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Last updated on July 24th, 2025

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Derivative of cos2x

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We use the derivative of cos(2x), which is -2sin(2x), to understand how the function changes in response to a small change in x. Derivatives are crucial in calculating various real-life scenarios like rates of change. We will now discuss the derivative of cos(2x) in detail.

Derivative of cos2x for Saudi Students
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What is the Derivative of cos2x?

We now understand the derivative of cos(2x). It is commonly represented as d/dx (cos(2x)) or (cos(2x))', and its value is -2sin(2x). The function cos(2x) has a well-defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below: Cosine Function: (cos(x) is a trigonometric function). Chain Rule: Rule for differentiating cos(2x) as it consists of a composition of functions. Sine Function: sin(x) is the derivative of cos(x) with a negative sign.

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Derivative of cos2x Formula

The derivative of cos(2x) can be denoted as d/dx (cos(2x)) or (cos(2x))'. The formula we use to differentiate cos(2x) is: d/dx (cos(2x)) = -2sin(2x) (or) (cos(2x))' = -2sin(2x) The formula applies to all x.

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Proofs of the Derivative of cos2x

We can derive the derivative of cos(2x) using proofs. To show this, we will use trigonometric identities along with the rules of differentiation. There are several methods we use to prove this, such as: By First Principle Using Chain Rule Using Product Rule We will now demonstrate that the differentiation of cos(2x) results in -2sin(2x) using the above-mentioned methods: By First Principle The derivative of cos(2x) can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of cos(2x) using the first principle, we will consider f(x) = cos(2x). Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = cos(2x), we write f(x + h) = cos(2(x + h)). Substituting these into equation (1), f'(x) = limₕ→₀ [cos(2(x + h)) - cos(2x)] / h = limₕ→₀ [cos(2x + 2h) - cos(2x)] / h Using the formula cos A - cos B = -2 sin((A + B)/2) sin((A - B)/2), f'(x) = limₕ→₀ [-2 sin((2x + 2h + 2x)/2) sin((2x + 2h - 2x)/2)] / h = limₕ→₀ [-2 sin(2x + h) sin(h)] / h = limₕ→₀ [-2 sin(2x + h) sin(h)/h] Using limit formulas, limₕ→₀ (sin(h)/h) = 1, f'(x) = -2 sin(2x + 0) = -2 sin(2x) Hence, proved. Using Chain Rule To prove the differentiation of cos(2x) using the chain rule, We use the formula: cos(2x) = cos(u), where u = 2x By chain rule: d/dx [cos(u)] = -sin(u) du/dx Let’s substitute u = 2x, d/dx (cos(2x)) = -sin(2x).d/dx (2x) = -sin(2x).2 Therefore, d/dx (cos(2x)) = -2sin(2x) Using Product Rule We will now prove the derivative of cos(2x) using the product rule. The step-by-step process is demonstrated below: Here, we use the formula, cos(2x) = cos(x + x) = cos(x)cos(x) - sin(x)sin(x) Given that, u = cos(x) and v = cos(x) Using the product rule formula: d/dx [u.v] = u'.v + u.v' u' = d/dx (cos(x)) = -sin(x) (substitute u = cos(x)) v' = d/dx (cos(x)) = -sin(x) (substitute v = cos(x)) Again, use the product rule formula: d/dx (cos(2x)) = u'.v + u.v' Let’s substitute u = cos(x), u' = -sin(x), v = cos(x), and v' = -sin(x) When we simplify each term: We get, d/dx (cos(2x)) = -2 sin(x)cos(x) Using the identity sin(2x) = 2sin(x)cos(x), Thus: d/dx (cos(2x)) = -sin(2x) Therefore, d/dx (cos(2x)) = -2sin(x).2cos(x) = -2sin(2x).

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Higher-Order Derivatives of cos2x

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like cos(2x). For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues. For the nth Derivative of cos(2x), we generally use f(n)(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).

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Special Cases:

When x is π/2, the derivative is -2sin(π) = 0 since sin(π) is 0. When x is 0, the derivative of cos(2x) = -2sin(0), which is 0.

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Common Mistakes and How to Avoid Them in Derivatives of cos2x

Students frequently make mistakes when differentiating cos(2x). These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not applying the chain rule properly

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Students may forget to apply the chain rule correctly, which can lead to incorrect results. They often skip steps and directly arrive at the result, especially when solving trigonometric functions. Ensure that each inner function is differentiated properly. Students might think it is straightforward, but it is important to avoid errors in the process.

Mistake 2

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Forgetting the Trigonometric Identity

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Students might not remember trigonometric identities, which are crucial for simplifying derivatives. Keep in mind that using identities like sin(2x) = 2sin(x)cos(x) is essential for accurate results.

Mistake 3

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Incorrect use of Product Rule

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While differentiating functions like cos(2x), students misapply the product rule by not identifying the right functions to derive. For example: Incorrect differentiation: d/dx (cos(x)cos(x)) = -2sin(x)cos(x). To avoid this mistake, write the product rule without errors. Always check for errors in the calculation and ensure it is properly simplified.

Mistake 4

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Ignoring the Sign Change

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There is a common mistake where students forget that the derivative of the cosine function is negative. For example, they incorrectly write d/dx (cos(2x)) = 2sin(2x). Students should remember to include the negative sign, as the correct derivative is -2sin(2x).

Mistake 5

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Not Applying the First Principle

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Students often overlook the first principle of differentiation, which is the basis of derivatives. This happens when they do not express the difference quotient properly. For example: Incorrect: d/dx (cos(2x)) = -2sin(2x). To fix this error, students should revisit the limit definition and ensure the steps are correctly derived.

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Examples Using the Derivative of cos2x

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Problem 1

Calculate the derivative of (cos(2x) · e^x)

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Here, we have f(x) = cos(2x) · e^x. Using the product rule, f'(x) = u′v + uv′ In the given equation, u = cos(2x) and v = e^x. Let’s differentiate each term, u′ = d/dx (cos(2x)) = -2sin(2x) v′ = d/dx (e^x) = e^x Substituting into the given equation, f'(x) = (-2sin(2x)) · e^x + cos(2x) · e^x Let’s simplify terms to get the final answer, f'(x) = e^x(-2sin(2x) + cos(2x)) Thus, the derivative of the specified function is e^x(-2sin(2x) + cos(2x)).

Explanation

We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.

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Problem 2

The elevation of a hill is represented by the function y = cos(2x), where y represents the height at a distance x. If x = π/6 meters, measure the rate of change of the elevation.

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We have y = cos(2x) (height of the hill)...(1) Now, we will differentiate the equation (1) Take the derivative cos(2x): dy/dx = -2sin(2x) Given x = π/6 (substitute this into the derivative) dy/dx = -2sin(π/3) dy/dx = -2(√3/2) = -√3 Hence, we get the rate of change of the elevation at a distance x = π/6 as -√3.

Explanation

We find the rate of change of elevation at x = π/6 as -√3, which means that at this point, the height of the hill is decreasing at a rate of √3 times the horizontal distance.

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Problem 3

Derive the second derivative of the function y = cos(2x).

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The first step is to find the first derivative, dy/dx = -2sin(2x)...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-2sin(2x)] Here we use the chain rule, d²y/dx² = -2 · 2cos(2x) d²y/dx² = -4cos(2x) Therefore, the second derivative of the function y = cos(2x) is -4cos(2x).

Explanation

We use the step-by-step process, where we start with the first derivative. Using the chain rule, we differentiate -2sin(2x). We then simplify the terms to find the final answer.

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Problem 4

Prove: d/dx (sin²(2x)) = 4sin(2x)cos(2x).

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Let’s start using the chain rule: Consider y = sin²(2x) = [sin(2x)]² To differentiate, we use the chain rule: dy/dx = 2sin(2x) · d/dx [sin(2x)] Since the derivative of sin(2x) is 2cos(2x), dy/dx = 2sin(2x) · 2cos(2x) dy/dx = 4sin(2x)cos(2x) Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replaced sin(2x) with its derivative. As a final step, we simplified to derive the equation.

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Problem 5

Solve: d/dx (cos(2x)/x)

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To differentiate the function, we use the quotient rule: d/dx (cos(2x)/x) = (d/dx (cos(2x))·x - cos(2x)·d/dx(x))/x² We will substitute d/dx (cos(2x)) = -2sin(2x) and d/dx (x) = 1 = (-2sin(2x)·x - cos(2x)·1) / x² = (-2xsin(2x) - cos(2x)) / x² Therefore, d/dx (cos(2x)/x) = (-2xsin(2x) - cos(2x)) / x²

Explanation

In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of cos2x

1.Find the derivative of cos2x.

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2.Can we use the derivative of cos2x in real life?

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3.Is it possible to take the derivative of cos2x at the point where x = π/2?

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4.What rule is used to differentiate cos2x/x?

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5.Are the derivatives of cos(2x) and cos⁻¹(x) the same?

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6.Can we find the derivative of the cos2x formula?

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Important Glossaries for the Derivative of cos2x

Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x. Cosine Function: The cosine function is one of the primary six trigonometric functions and is written as cos(x). Sine Function: A trigonometric function that represents the y-coordinate of a point on the unit circle, written as sin(x). Chain Rule: A fundamental rule in calculus used to differentiate composite functions. Trigonometric Identity: Equations involving trigonometric functions that are true for every value of the occurring variables.

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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