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Last updated on February 18th, 2025
The divisibility rule is a way to find out whether a number is divisible by another number without using the division method. In real life, we can use divisibility rules for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 923.
The divisibility rule for 923 is a method by which we can find out if a number is divisible by 923 or not without using the division method. Check whether 1846 is divisible by 923 with the divisibility rule.
Step 1: Multiply the last digit of the number by 2, here in 1846, 6 is the last digit, multiply it by 2. 6 × 2 = 12.
Step 2: Subtract the result from Step 1 from the remaining values, but do not include the last digit. i.e., 184–12 = 172.
Step 3: As it is shown that 172 is not a multiple of 923, the number is not divisible by 923. If the result from step 2 isn't a multiple of 923, then the number isn't divisible by 923.
Learning the divisibility rule will help kids to master division. Let’s learn a few tips and tricks for the divisibility rule of 923.
Memorize the multiples of 923 (923, 1846, 2769, 3692… etc.) to quickly check divisibility. If the result from the subtraction is a multiple of 923, then the number is divisible by 923.
If the result we get after the subtraction is negative, we will avoid the symbol and consider it as positive for checking the divisibility of a number.
Students should keep repeating the divisibility process until they reach a small number that is divisible by 923.
For example: Check if 3692 is divisible by 923 using the divisibility test. Multiply the last digit by 2, i.e., 2 × 2 = 4. Subtract the remaining digits excluding the last digit by 4, 369–4 = 365.
Since 365 is not a multiple of 923, repeat the process. Multiply the last digit by 2, 5 × 2 = 10. Now subtracting 10 from the remaining numbers excluding the last digit, 36–10 = 26. As 26 is not a multiple of 923, 3692 is not divisible by 923.
Students can use the division method as a way to verify and crosscheck their results. This will help them to verify and also learn.
The divisibility rule of 923 helps us to quickly check if the given number is divisible by 923, but common mistakes like calculation errors lead to incorrect calculations. Here we will understand some common mistakes that will help you to understand.
Is 1846 divisible by 923?
Yes, 1846 is divisible by 923.
To check if 1846 is divisible by 923, we use the divisibility rule for 923:
1) Break down the number into two parts: the last three digits, "846", and the preceding part, "1".
2) Multiply "846" by a specific factor (let's say factor 'X') and subtract it from "1". Assume the factor X is derived from a rule for simplification purposes.
3) If the result is zero or a multiple of 923, the original number is divisible by 923. In this case, 846 is exactly half of 1846, so 1846 is divisible by 923.
Check the divisibility rule of 923 for 2769.
Yes, 2769 is divisible by 923.
To verify divisibility of 2769 by 923:
1) Consider the last three digits "769" and the preceding part "2".
2) Multiply "769" by a specific factor (again, assume factor 'Y' for simplicity) and subtract from "2".
3) If the outcome is zero or a multiple of 923, then the number is divisible. Here, 2769 is composed of three times 923, confirming its divisibility.
Is 4615 divisible by 923?
Yes, 4615 is divisible by 923.
To check divisibility for 4615:
1) Take the last three digits "615" and the leading digits "4".
2) Multiply "615" by a divisor-specific factor and subtract it from "4".
3) The result should be zero or a multiple of 923. Since 4615 is five times 923, it is divisible by 923.
Can 3707 be divisible by 923 following the divisibility rule?
No, 3707 is not divisible by 923.
To determine if 3707 is divisible by 923:
1) Separate the last three digits "707" from the first digit "3".
2) Multiply "707" by a chosen factor and subtract from "3".
3) If the result is not zero or a multiple of 923, then it is not divisible. Here, the computation does not result in zero or a multiple of 923, thus 3707 is not divisible by 923.
Check the divisibility rule of 923 for 9230.
Yes, 9230 is divisible by 923.
Checking divisibility for 9230:
1) Take the last three digits "230" and the preceding part "9".
2) Multiply "230" by a specific factor and subtract from "9".
3) If this results in zero or a multiple of 923, then 9230 is divisible by 923. Since 9230 is ten times 923, it is divisible by 923.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.