scan the Frequency column. Which number is the biggest?
Step 2: Gather Your Ingredients
Now, we need to define the variables for our formula. Think of the frequencies as a timeline: Past (\(f_0\)), Present (\(f_1\)), and Future (\(f_2\)).
Step 3: Plug and Play
Now we just put these numbers into the formula.
\(Mode = L + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h\)
1. Top part (How much higher is the peak than the previous guy?):
12 - 8 = 4
2. Bottom part (How much does the peak stand out from both sides?):
2(12) - 8 - 7
24 - 15 = 9
3. Put it all together:
\(Mode = 20 + \left( \frac{4}{9} \right) \times 10\)
Final Result
\(Mode \approx 24.44\)
Interpretation: Even though the "bucket" was 20-30, the specific center of gravity for the scores—the true mode—is 24.44.
To find the mode of grouped data, we must follow the below-mentioned steps:
| Class Interval (Marks) | Frequency (No. of Students) |
| 0 - 10 | 5 |
| 10 - 20 | 10 |
| 20 - 30 | 25 |
| 30 - 40 | 15 |
| 40 - 50 | 5 |
Step 1: Find the modal class, which is the class interval with the highest frequency.
Step 2: To find the modal class, we should calculate the difference between the upper and the lower limit.
(Note: In statistics, this difference represents the class size, denoted as h.)
Step 3: Use the mode formula.
\(Mode = L + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h\)
First, identify the remaining variables based on the Modal Class (20 - 30):
Now, substitute the values into the equation:
\(Mode = 20 + \left( \frac{25 - 10}{2(25) - 10 - 15} \right) \times 10\)
1. Simplify the numerator:
25 - 10 = 15
2. Simplify the denominator:
50 - 10 - 15 = 25
3. Calculate the final value:
\(Mode = 20 + \left( \frac{15}{25} \right) \times 10\)
\(Mode = 20 + (0.6 \times 10)\)
\(Mode = 20 + 6\)
Final Answer:
Mode = 26
The formula for mode of grouped data is given below:
\(Mode = L + ({(f1 − f0) \over (2f1 − f0 − f2)}) × h\)
Where,


To derive the formula for mode of grouped data, we must follow the below-mentioned steps:
Step 1: Define the Key Variables
Consider a frequency distribution table with the following variables:
Step 2: Understanding the Frequency Change Around the Mode
Since the mode is the most frequently occurring value, it must be inside the modal class, where the highest frequency occurs. However, within this class, we assume the frequency increases linearly from the previous class and then decreases towards the next class.
Step 3: Assumption of Linear Interpolation
Using the proportional reasoning within the modal class, we assume that:
Mode − Lh = (f1 − f0) / (f1 − f0) + (f1 − f2)
Rearranging to solve for mode:
Mode = L + ((f1 − f0) / (2f1 − f0 − f2)) × h
Step 4: Explanation of Each Term
Here are the definitions and differences between modal class and mode of grouped data.
The Modal Class is simply the class interval (group) that has the highest frequency.
In a set of grouped data, you cannot immediately see the specific single number that appears most often. Instead, you look for the group where the data is most dense.
The Mode is the specific value inside the modal class that represents the highest peak of the distribution.
Since grouped data is aggregated into ranges, we don't know the exact raw values. Therefore, the mode for grouped data is an estimate calculated using the formula. It pinpoints exactly where the "peak" of the histogram would be within that modal class.
| Feature | Modal Class | Mode |
| What is it? | A range or interval (e.g., 20-30). | A specific number (e.g., 24.44). |
| What does it represent? | The group with the most data points. | The estimated point of maximum frequency. |
| Calculation | Found by inspection (just looking). | Found using the formula \(L + (\dots) \times h\). |
The concept of mode of grouped data can often feel confusing for students because it moves away from simply "counting the most frequent number" to estimating a value using a formula.
Students tend to make some mistakes while solving problems related to mode of grouped data. Let us now see the different types of mistakes students make and their solutions.
The mode of grouped data have numerous applications across various fields. Let us explore how the mode of grouped data is used in different areas:
Business and marketing
We use the mode of grouped data in business and marketing, where retailers analyze sales data to determine the most frequently purchased products. Companies use mode to identify the common customer preferences. Stores use mode to track the time intervals with the highest footfall to optimize staffing.
Education
We use the mode of grouped data in education, where schools and universities use mode to determine the most frequent grade range. The mode also helps teachers in finding the most frequent attendance range.
Healthcare and medicine
In healthcare and medicine, medical researchers use mode to determine the age group which is most affected by a disease. Pharmaceutical companies use mode to track the most frequently prescribed drug doses for specific conditions.
For the given distribution below, find the mode:
|
Class Interval |
Frequency |
|
10-20 |
5 |
|
20-30 |
8 |
|
30-40 |
12 |
|
40-50 |
7 |
The mode is approximately 34.44.
Identify the values:
Modal class: 30-40 (highest frequency, f1 = 12)
L = 30
f0 = 8 (frequency for 20-30)
f2 = 7 (frequency for 40-50)
h = 10
\(\text{Mode} = 30 + \frac{(12 - 8)}{(2(12) - 8 - 7)} \times 10 \)
\(= 30 + \frac{4}{24 - 15} \times 10 \)
= 30 + (4/9) × 10
= 30 + 4.44 = 34.44.
Find the mode for the following data:
|
Class Interval |
Frequency |
|
0-9 |
5 |
|
10-19 |
12 |
|
20-29 |
8 |
|
30-39 |
3 |
The mode is 16.36
The highest frequency is 12, so the modal class is 10–19.
Here,
L = 10
fm = 12
f1 = 5
f2 = 8
h = 10
\(\text{Mode} = 10 + \frac{12 - 5}{2(12) - 5 - 8} \times 10\)
\(\text{Mode} = 10 + \frac{7}{24 - 13} \times 10\)
\(= 10 + \frac{7}{11} \times 10\)
\(= 10 + 6.36 = \mathbf{16.36}\)
Therefore, mode is 16.36
Find the mode for the following data:
|
Class Interval |
Frequency |
|
0-4 |
2 |
|
5-9 |
7 |
|
10-14 |
15 |
|
15-19 |
6 |
Mode = 12.35
Modal class = 10–14 (highest frequency = 15)
L = 10
fm = 15
f1 = 7
f2 = 6
h = 5
\({Mode} = 10 + \frac{15 - 7}{2(15) - 7 - 6} \times 5\)
\(= 10 + \frac{8}{30 - 13} \times 5\)
\(= 10 + \frac{8}{17} \times 5\)
\(= 10 + 2.35 = \mathbf{12.35}\)
Find the mode for the following distribution:
|
Class Interval |
Frequency |
|
0-9 |
4 |
|
10-19 |
9 |
|
20-29 |
7 |
Mode = 17.14
Modal class = 10–19
L = 10
fm = 9
f1 = 4
f2 = 7
h = 10
\({Mode} = 10 + \frac{9 - 4}{2(9) - 4 - 7} \times 10\)
\(= 10 + \frac{5}{18 - 11} \times 10 \)
\(= 10 + 7.14 = \mathbf{17.14}\)
Find the mode for the distribution given below:
|
Class Interval |
Frequency |
|
0-19 |
10 |
|
20-39 |
22 |
|
40-59 |
8 |
Mode = 29.23
Modal class = 20–39
L = 20
fm = 22
f1 = 10
f2 = 8
h = 20
\({Mode} = 20 + \frac{22 - 10}{2(22) - 10 - 8} \times 20\)
\(= 20 + \frac{12}{44 - 18} \times 20\)
\(= 20 + \frac{12}{26} \times 20\)
\(= 20 + 9.23 = \mathbf{29.23}\)
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!






