Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 10 and 7.
The greatest common factor of 10 and 7 is 1. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 10 and 7, a few methods are described below:
Steps to find the GCF of 10 and 7 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 10 = 1, 2, 5, 10.
Factors of 7 = 1, 7.
Step 2: Now, identify the common factors of them
Common factor of 10 and 7: 1.
Step 3: Choose the largest factor
The largest factor that both numbers have is 1.
The GCF of 10 and 7 is 1.
To find the GCF of 10 and 7 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 10: 10 = 2 × 5
Prime Factors of 7: 7 = 7 (7 is a prime number)
Step 2: Now, identify the common prime factors
There are no common prime factors.
Step 3: Multiply the common prime factors
Since there are no common prime factors, the GCF is 1.
The Greatest Common Factor of 10 and 7 is 1.
Find the GCF of 10 and 7 using the Division Method or Euclidean Algorithm Method, follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 10 by 7
10 ÷ 7 = 1 (quotient), The remainder is calculated as 10 − (7 × 1) = 3
The remainder is 3, not zero, so continue the process
Step 2: Now divide the previous divisor (7) by the previous remainder (3)
Divide 7 by 3
7 ÷ 3 = 2 (quotient), remainder = 7 − (3 × 2) = 1
Step 3: Now divide the previous divisor (3) by the previous remainder (1)
Divide 3 by 1
3 ÷ 1 = 3 (quotient), remainder = 3 − (1 × 3) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 10 and 7 is 1.
Finding GCF of 10 and 7 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 10 apples and 7 oranges. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find GCF of 10 and 7.
GCF of 10 and 7 is 1.
There is only 1 group with 10 apples and 7 oranges.
As the GCF of 10 and 7 is 1, the teacher can only make 1 group.
All the apples and oranges remain in that one group as they cannot be further divided into equal sets.
A school has 10 benches and 7 desks. They want to arrange them in rows with the same number of benches and desks in each row, using the largest possible number of benches and desks per row. How many benches and desks will be in each row?
GCF of 10 and 7 is 1.
So each row will have 1 bench and 1 desk.
There are 10 benches and 7 desks.
To find the total number of benches and desks in each row, we should find the GCF of 10 and 7.
There will be 1 bench and 1 desk in each row.
A tailor has 10 meters of blue fabric and 7 meters of red fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 10 and 7
The GCF of 10 and 7 is 1.
Each piece of fabric is 1 meter long.
For calculating the longest length of the fabric first we need to calculate the GCF of 10 and 7 which is 1.
The length of each piece of the fabric will be 1 meter.
A carpenter has two wooden planks, one 10 cm long and the other 7 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 10 and 7 is 1.
The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 10 cm and 7 cm, respectively, we have to find the GCF of 10 and 7, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 10 and ‘a’ is 1, and the LCM is 70, find ‘a’.
The value of ‘a’ is 7.
GCF × LCM = product of the numbers
1 × 70 = 10 × a
70 = 10a
a = 70 ÷ 10 = 7
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.