Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 2650, how they are used in real life, and tips to learn them quickly.
The numbers that divide 2650 evenly are known as factors of 2650.
A factor of 2650 is a number that divides the number without remainder.
The factors of 2650 are 1, 2, 5, 10, 53, 106, 265, 530, 1325, and 2650.
Negative factors of 2650: -1, -2, -5, -10, -53, -106, -265, -530, -1325, and -2650.
Prime factors of 2650: 2, 5, and 53.
Prime factorization of 2650: 2 × 5² × 53.
The sum of factors of 2650: 1 + 2 + 5 + 10 + 53 + 106 + 265 + 530 + 1325 + 2650 = 4947
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 2650. Identifying the numbers which are multiplied to get the number 2650 is the multiplication method.
Step 1: Multiply 2650 by 1, 2650 × 1 = 2650.
Step 2: Check for other numbers that give 2650 after multiplying
2 × 1325 = 2650
5 × 530 = 2650
10 × 265 = 2650
53 × 50 = 2650
Therefore, the positive factor pairs of 2650 are: (1, 2650), (2, 1325), (5, 530), (10, 265), and (53, 50).
For every positive factor, there is a negative factor.
Dividing the given numbers with whole numbers until the remainder becomes zero and listing out the numbers which result as whole numbers as factors. Factors can be calculated by following the simple division method -
Step 1: Divide 2650 by 1, 2650 ÷ 1 = 2650.
Step 2: Continue dividing 2650 by the numbers until the remainder becomes 0.
2650 ÷ 1 = 2650
2650 ÷ 2 = 1325
2650 ÷ 5 = 530
2650 ÷ 10 = 265
2650 ÷ 53 = 50
Therefore, the factors of 2650 are: 1, 2, 5, 10, 53, 106, 265, 530, 1325, 2650.
The factors can be found by dividing it with prime numbers. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 2650 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
2650 ÷ 2 = 1325
1325 ÷ 5 = 265
265 ÷ 5 = 53
53 ÷ 53 = 1
The prime factors of 2650 are 2, 5, and 53.
The prime factorization of 2650 is: 2 × 5² × 53.
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows -
Step 1: Firstly, 2650 is divided by 2 to get 1325.
Step 2: Now divide 1325 by 5 to get 265.
Step 3: Then divide 265 by 5 to get 53.
Here, 53 is the smallest prime number that cannot be divided anymore.
So, the prime factorization of 2650 is: 2 × 5² × 53.
Factor Pairs Two numbers that are multiplied to give a specific number are called factor pairs.
Both positive and negative factors constitute factor pairs.
Positive factor pairs of 2650: (1, 2650), (2, 1325), (5, 530), (10, 265), and (53, 50).
Negative factor pairs of 2650: (-1, -2650), (-2, -1325), (-5, -530), (-10, -265), and (-53, -50).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
There are 10 friends and 2650 candies. How will they divide it equally?
They will get 265 candies each.
To divide the candies equally, we need to divide the total candies with the number of friends.
2650/10 = 265
A field is rectangular, the length of the field is 53 meters and the total area is 2650 square meters. Find the width?
50 meters.
To find the width of the field, we use the formula,
Area = length × width
2650 = 53 × width
To find the value of width, we need to shift 53 to the left side.
2650/53 = width
Width = 50.
There are 530 bags and 2650 candies. How many candies will be in each bag?
Each bag will have 5 candies.
To find the candies in each bag, divide the total candies with the bags.
2650/530 = 5
In a class, there are 2650 students, and 5 groups. How many students are there in each group?
There are 530 students in each group.
Dividing the students with the total groups, we will get the number of students in each group.
2650/5 = 530
2650 books need to be arranged in 5 shelves. How many books will go on each shelf?
Each of the shelves has 530 books.
Divide total books with shelves.
2650/5 = 530
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.