Last updated on August 14th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 105 and 90.
The greatest common factor of 105 and 90 is 15. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 105 and 90, a few methods are described below -
Steps to find the GCF of 105 and 90 using the listing of factors:
Step 1: Firstly, list the factors of each number.
Factors of 105 = 1, 3, 5, 7, 15, 21, 35, 105.
Factors of 90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
Step 2: Now, identify the common factors of them. Common factors of 105 and 90: 1, 3, 5, 15.
Step 3: Choose the largest factor. The largest factor that both numbers have is 15. The GCF of 105 and 90 is 15.
To find the GCF of 105 and 90 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number. Prime Factors of 105: 105 = 3 x 5 x 7 Prime Factors of 90: 90 = 2 x 3 x 3 x 5
Step 2: Now, identify the common prime factors. The common prime factors are: 3 x 5
Step 3: Multiply the common prime factors. 3 x 5 = 15. The Greatest Common Factor of 105 and 90 is 15.
Find the GCF of 105 and 90 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number. Here, divide 105 by 90. 105 ÷ 90 = 1 (quotient), The remainder is calculated as 105 − (90×1) = 15. The remainder is 15, not zero, so continue the process.
Step 2: Now divide the previous divisor (90) by the previous remainder (15). Divide 90 by 15. 90 ÷ 15 = 6 (quotient), remainder = 90 − (15×6) = 0.
The remainder is zero, the divisor will become the GCF. The GCF of 105 and 90 is 15.
Finding the GCF of 105 and 90 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by students.
A teacher has 105 markers and 90 highlighters. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 105 and 90. GCF of 105 and 90: 3 x 5 = 15.
There are 15 equal groups. 105 ÷ 15 = 7 90 ÷ 15 = 6
There will be 15 groups, and each group gets 7 markers and 6 highlighters.
As the GCF of 105 and 90 is 15, the teacher can make 15 groups. Now divide 105 and 90 by 15. Each group gets 7 markers and 6 highlighters.
A school has 105 red chairs and 90 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 105 and 90: 3 x 5 = 15. So each row will have 15 chairs.
There are 105 red and 90 blue chairs. To find the total number of chairs in each row, we should find the GCF of 105 and 90. There will be 15 chairs in each row.
A tailor has 105 meters of red ribbon and 90 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 105 and 90. The GCF of 105 and 90: 3 x 5 = 15. The ribbon is 15 meters long.
For calculating the longest length of the ribbon, first we need to calculate the GCF of 105 and 90, which is 15. The length of each piece of the ribbon will be 15 meters.
A carpenter has two wooden planks, one 105 cm long and the other 90 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 105 and 90: 3 x 5 = 15. The longest length of each piece is 15 cm.
To find the longest length of each piece of the two wooden planks, 105 cm and 90 cm, respectively, we have to find the GCF of 105 and 90, which is 15 cm. The longest length of each piece is 15 cm.
If the GCF of 105 and ‘a’ is 15, and the LCM is 630, find ‘a’.
The value of ‘a’ is 90.
GCF x LCM = product of the numbers
15 × 630 = 105 × a
9450 = 105a
a = 9450 ÷ 105 = 90
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.