Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse operation is finding the square root. The square root is used in various fields like vehicle design, finance, etc. Here, we will discuss the square root of 27/4.
The square root is the inverse of the square of the number. 27/4 is not a perfect square. The square root of 27/4 is expressed in both radical and exponential form. In the radical form, it is expressed as √(27/4), whereas in the exponential form it is expressed as (27/4)^(1/2). √(27/4) = √27/2 = 2.59808, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, for non-perfect square numbers like 27/4, the long-division and approximation methods are used. Let us now learn the following methods:
The long division method is particularly used for non-perfect square numbers. Let us now learn how to find the square root of 27/4 using the long division method, step by step.
Step 1: First, express the number as a decimal. 27/4 = 6.75.
Step 2: Group the digits from right to left as 6.75.
Step 3: Find n whose square is closest to 6. The closest is 2, because 2² = 4.
Step 4: Subtract 4 from 6, bringing down 75 to get 275.
Step 5: Double the quotient obtained, which is 2, to get 4 and find a digit x such that 4x × x ≤ 275. The suitable x is 5, as 45 × 5 = 225.
Step 6: Subtract 225 from 275 to get 50.
Step 7: Add a decimal point and bring down 00 to make it 5000.
Step 8: Double the quotient 25 to get 50, then find x such that 50x × x ≤ 5000. The suitable x is 9, as 509 × 9 = 4581.
Step 9: Subtract 4581 from 5000 to get 419.
Step 10: Continue this process to get more decimal places.
The square root of 6.75 is approximately 2.59808.
The approximation method is another method for finding square roots. Let us learn how to find the square root of 27/4 using the approximation method.
Step 1: Find the closest perfect squares around 27/4. The smallest perfect square is 4 and the largest perfect square is 9. √(27/4) lies between √4 = 2 and √9 = 3.
Step 2: Apply the formula (Given number - smallest perfect square)/(Greater perfect square - smallest perfect square). Using the formula, (6.75 - 4)/(9 - 4) = 0.55.
Step 3: Add this decimal to the smaller root: 2 + 0.55 = 2.55. Adjust further by checking higher precision to approximate further.
Thus, the square root of 6.75 is approximately 2.59808.
Students often make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in long division methods. Let us look at a few common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √(27/4)?
The area of the square is approximately 6.75 square units.
The area of the square = side².
The side length is given as √(27/4) = 2.59808.
Area of the square = (2.59808)²
≈ 6.75.
Therefore, the area of the square box is approximately 6.75 square units.
A square-shaped building measuring 27/4 square feet is built; if each of the sides is √(27/4), what will be the square feet of half of the building?
3.375 square feet
Divide the given area by 2 as the building is square-shaped.
Dividing 27/4 by 2 gives 3.375.
So half of the building measures 3.375 square feet.
Calculate √(27/4) × 5.
12.9904
First, find the square root of 27/4, which is approximately 2.59808. Then multiply 2.59808 by 5. So, 2.59808 × 5 ≈ 12.9904.
What will be the square root of (27/4 + 5)?
The square root is approximately 3.5.
Find the sum of (27/4 + 5) = 6.75 + 5 = 11.75.
Then find the square root of 11.75, which is approximately 3.5.
Therefore, the square root of (27/4 + 5) is approximately ±3.5.
Find the perimeter of the rectangle if its length 'l' is √(27/4) units and the width 'w' is 5 units.
The perimeter of the rectangle is approximately 15.19616 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√(27/4) + 5)
≈ 2 × (2.59808 + 5)
≈ 2 × 7.59808
≈ 15.19616 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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