Last updated on May 27th, 2025
When a number is multiplied by itself thrice, the resultant number is called the cube of a number. Cubing is used in comparing the sizes of objects or things with cubic measurements. In this topic, we shall learn about the cube of 858.
A cube number is a value obtained by raising a number to the power of 3, or by multiplying the number by itself three times. When you cube a positive number, the result is always positive. When you cube a negative number, the result is always negative. This is because a negative number by itself three times results in a negative number. The cube of 858 can be written as 858³, which is the exponential form. Or it can also be written in arithmetic form as, 858 × 858 × 858.
In order to check whether a number is a cube number or not, we can use the following three methods, such as the multiplication method, a factor formula (a³), or by using a calculator. These three methods will help kids to cube the numbers faster and easier without feeling confused or stuck while evaluating the answers. By Multiplication Method Using a Formula Using a Calculator
The multiplication method is a process in mathematics used to find the product of two numbers or quantities by combining them through repeated addition. It is a fundamental operation that forms the basis for more complex mathematical concepts. Step 1: Write down the cube of the given number. 858³ = 858 × 858 × 858 Step 2: You get 631,454,832 as the answer. Hence, the cube of 858 is 631,454,832.
The formula (a + b)³ is a binomial formula for finding the cube of a number. The formula is expanded as a³ + 3a²b + 3ab² + b³. Step 1: Split the number 858 into two parts, as 800 and 58. Let a = 800 and b = 58, so a + b = 858 Step 2: Now, apply the formula (a + b)³ = a³ + 3a²b + 3ab² + b³ Step 3: Calculate each term a³ = 800³ 3a²b = 3 × 800² × 58 3ab² = 3 × 800 × 58² b³ = 58³ Step 4: Add all the terms together: (a + b)³ = a³ + 3a²b + 3ab² + b³ (800 + 58)³ = 800³ + 3 × 800² × 58 + 3 × 800 × 58² + 58³ 858³ = 512,000,000 + 111,360,000 + 80,784,000 + 195,832 858³ = 631,454,832 Step 5: Hence, the cube of 858 is 631,454,832.
To find the cube of 858 using a calculator, input the number 858 and use the cube function (if available) or multiply 858 × 858 × 858. This operation calculates the value of 858³, resulting in 631,454,832. It’s a quick way to determine the cube without manual computation. Step 1: Ensure the calculator is functioning properly. Step 2: Press 8 followed by 5 and then 8 Step 3: If the calculator has a cube function, press it to calculate 858³. Step 4: If there is no cube function on the calculator, simply multiply 858 three times manually. Step 5: The calculator will display 631,454,832.
The cube of any even number is always even, while the cube of any odd number is always odd. The product of two or more perfect cube numbers is always a perfect cube. A perfect cube can always be expressed as the product of three identical groups of equal prime factors.
There are some typical errors that kids might make during the process of cubing a number. Let us take a look at five of the major mistakes that kids might make:
What is the cube and cube root of 858?
The cube of 858 is 631,454,832 and the cube root of 858 is approximately 9.541.
First, let’s find the cube of 858. We know that the cube of a number, such that x³ = y Where x is the given number, and y is the cubed value of that number So, we get 858³ = 631,454,832 Next, we must find the cube root of 858 We know that the cube root of a number ‘x’ is such that ³√x = y Where ‘x’ is the given number, and y is the cube root value of the number So, we get ³√858 ≈ 9.541 Hence the cube of 858 is 631,454,832 and the cube root of 858 is approximately 9.541.
If the side length of the cube is 858 cm, what is the volume?
The volume is 631,454,832 cm³.
Use the volume formula for a cube V = Side³. Substitute 858 for the side length: V = 858³ = 631,454,832 cm³.
How much larger is 858³ than 800³?
858³ – 800³ = 119,454,832.
First find the cube of 858³, that is 631,454,832 Next, find the cube of 800³, which is 512,000,000 Now, find the difference between them using the subtraction method. 631,454,832 – 512,000,000 = 119,454,832 Therefore, 858³ is 119,454,832 larger than 800³.
If a cube with a side length of 858 cm is compared to a cube with a side length of 58 cm, how much larger is the volume of the larger cube?
The volume of the cube with a side length of 858 cm is 631,454,832 cm³.
To find its volume, we multiply the side length by itself three times (since it’s a 3-dimensional object). Cubing 858 means multiplying 858 by itself three times: 858 × 858 = 736,164, and then 736,164 × 858 = 631,454,832. The unit of volume is cubic centimeters (cm³), because we are calculating the space inside the cube. Therefore, the volume of the cube is 631,454,832 cm³.
Estimate the cube 857 using the cube 858.
The cube of 857 is approximately 631,454,832.
First, identify the cube of 858, The cube of 858 is 858³ = 631,454,832. Since 857 is only a tiny bit less than 858, the cube of 857 will be almost the same as the cube of 858. The cube of 857 is approximately 631,454,832 because the difference between 857 and 858 is very small. So, we can approximate the value as 631,454,832.
Binomial Formula: It is an algebraic expression used to expand the powers of a number, written as (a + b)ⁿ, where ‘n’ is a positive integer. The formula is used to find the square and cube of a number. Cube of a Number: Multiplying a number by itself three times is called the cube of a number. Exponential Form: It is a way of expressing numbers using a base and an exponent (or power), where the exponent value indicates how many times the base is multiplied by itself. For example, 2³ represents 2 × 2 × 2 equals 8. Cube Root: The cube root of a number is a value that, when multiplied by itself three times, gives the original number. It is denoted by the radical symbol with a small three (³√). Volume of a Cube: The amount of space occupied by a cube, calculated as the side length raised to the third power or cubed (Side³).
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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