Last updated on May 26th, 2025
The divisibility rule is a way to find out whether a number is divisible by another number without using the division method. In real life, we can use the divisibility rule for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 105.
The divisibility rule for 105 is a method by which we can find out if a number is divisible by 105 or not without using the division method. A number is divisible by 105 if it is divisible by 3, 5, and 7 (since 105 = 3 × 5 × 7).
Check whether 315 is divisible by 105 using the divisibility rule.
Step 1: Check divisibility by 3. The sum of the digits is 3 + 1 + 5 = 9, which is divisible by 3.
Step 2: Check divisibility by 5. The last digit is 5, which means it is divisible by 5.
Step 3: Check divisibility by 7. Double the last digit and subtract it from the rest of the number: 31 - (5 × 2) = 21, which is a multiple of 7.
Since 315 is divisible by 3, 5, and 7, it is divisible by 105.
Learning the divisibility rules will help kids master division. Let’s learn a few tips and tricks for the divisibility rule of 105.
The divisibility rule of 105 helps us quickly check if a given number is divisible by 105, but common mistakes like calculation errors can lead to incorrect results. Here, we will understand some common mistakes and how to avoid them.
A shipment contains 525 boxes. Is the total number of boxes divisible by 105?
Yes, 525 is divisible by 105.
To check the divisibility of 525 by 105, we need to confirm divisibility by 3, 5, and 7.
1) Check divisibility by 3: Sum of digits is 5 + 2 + 5 = 12, which is divisible by 3.
2) Check divisibility by 5: The last digit is 5, so it is divisible by 5.
3) Check divisibility by 7: Multiply the last digit by 2, 5 × 2 = 10. Subtract from the rest, 52 – 10 = 42, which is divisible by 7.
Since 525 is divisible by 3, 5, and 7, it is divisible by 105.
A farmer has 630 apples and wants to pack them equally into boxes that can hold a number of apples divisible by 105. Can he do this?
Yes, 630 apples can be packed equally into boxes divisible by 105.
For 630 to be divisible by 105, it must be divisible by 3, 5, and 7.
1) Divisibility by 3: Sum of digits is 6 + 3 + 0 = 9, which is divisible by 3.
2) Divisibility by 5: The last digit is 0, so it is divisible by 5.
3) Divisibility by 7: Multiply the last digit by 2, 0 × 2 = 0. Subtract from the rest, 63 – 0 = 63, which is divisible by 7.
Since 630 is divisible by these three numbers, it is divisible by 105.
A concert hall has 840 seats. Are the seats arranged in rows that are divisible by 105?
Yes, 840 seats can be arranged in rows divisible by 105.
To check if 840 is divisible by 105, confirm divisibility by 3, 5, and 7.
1) Divisibility by 3: Sum of digits is 8 + 4 + 0 = 12, which is divisible by 3.
2) Divisibility by 5: The last digit is 0, so it is divisible by 5.
3) Divisibility by 7: Multiply the last digit by 2, 0 × 2 = 0. Subtract from the rest, 84 – 0 = 84, which is divisible by 7.
Thus, 840 is divisible by 105.
A company manufactures 945 widgets each week. Is this weekly production divisible by 105?
Yes, 945 is divisible by 105.
For 945 to be divisible by 105, it must be divisible by 3, 5, and 7.
1) Divisibility by 3: Sum of digits is 9 + 4 + 5 = 18, which is divisible by 3.
2) Divisibility by 5: The last digit is 5, so it is divisible by 5.
3) Divisibility by 7: Multiply the last digit by 2, 5 × 2 = 10. Subtract from the rest, 94 – 10 = 84, which is divisible by 7.
Therefore, 945 is divisible by 105.
There are 1,155 chairs to be set up in a conference hall. Can the chairs be arranged in sections divisible by 105?
Yes, 1,155 can be arranged in sections divisible by 105.
To determine if 1,155 is divisible by 105, we check divisibility by 3, 5, and 7.
1) Divisibility by 3: Sum of digits is 1 + 1 + 5 + 5 = 12, which is divisible by 3.
2) Divisibility by 5: The last digit is 5, so it is divisible by 5.
3) Divisibility by 7: Multiply the last digit by 2, 5 × 2 = 10. Subtract from the rest, 115 – 10 = 105, which is divisible by 7.
Thus, 1,155 is divisible by 105.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.