Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 3136.
The square root is the inverse of the square of the number. 3136 is a perfect square. The square root of 3136 is expressed in both radical and exponential form. In the radical form, it is expressed as √3136, whereas (3136)^(1/2) in the exponential form. √3136 = 56, which is a rational number because it can be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method can be used for perfect square numbers. For non-perfect square numbers, methods like long-division and approximation are used. Let us now learn the following methods for finding the square root of 3136:
The product of prime factors is the prime factorization of a number. Now let us look at how 3136 is broken down into its prime factors.
Step 1: Finding the prime factors of 3136 Breaking it down, we get 2 x 2 x 2 x 2 x 7 x 7: 2^4 x 7^2
Step 2: Now we found the prime factors of 3136. The second step is to make pairs of those prime factors. Since 3136 is a perfect square, the digits of the number can be grouped in pairs. Therefore, calculating 3136 using prime factorization is possible.
Step 3: Taking one number from each pair gives us 2^2 x 7 = 4 x 7 = 28 Thus, the square root of 3136 is 56.
The long division method is used to find the square root of perfect square numbers too. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, we need to group the numbers from right to left. In the case of 3136, we need to group it as 36 and 31.
Step 2: Now we need to find n whose square is less than or equal to 31. We can say n as '5' because 5^2 = 25 is less than 31. Now the quotient is 5; after subtracting 25 from 31, the remainder is 6.
Step 3: Now let us bring down 36, which is the new dividend. Add the old divisor with the same number: 5 + 5 = 10, which will be our new divisor.
Step 4: The new divisor will be 10n. We need to find the value of n such that 10n x n ≤ 636. Let's consider n as 6; now 106 x 6 = 636.
Step 5: Subtract 636 from 636; the difference is 0, and the quotient is 56. So the square root of √3136 is 56.
The approximation method is not necessary for perfect squares but can be applied to understand the proximity of results. For 3136, direct methods are more efficient.
Students do make mistakes while finding the square root, like forgetting about the negative square root or skipping long division methods. Now let us look at a few of those mistakes that students tend to make in detail.
Can you help Max find the area of a square box if its side length is given as √3136?
The area of the square is 3136 square units.
The area of the square = side^2.
The side length is given as √3136.
Area of the square = side^2 = √3136 x √3136 = 56 x 56 = 3136.
Therefore, the area of the square box is 3136 square units.
A square-shaped building measuring 3136 square feet is built; if each of the sides is √3136, what will be the square feet of half of the building?
1568 square feet
We can just divide the given area by 2 as the building is square-shaped.
Dividing 3136 by 2, we get 1568.
So half of the building measures 1568 square feet.
Calculate √3136 x 5.
280
The first step is to find the square root of 3136, which is 56.
The second step is to multiply 56 by 5.
So 56 x 5 = 280.
What will be the square root of (3130 + 6)?
The square root is 56.
To find the square root, we need to find the sum of (3130 + 6).
3130 + 6 = 3136, and then √3136 = 56.
Therefore, the square root of (3130 + 6) is ±56.
Find the perimeter of a rectangle if its length ‘l’ is √3136 units and the width ‘w’ is 38 units.
The perimeter of the rectangle is 188 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√3136 + 38) = 2 × (56 + 38) = 2 × 94 = 188 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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