Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse of a square is a square root. The square root is used in various fields including vehicle design and finance. Here, we will discuss the square root of 4900.
The square root is the inverse of squaring a number. 4900 is a perfect square. The square root of 4900 can be expressed in both radical and exponential forms. In radical form, it is expressed as √4900, whereas in exponential form it is (4900)^(1/2). √4900 = 70, which is a rational number because it can be expressed in the form of p/q, where p and q are integers with q ≠ 0.
For perfect square numbers like 4900, the prime factorization method is often used. We can also use the long division method and approximation method, though they are more common for non-perfect squares. Let us explore these methods:
The product of prime factors is the prime factorization of a number. Let us break down 4900 into its prime factors:
Step 1: Finding the prime factors of 4900
Breaking it down, we get 2 × 2 × 5 × 5 × 7 × 7: 2^2 × 5^2 × 7^2
Step 2: Now that we have found the prime factors of 4900, we make pairs of those prime factors. Since 4900 is a perfect square, the digits of the number can be grouped in pairs. Therefore, the square root of 4900 using prime factorization is possible. Thus, √4900 = √(2^2 × 5^2 × 7^2) = 2 × 5 × 7 = 70.
The long division method can also be used for finding the square root of perfect square numbers. Let us learn how to find the square root using the long division method, step by step:
Step 1: To begin, we need to group the numbers from right to left in pairs. In the case of 4900, we group it as 49 and 00.
Step 2: Now we find a number whose square is less than or equal to 49. The number is 7 because 7 × 7 = 49. The quotient is 7, and the remainder is 0.
Step 3: Now, bring down the next pair of zeros, making it 00.
Step 4: Add the old divisor with the same number, 7 + 7 = 14, which will be our new divisor.
Step 5: Determine a number n such that 14n × n is less than or equal to 00. Here n is 0, because 140 × 0 = 0.
Step 6: Subtracting gives us 0 as the remainder.
Step 7: The quotient is 70, which is the square root of 4900.
The approximation method is straightforward for finding square roots. Let us learn how to find the square root of 4900 using this method:
Step 1: Find the closest perfect squares to √4900. The closest perfect squares are 4900 itself (exact) and no need for approximation.
Step 2: √4900 = 70 since it is a perfect square.
Students often make mistakes while finding square roots, such as forgetting about the negative square root or applying incorrect methods. Let's look at a few common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √4900?
The area of the square is 4900 square units.
The area of a square is calculated as side^2.
The side length is given as √4900.
Area of the square = (√4900) × (√4900) = 70 × 70 = 4900
Therefore, the area of the square box is 4900 square units.
A square-shaped building measuring 4900 square feet is built; if each of its sides is √4900, what will be the square feet of half of the building?
2450 square feet
Since the building is square-shaped, we divide the given area by 2.
Dividing 4900 by 2 gives us 2450.
So, half of the building measures 2450 square feet.
Calculate √4900 × 5.
350
The first step is finding the square root of 4900, which is 70.
The second step is multiplying 70 by 5.
So, 70 × 5 = 350.
What will be the square root of (4900 + 100)?
The square root is 71.
First, find the sum of (4900 + 100) = 5000.
Then find the square root of 5000.
5000 is not a perfect square, but it is close to 4900.
You can approximate it by noting that √4900 = 70 and √5000 is slightly more than 70, approximately 71.
Find the perimeter of the rectangle if its length ‘l’ is √4900 units and the width ‘w’ is 38 units.
We find the perimeter of the rectangle as 216 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√4900 + 38) = 2 × (70 + 38) = 2 × 108 = 216 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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