Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 15/4.
The square root is the inverse of the square of the number. The fraction 15/4 is not a perfect square. The square root of 15/4 is expressed in both radical and exponential form. In the radical form, it is expressed as √(15/4), whereas (15/4)^(1/2) in the exponential form. √(15/4) = √15/2, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long-division method and approximation method are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 15/4 is broken down into its prime factors.
Step 1: Finding the prime factors of 15 and 4. Breaking them down, we get 15 = 3 × 5 and 4 = 2 × 2.
Step 2: Now we found out the prime factors of 15 and 4. Since 15/4 is not a perfect square, we cannot pair the factors completely.
Therefore, calculating √(15/4) using prime factorization involves simplifying it to √15/2.
The long division method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square numbers for the given number. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, we'll find the square root of the numerator 15 and the denominator 4 separately.
Step 2: The closest perfect square number to 15 is 16. The square root of 16 is 4, so √15 is slightly less than 4.
Step 3: For 4, the square root is 2.
Step 4: Therefore, √(15/4) = √15/2. Using the long division method or a calculator, √15 ≈ 3.87298.
The approximation method is another method for finding square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 15/4 using the approximation method.
Step 1: Now we have to find the closest perfect squares for the numerator 15, which are 9 and 16. √15 falls between 3 and 4.
Step 2: To approximate √15, we consider it as approximately 3.87298.
Step 3: Therefore, √(15/4) is approximately 3.87298/2 = 1.93649.
Students do make mistakes while finding the square root, like forgetting about the negative square root or skipping long division methods. Now let us look at a few of those mistakes that students tend to make in detail.
Can you help Max find the area of a square box if its side length is given as √(15/4)?
The area of the square is 15/4 square units.
The area of the square = side².
The side length is given as √(15/4).
Area of the square = (√(15/4))²
= 15/4.
Therefore, the area of the square box is 15/4 square units.
A square-shaped building measuring 15/4 square units is built; if each of the sides is √(15/4), what will be the square units of half of the building?
15/8 square units
We can just divide the given area by 2 as the building is square-shaped.
Dividing 15/4 by 2 = 15/8.
So half of the building measures 15/8 square units.
Calculate √(15/4) × 5.
9.68245
The first step is to find the approximate square root of 15/4, which is 1.93649.
The second step is to multiply 1.93649 with 5.
So 1.93649 × 5 ≈ 9.68245.
What will be the square root of (15/4 + 1)?
The square root is approximately 2.12132.
To find the square root, we need to find the sum of (15/4 + 1).
15/4 + 1 = 19/4, and then √(19/4) = √19/2 ≈ 2.12132.
Therefore, the square root of (15/4 + 1) is approximately ±2.12132.
Find the perimeter of the rectangle if its length ‘l’ is √(15/4) units and the width ‘w’ is 2 units.
The perimeter of the rectangle is approximately 7.87298 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√(15/4) + 2)
= 2 × (1.93649 + 2)
= 2 × 3.93649
= 7.87298 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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