101 LearnersLast updated on May 26th, 2025
Factors of 1985
Factors are the numbers that divide any given number evenly without remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 1985, how they are used in real life, and the tips to learn them quickly.
What are the Factors of 1985?
The numbers that divide 1985 evenly are known as factors of 1985.
A factor of 1985 is a number that divides the number without remainder.
The factors of 1985 are 1, 5, 397, and 1985.
Negative factors of 1985: -1, -5, -397, and -1985.
Prime factors of 1985: 5 and 397.
Prime factorization of 1985: 5 × 397.
The sum of factors of 1985: 1 + 5 + 397 + 1985 = 2388
How to Find Factors of 1985?
Factors can be found using different methods. Mentioned below are some commonly used methods:
- Finding factors using multiplication
- Finding factors using division method
- Prime factors and Prime factorization
Finding Factors Using Multiplication
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 1985. Identifying the numbers which are multiplied to get the number 1985 is the multiplication method.
Step 1: Multiply 1985 by 1, 1985 × 1 = 1985.
Step 2: Check for other numbers that give 1985 after multiplying 5 × 397 = 1985
Therefore, the positive factor pairs of 1985 are: (1, 1985) and (5, 397).
All these factor pairs result in 1985.
For every positive factor, there is a negative factor.
Finding Factors Using Division Method
Dividing the given numbers with whole numbers until the remainder becomes zero and listing out the numbers which result as whole numbers as factors. Factors can be calculated by following a simple division method
Step 1: Divide 1985 by 1, 1985 ÷ 1 = 1985.
Step 2: Continue dividing 1985 by the numbers until the remainder becomes 0.
1985 ÷ 1 = 1985
1985 ÷ 5 = 397
Therefore, the factors of 1985 are: 1, 5, 397, and 1985.
Prime Factors and Prime Factorization
The factors can be found by dividing it with prime numbers. We can find the prime factors using the following methods:
- Using prime factorization
- Using factor tree
Using Prime Factorization: In this process, prime factors of 1985 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
1985 ÷ 5 = 397
397 ÷ 397 = 1
The prime factors of 1985 are 5 and 397.
The prime factorization of 1985 is: 5 × 397.
Factor Tree
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows
Step 1: Firstly, 1985 is divided by 5 to get 397.
Step 2: Now divide 397 by itself to get 1. Here, 397 is a prime number and cannot be divided further.
So, the prime factorization of 1985 is: 5 × 397.
Factor Pairs: Two numbers that are multiplied to give a specific number are called factor pairs. Both positive and negative factors constitute factor pairs.
Positive factor pairs of 1985: (1, 1985) and (5, 397).
Negative factor pairs of 1985: (-1, -1985) and (-5, -397).
Common Mistakes and How to Avoid Them in Factors of 1985
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
Mistake 1
Forgetting the number itself and 1 is a factor
Children might forget to add the given number itself and 1 as a factor. The number itself and 1 are the factors for every number. Always remember to include 1 and the number itself.
For example, in factors of 1985, 1 and 1985 are also factors.
Factors of 1985 Examples
Problem 1
There are 5 teams and 1985 points to be distributed equally. How many points will each team get?
Each team will get 397 points.
Explanation
To divide the points equally, we need to divide the total points by the number of teams.
1985/5 = 397
Problem 2
A rectangular garden has an area of 1985 square meters and a length of 397 meters. Find the width.
The width is 5 meters.
Explanation
To find the width of the garden, we use the formula,
Area = length × width
1985 = 397 × width
To find the value of width, we need to shift 397 to the left side.
1985/397 = width
Width = 5.
Problem 3
A concert hall has 1985 seats and 397 rows. How many seats are in each row?
Each row will have 5 seats.
Explanation
To find the seats in each row, divide the total seats by the number of rows.
1985/397 = 5
Problem 4
1985 apples need to be packed into boxes, with each box holding 5 apples. How many boxes are needed?
397 boxes are needed.
Explanation
Dividing the apples by the number of apples per box gives the number of boxes needed.
1985/5 = 397
Problem 5
A company has 1985 products to distribute equally among 5 stores. How many products will each store receive?
Each store will receive 397 products.
Explanation
Divide total products by the number of stores.
1985/5 = 397
FAQs on Factors of 1985
1.What are the factors of 1985?
2.Mention the prime factors of 1985.
3.Is 1985 a multiple of 5?
4.Mention the factor pairs of 1985?
5.What is the square of 1985?
6.How can children in Thailand use numbers in everyday life to understand Factors of 1985?
7.What are some fun ways kids in Thailand can practice Factors of 1985 with numbers?
8.What role do numbers and Factors of 1985 play in helping children in Thailand develop problem-solving skills?
9.How can families in Thailand create number-rich environments to improve Factors of 1985 skills?
Important Glossaries for Factor of 1985
- Factors: The numbers that divide the given number without leaving a remainder are called factors. For example, the factors of 1985 are 1, 5, 397, and 1985.
- Prime factors: The factors which are prime numbers. For example, 5 and 397 are prime factors of 1985.
- Factor pairs: Two numbers in a pair that are multiplied to give the original number are called factor pairs. For example, the factor pairs of 1985 are (1, 1985) and (5, 397).
- Multiple: A number that can be divided by another number without a remainder. For example, 1985 is a multiple of 5.
- Prime factorization: Breaking down a number into a product of its prime factors. For example, 1985 is broken down into 5 × 397.
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Hiralee Lalitkumar Makwana
About the Author
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
Fun Fact
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