Last updated on August 11th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 18 and 30.
The greatest common factor of 18 and 30 is 6. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 18 and 30, a few methods are described below - Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 18 and 30 using the listing of factors:
Step 1: Firstly, list the factors of each number.
Factors of 18 = 1, 2, 3, 6, 9, 18.
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Step 2: Now, identify the common factors of them. Common factors of 18 and 30: 1, 2, 3, 6.
Step 3: Choose the largest factor. The largest factor that both numbers have is 6.
The GCF of 18 and 30 is 6.
To find the GCF of 18 and 30 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number.
Prime Factors of 18: 18 = 2 × 3 × 3 = 2 × 3²
Prime Factors of 30: 30 = 2 × 3 × 5
Step 2: Now, identify the common prime factors. The common prime factors are: 2 × 3
Step 3: Multiply the common prime factors. 2 × 3 = 6. The Greatest Common Factor of 18 and 30 is 6.
Find the GCF of 18 and 30 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number. Here, divide 30 by 18. 30 ÷ 18 = 1 (quotient), The remainder is calculated as 30 − (18×1) = 12. The remainder is 12, not zero, so continue the process.
Step 2: Now divide the previous divisor (18) by the previous remainder (12). Divide 18 by 12. 18 ÷ 12 = 1 (quotient), remainder = 18 − (12×1) = 6. The remainder is not zero, so continue the process.
Step 3: Divide the previous divisor (12) by the previous remainder (6). 12 ÷ 6 = 2 (quotient), remainder = 12 − (6×2) = 0.
The remainder is zero, the divisor will become the GCF. The GCF of 18 and 30 is 6.
Finding the GCF of 18 and 30 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 18 markers and 30 notebooks. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 18 and 30. GCF of 18 and 30 is 6. There are 6 equal groups. 18 ÷ 6 = 3 30 ÷ 6 = 5 There will be 6 groups, and each group gets 3 markers and 5 notebooks.
As the GCF of 18 and 30 is 6, the teacher can make 6 groups. Now divide 18 and 30 by 6. Each group gets 3 markers and 5 notebooks.
A school has 18 red flags and 30 blue flags. They want to arrange them in rows with the same number of flags in each row, using the largest possible number of flags per row. How many flags will be in each row?
GCF of 18 and 30 is 6. So each row will have 6 flags.
There are 18 red and 30 blue flags. To find the total number of flags in each row, we should find the GCF of 18 and 30. There will be 6 flags in each row.
A tailor has 18 meters of green fabric and 30 meters of yellow fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 18 and 30. The GCF of 18 and 30 is 6. The fabric pieces should be 6 meters long.
For calculating the longest length of the fabric pieces first we need to calculate the GCF of 18 and 30 which is 6. The length of each piece of the fabric will be 6 meters.
A carpenter has two wooden planks, one 18 cm long and the other 30 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 18 and 30 is 6. The longest length of each piece is 6 cm.
To find the longest length of each piece of the two wooden planks, 18 cm and 30 cm, respectively. We have to find the GCF of 18 and 30, which is 6 cm. The longest length of each piece is 6 cm.
If the GCF of 18 and ‘b’ is 6, and the LCM is 90. Find ‘b’.
The value of ‘b’ is 30.
GCF × LCM = product of the numbers
6 × 90 = 18 × b
540 = 18b
b = 540 ÷ 18 = 30
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.