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Last updated on July 4th, 2025

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Imaginary Numbers

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Imaginary numbers were first introduced by Hero of Alexandria and later developed by Gerolamo Cardano. These numbers are used to solve problems involving the square roots of negative numbers. In this topic, the concept of imaginary numbers and their wider applications will be discussed.

Imaginary Numbers for Singaporean Students
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What are Imaginary Numbers?

Imaginary numbers are numbers that, when squared, give negative numbers. In other words, they are the square roots of negative numbers. We get an imaginary number by multiplying a non-zero real number by the imaginary unit “i” (iota), where the value of i is √(– 1) or i2 = –1.

 


For example: 
√(–9) = √9 × √(-1) = 3i
√(– 7) = i √7
The square root of a negative number, for any positive real number x:
√(– x) = i√x 

 


For example: √(–36) = i√36 = 6i
A complex number is expressed as the sum of a real number and an imaginary number.  It has the form a + ib, where ‘a’ and ‘b’ are real numbers and i is the imaginary number.
 

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Geometrical Interpretation of Imaginary Numbers

A complex number (a + bi) can be represented as a point (a, b) on the Argand plane. For example, we represent the complex number 2 – 4i using the point (2, – 4) on the plane. Since an imaginary number bi can also be expressed as 0 + bi, it is represented as (0, b). For a better understanding, let’s look at an example:
 

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What is ‘i’ in Math?

The letter “i” in a complex number (a + ib) is a unique imaginary unit, which is also known as “iota”. Since “i” is not a real number, we represent it on the imaginary axis. Consider ‘i’ as an imaginary unit that moves in a perpendicular direction to the real number line. On the Argand plane, the point (0,1) is used to represent i.

 


(a + ib) is a complex number where the real part “a” moves along the real axis, and the imaginary part “ib” moves “b” units along the imaginary axis. This implies that a + ib represents the point (a, b) in the plane. Let’s look at the representation of i in math:

 

 

  • The value of i can be mathematically represented as: i2 = –1, which means i = √(– 1). 

 

  • Imaginary numbers are called “imaginary” not because they do not exist, but because they do not belong to the real number set.
     
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How to Calculate Imaginary Numbers

To calculate the imaginary numbers, we follow the same methods as real numbers. We will now look at the arithmetic operations performed on imaginary numbers:

 

 

Addition and Subtraction of Imaginary Numbers


We can add or subtract imaginary numbers in the same way as combining like terms in algebra. For example:
5i + 4i = 9i
5i – 4i = i

 

 

Multiplication of Imaginary Numbers


We multiply imaginary numbers using algebraic multiplication rules and the property i2 = -1. 
For example: 
5i × 4i = 20i2 = 20(– 1) = – 20
4i2 × (– 3i3) = – 12i5 = – 12(i2)2i = –12 (– 1)2i = –12i
While multiplying complex numbers, apply the following rules to simplify the powers of i:

 

  • i4k = 1
     
  • i4k + 1 = i
     
  • i4k +2 = –1
     
  • i4k + 3 = -i
     

Here, k is a whole number. This indicates that we can reduce any power of i to one of these four values. Example:

  • i4 = i0 = 1
  • i17 = i1 = i



Division of Imaginary Numbers


To divide imaginary numbers, we apply exponent rules:
am/ an = am — n
To rationalize the denominator, we eliminate i by multiplying the numerator and denominator by i; we use the identity 1/i = –i, which can be expanded as:
1/i = 1/i ˟ i/i = i/i2= i /–1 = –i
For example:
6i/3i = 2
 

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Real-Life Applications of Imaginary Numbers

Imaginary numbers are abstract concepts, but they are applicable in various real-life situations. Let’s see how they are applied in different fields:

 

 

  • Imaginary numbers are used in designing circuits for electronic devices such as mobile phones and computers to improve their signal processing performance.

 

  • These numbers are used in healthcare to enhance the clarity of MRI scans.

 

  • Computers use the imaginary unit (i) in the Fourier transforms, which filter noise and enhance audio signals.

 

  • They are used to analyze the strength of tall buildings or bridge foundations against natural disasters.

 

  • Imaginary numbers are used to improve the quality of communication by reducing errors.
     
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Common Mistakes and How to Avoid Them in Imaginary Numbers

Imaginary numbers are significant units in complex numbers. Understanding them helps students solve problems involving negative square roots. However, students often find them tricky to deal with. Here are a few common mistakes along with tips to avoid them:

Mistake 1

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Simplifying Higher Powers of ‘i’ Incorrectly
 

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Students often overlook the fact that powers of i follow a pattern of repeating cycles such as i, –1, –i, 1.
When calculating the higher powers, follow the pattern:
i4 = 1, i5 = i, i6 = –1, i7 = –i, i8 = 1, etc.
 

Mistake 2

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Incorrectly Locating Imaginary Numbers on the Argand Plane
 

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Placing imaginary numbers such as (0 + 4i) on the real axis.
The imaginary numbers should be placed on the imaginary axis (vertical axis).
 

Mistake 3

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Errors in Addition and Subtraction
 

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Students might mistakenly add unlike terms, such as real and imaginary parts, together.
Always add or subtract the real and imaginary parts separately. 
For example: (6 + 4i) + (5 – 2i) = (6 + 5) + (4i – 2i) = 11 – 2i.
 

Mistake 4

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Incorrectly Applying the Values of i2
 

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Some students assume the value of i2 as i instead of –1.
Keep in mind that the value of i2 is –1. Sometimes, students also make mistakes in considering the negative sign of 1.
 

Mistake 5

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 Performing Division by ‘i’ Incorrectly
 

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To eliminate the imaginary value of i from the denominator, students make an incorrect calculation. 
 To eliminate i, multiply both the numerator and denominator by i.
 

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Solved Examples of Imaginary Numbers

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Problem 1

Multiply 5i × 6i

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–30
 

Explanation

We first multiply the coefficients: 
5 × 6 = 30
Then, multiply i × i:
Substitute i2 = -1 and combine the terms
30i2 = 30 (–1) = – 30.
 

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Problem 2

Simplify 8/i square

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 – 8
 

Explanation

Substituting i2 = –1 in the denominator:
8/ i2 = 8/ –1 (Since i2 = – 1)
Simplifying the fraction,
8/ –1 = – 8
 

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Problem 3

Determine the value of i to the power 30

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 i30 = –1
 

Explanation

The powers of i repeat in every 4 steps:
i1 = i, i2 = –1, i3 = – i, i4 = 1, and so on.
Here, since the cycle repeats every 4 steps, we divide 30 by 4:
30 ÷ 4 = 7, remainder 2
Now, we use the remainder to determine the value:
We have i2 = –1, so:
i30 = i2 = –1
 

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Problem 4

Simplify √– 64

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8i

Explanation

Since √–1 = i,
We divide √–64 into two parts:
√–64 = √64 × √–1
Since √64 = 8 and √–1 = i,
√–64 = 8i
 

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Problem 5

Calculate (2i)(3 - 4i)

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8 + 6i
 

Explanation

We apply the distributive property,
2i × 3 = 6i 
2i × (-4i) = -8i2
Since i2 = -1, we substitute
-82 = -8(-1) = 8
Now, combining terms, we get,
8 + 6i 
 

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FAQs on Imaginary Numbers

1.What do you mean by an imaginary number?

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2.Is it possible for imaginary numbers to be negative?

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3.What do you mean by complex numbers?

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4.Can we consider zero as an imaginary number?

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5.Can two imaginary numbers be added or subtracted directly?

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6.How can children in Singapore use numbers in everyday life to understand Imaginary Numbers?

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7.What are some fun ways kids in Singapore can practice Imaginary Numbers with numbers?

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8.What role do numbers and Imaginary Numbers play in helping children in Singapore develop problem-solving skills?

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9.How can families in Singapore create number-rich environments to improve Imaginary Numbers skills?

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Hiralee Lalitkumar Makwana

About the Author

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.

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Fun Fact

: She loves to read number jokes and games.

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