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Last updated on April 9th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in fields like vehicle design, finance, etc. Here, we will discuss the square root of 7600.
The square root is the inverse of the square of the number. 7600 is not a perfect square. The square root of 7600 is expressed in both radical and exponential form. In radical form, it is expressed as √7600, whereas (7600)^(1/2) in exponential form. √7600 ≈ 87.17798, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long-division method and approximation method are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 7600 is broken down into its prime factors.
Step 1: Finding the prime factors of 7600 Breaking it down, we get 2 × 2 × 2 × 2 × 5 × 5 × 19: 2^4 × 5^2 × 19
Step 2: Now we found out the prime factors of 7600. The second step is to make pairs of those prime factors. Since 7600 is not a perfect square, the digits of the number can’t be grouped in perfect pairs. Therefore, calculating 7600 using prime factorization to find an exact square root is impossible.
The long division method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, we need to group the numbers from right to left. In the case of 7600, we need to group it as 76 and 00
Step 2: Now we need to find n whose square is less than or equal to 76. We can say n is '8' because 8 × 8 = 64, which is less than 76. Now the quotient is 8.
Step 3: Subtract 64 from 76, and the remainder is 12.
Step 4: Bring down the next pair of zeros so the new dividend is 1200. Step 5: Double the quotient (8), which is 16, and use it as part of the new divisor.
Step 6: Find a digit (n) such that 16n × n is less than or equal to 1200. Trying n as 7, we get 167 × 7 = 1169.
Step 7: Subtract 1169 from 1200, and the remainder is 31.
Step 8: Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 3100.
Step 9: Double the quotient (87) and find the new digit n such that 174n × n is less than or equal to 3100. Trying n as 1 gives 1741 × 1 = 1741.
Step 10: Subtract 1741 from 3100, and the remainder is 1359.
Step 11: Continue these steps until we get the desired level of precision. So the square root of √7600 is approximately 87.18.
The approximation method is another method for finding the square roots; it is an easy method to estimate the square root of a given number. Now let us learn how to find the square root of 7600 using the approximation method.
Step 1: Find the closest perfect squares around √7600. The smallest perfect square less than 7600 is 7396 (86²) and the largest perfect square greater than 7600 is 7744 (88²). Therefore, √7600 falls between 86 and 88.
Step 2: Apply the formula: (Given number - smallest perfect square) ÷ (Greater perfect square - smallest perfect square). Using the formula: (7600 - 7396) ÷ (7744 - 7396) = 204 ÷ 348 = 0.586. Therefore, the square root of 7600 is approximately 86 + 0.586 = 86.586.
Can you help Alex find the area of a square if its side length is given as √7600?
A square-shaped garden measuring 7600 square feet is created; if each of the sides is √7600, what will be the square feet of half of the garden?
Calculate √7600 × 5.
What will be the square root of (3600 + 4000)?
Find the perimeter of a rectangle if its length 'l' is √7600 units and its width 'w' is 100 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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