BrightChamps Logo
Login
Creative Math Ideas Image
Live Math Learners Count Icon103 Learners

Last updated on July 11th, 2025

Math Whiteboard Illustration

Quadratic Equations

Professor Greenline Explaining Math Concepts

A quadratic equation is a second-degree polynomial written in the form of ax2 + bx + c = 0, where a ≠ 0. It is used to solve problems involving area, velocity, and path. For e.g., the area of different shapes, the velocity of a moving object, and the trajectories of objects following parabolic paths like a projectile. The solutions to a quadratic equation are the points where its parabola-shaped graph crosses the x-axis. These solutions are called roots or zeros.

Quadratic Equations for Saudi Students
Professor Greenline from BrightChamps

What is Quadratic Equation

A quadratic equation is a second-degree polynomial equation written as:
ax2 + bx + c = 0

 

 

Where:
a, b are coefficients (with a ≠ 0),
x is the variable
c is the constant
And the highest power of x is 2.

 

 

The word ‘quadratic’ is derived from the Latin word ‘quadratus’, which means square. The equation is quadratic because ‘quad’ means the square (power 2). The solutions to a quadratic equation, known as its roots, can be real or complex numbers. The graph of a quadratic equation is known as a parabola.
 

Professor Greenline from BrightChamps

What are the Roots of a Quadratic Equation?

The roots of a quadratic equation of the form ax2 + bx + c = 0 are values of x that equate the equation to zero. Hence, they are also called zeros, and they satisfy the equation. Solving a quadratic equation yields two values of x, which can be real or complex. For e.g., the equation x2 - 3x - 4 = 0 has two roots; x = -1 and x = 4. 

 

 

We can verify this by substituting the values of x in the equation:

 

 

When x = -1, we get: (-1)2 - 3(-1) - 4 = 0
Simplifying it: 1 + 3 - 4 = 0 
4 - 4 = 0

When x = 4, we get: (4)2 - 3(4) - 4 = 0 
Simplifying it: 16 - 12 - 4 = 0 
4 - 4 = 0

 

 

There are various methods to find the roots of a quadratic equation. One of them is by using the quadratic formula.

Professor Greenline from BrightChamps

What is the Quadratic Formula?

There are a few quadratic equations that cannot be factorized with ease, and here use this formula to find the roots. The two roots in the quadratic formula are written in the form of a single expression. Solving a quadratic expression will usually yield two roots; one with a positive value and one with a negative value.

The quadratic formula for the equation ax2 + bx + c = 0 is: 
x = -bb2-4ac2a.

 

 

Example: Let’s find the roots of the quadratic equation y² + 2y - 15 = 0 using the quadratic formula.

Here,
a = 1,
b = 2,
c = −15
Using the formula:  y = -b b2-4ac2a

Substituting the values: y = -2  (2)2- 4(1) (-15)2(1)
                              
                                         = -2   4 + 602

                                         = -2   642
                                         

                                         = -2  82

So,                 
                 y = -2 + 82 = 62 = 3
        
       and,   y = -2 -82 = - 102 = -5

Therefore, the roots of the equation are 3 and -5.
 

Professor Greenline from BrightChamps

Proof of Quadratic Formula

The quadratic formula, used in solving equations of the form ax2 + bx + c = 0, is obtained by following the process of completing the square. In this manner, we convert the given equation into the perfect square form, and thus we can isolate the variable and get a general solution that is applicable for any given coefficient.

 

 

Example: Examine the following arbitrary quadratic equation: ax2 + bx + c = 0, a ≠ 0.

We take the following steps to find the equation's roots:

Step 1: ax2 + bx = -c ⇒ x2 + bxa = -ca

By adding a new term (b/2a)2 to both sides, we can now represent the left-hand side as a perfect square:

x2 + bxa + (b2a)2 = -ca + (b2a)2.

Now, the left side is a perfect square:

(x + b2a)2 = - ca + b24a2 ⇒ (x + b2a)2 = (b2 - 4ac 4a2)

Simplifying the equation further, we get:

x + b2a = ± b2 - 4ac 2a

x = (-b ± √(b2 - 4ac)2a

We were therefore able to isolate x and derive the equation's two roots by completing the squares.
 

Professor Greenline from BrightChamps

What is the Nature of Roots of the Quadratic Equation?

Greek letters alpha (α) and beta (β) are commonly used to represent the roots of a quadratic equation. Here, we'll learn more about determining the type of roots in a quadratic equation.

 

 

It is possible to determine the nature of a quadratic equation's roots without actually determining the equation's roots (α, β). This can be accomplished by calculating the discriminant value, which is a component of the quadratic equation solution formula. The discriminant of a quadratic equation, denoted by the letter ‘D,’ is the value b2 - 4ac. It is possible to predict the characteristics of the quadratic equation's roots based on the discriminant value.
Discriminant: D = b2 - 4ac.
If D > 0, then the roots are real and distinct.
If D = 0, then the roots are real and equal.
When D < 0, the roots are complex.

Now observe the formulas for finding the sum and the product of the roots of the given equation.

 

 

Sum and Product of Roots of Quadratic Equation 

 

The sum and product of roots of a quadratic equation can be found using the coefficient of x2, the coefficient of x, and the constant term of the equation ax2 + bx + c = 0. Compute the sum and product of the roots of the equation from the equation. The sum and product of the roots of the quadratic equation ax2 + bx + c = 0 are as follows.

The sum of the roots is α + β = -b / a = - Coefficient of x / Coefficient of x2
The product of the roots is αβ = c / a = Constant term / Coefficient of x2.

 

 

What are the Formulas Related to Quadratic Equations 


Formulas help solve quadratic equations faster. There are many formulas related to quadratic equations, and some of the most important ones are mentioned below:

 

  • The standard form of a quadratic equation is ax2 + bx + c = 0
  • The discriminant of the quadratic equation is D = b2 - 4ac
  • For D > 0, the roots are real and distinct.
  • For D = 0, the roots are real and equal.
  • For D < 0, the roots are complex.
  • The roots of the standard quadratic equation can be found by using the formula:
  •         x = (-b ± √(b2 - 4ac)2a.
  • The sum of the roots of any quadratic equation is α + β = -b / a.
  • The product of the roots of any quadratic equation is αβ = c / a.
  • The quadratic equation whose roots are α and β is x2 - (α + β)x + αβ = 0.
  • The condition for the quadratic equations a1 x2 + b1 x + c1 = 0 and a2 x2 + b2 x + c2 = 0 to have the same roots is: a1a2 = b1b2 = c1c2. 
  • When a > 0, the quadratic expression f(x) = ax2 + bx + c has a minimum value at x = -b/2a.
  • When a < 0, the quadratic expression f(x) = ax2 + bx + c has a maximum value at x = -b/2a.
  • The domain of any quadratic function is the set of all real numbers.
     
Professor Greenline from BrightChamps

Methods to Solve Quadratic Equations

You can find the two roots of the quadratic equations using the four methods listed below:

 

 

  • Quadratic equation factorization

 

  • Applying the quadratic formula, which we have already seen in the above topics.

 

  • Completing the square

 

  • Graphing the equation

 

To learn more about the aforementioned techniques, their applications, and their uses, let's take a closer look at them.

 


How to Solve Quadratic Equations by Factorization

 

There are several steps involved in factorizing a quadratic equation. We must first split the middle part of the equation into two groups. The split must happen in such a way that their product should be the same as the product of coefficient a and constant c in the equation ax2 + bx + c = 0. Additionally, we can extract the common terms from the available terms to ultimately derive the necessary factors in the manner described below:

 

 

  • x2 + (a + b) x + ab = 0 
  • (x2 + ax) + (bx + ab) = 0 
  • x (x + a) + b (x + a) = 0
  • (x + a)(x + b) = 0

 

To better understand the factorization process, consider this example.

 

  • x2 + 5x + 6 = 0 
  • x2 + 2x + 3x + 6 = 0 
  • x(x + 2) + 3(x + 2) = 0
  • (x + 2) (x + 3) = 0

 

As a result, the quadratic equation's two obtained factors are (x + 2) and (x + 3). Simply set each factor to zero and solve for x to determine its roots. That is, x = -2 and x = -3 because x + 2 = 0 and x + 3 = 0. Therefore, the roots of x2 + 5x + 6 = 0 are x = -2 and x = -3.

 

Additionally, there is another crucial approach to solving a quadratic equation. Finding the roots of a quadratic equation can also be accomplished by using the method of completing the square.

Professor Greenline from BrightChamps

What are the Methods of Completing the Square

Completing the square in a quadratic equation involves simplifying and algebraically squaring the equation to find the necessary roots. Examine the quadratic equation ax2 + bx + c = 0, where a ≠ 0. We simplify this equation as follows to find its roots:

ax2 + bx + c = 0.
ax2 + bx = -c

x2 + bx / a = -c / a
By adding a new term (b / 2a)2 to both sides, we can now represent the left-hand side as a perfect square:
x2 + bx / a + (b / 2a)2 = -c/a + (b/2a)2 
(x + b / 2a)2 = -c/a + b2/4a2 
(x + b / 2a)2 = (b2 - 4ac)/4a2

x + b / 2a = +√(b2- 4ac) / 2a 
x = -b / 2a +√(b2 - 4ac) / 2a 
x = [-b ± √(b2 - 4ac)] / 2a
In this case, the quadratic equation's "+" and "-" signs indicate different roots. In most cases, this intricate process is omitted, and the necessary roots are obtained solely by applying the quadratic formula.

 

 


How to Graph a Quadratic Equation

 

By expressing the quadratic equation as a function y = ax2 + bx + c, the graph of the quadratic equation ax2 + bx + c = 0 can be found. Additionally, we can obtain values of y by substituting different values of x, which gives us the required points to plot the graph. To create a parabola, these points can be displayed on the coordinate plane.


The quadratic equation's solutions are the x-values where its graph crosses the x-axis. By setting y = 0 in the function y = ax2 + bx + c and solving for x, these points can be obtained algebraically.
 

Professor Greenline from BrightChamps

Common Roots of Quadratic Equations

Let a1x2 + b1x + c1 = 0 and a2x2 + b2 x + c2 = 0 be two quadratic equations with common roots. To determine the conditions under which these two equations share a root, let's solve them. The two equations are solved for x2 and x.

(x2) (b1 c2 - b2 c1) = (-x) / (a1 c2 - a2 c1) = 1 / (a1 b2 - a2 b1)
x2 = (b1c2 - b2c1) / (a1b2 - a2b1) 
x = (a2c1 - a1c2) / (a1b2 - a2b1)

Therefore, the following condition for the two equations having a common root is obtained by simplifying the two expressions above.
(a1b2 – a2b1) (b1c2 - b2c1) = (a2c1 - a1c2)2

 

 

Maximum and Minimum Value of Quadratic Expression


Graphs can be used to represent the maximum and minimum values of a quadratic function in the form f(x) = ax2 + bx + c. If the value of a is positive (a > 0), then the parabola opens upwards and the maximum value of x is at x = -b/2a. It has a maximum value at x = -b/2a for negative values of a (a < 0). And the parabola opens downwards.

The maximum and minimum values are used to determine the range of the unctions:

The range is [f(-b/2a), ∞] for positive values of a (a > 0) 
The range is [(-∞, f(-b/2a))] for negative values of a (a < 0).

Range for a > 0: [ f((- b2a), ∞)]
Range: [(-∞, f (- b2a))] for a < 0.

Keep in mind that the domain of any quadratic function is all real numbers, or (-∞, ∞).
 

Professor Greenline from BrightChamps

Real-Life Applications of Quadratic Equations

This section examines the practical applications of quadratic equations in a variety of domains. Quadratics are used to solve many problems in daily life. For e.g., in a sport like cricket, the concept is used to determine a ball's trajectory. Let us take a look at some other applications of quadratic equations:

 

 

  • The quadratic equations are used to model the path of objects in projectile motion. For example, to calculate how high a basketball will go.

 

  • In computer graphics and animation quadratic equation is used to model the motion of objects and to create realistic movements in games and cartoons 

 

  • Quadratic equations are used in finance to predict the amount based on variables like interest rates, time, and investment amount. 
     
Max Pointing Out Common Math Mistakes

Common Mistakes and How to Avoid Them in Quadratic Equations

This section highlights common mistakes that students frequently make when working with quadratic equations, such as incorrect signs, poor factoring, or improper formula usage. It offers helpful guidance on how to steer clear of these pitfalls and approach problems with greater assurance. Some of the common mistakes are as follows:

Mistake 1

Red Cross Icon Indicating Mistakes to Avoid in This Math Topic

Misidentifying the Coefficients
 

Green Checkmark Icon Indicating Correct Solutions in This Math Topic

Students often misidentify the coefficients in a quadratic equation, mostly when the equations are not in standard form. To avoid this, students should always rewrite the equation in standard form before identifying the coefficients. 
 

Mistake 2

Red Cross Icon Indicating Mistakes to Avoid in This Math Topic

Sign Errors When Substituting Values
 

Green Checkmark Icon Indicating Correct Solutions in This Math Topic

A common error students make when finding the root is mishandling the negative sign when substituting values in the formula. For example, if the value of b is -3, and when substituting the value in the formula -b ± b2 - 4ac2a, students write the value of -b as 3 instead of -(-3). To avoid this, always use parentheses when substituting the value.  
 

Mistake 3

Red Cross Icon Indicating Mistakes to Avoid in This Math Topic

Errors in Simplifying Square Roots
 

Green Checkmark Icon Indicating Correct Solutions in This Math Topic

Students frequently overlook the fact that using the quadratic formula to take the square root of a positive number involves both positive and negative roots. For example,  25 it should produce ±5, not just 5. One of the two solutions is lost if the "±" sign is ignored. Always keep in mind that the quadratic formula's square root symbol encompasses both the positive and negative roots, to prevent this. This point is reinforced when the formula is written with the ±.
 

Mistake 4

Red Cross Icon Indicating Mistakes to Avoid in This Math Topic

Incorrect Use of the Quadratic Formula
 

Green Checkmark Icon Indicating Correct Solutions in This Math Topic

Sometimes the students misinterpret the quadratic formula by missing dividing the whole expression by 2a, or by improperly grouping the whole numerator. For example, writing -b   b2 - 4ac / 2a. Not writing parentheses may result in inaccuracy while simplifying the equation. To prevent this, memorize the entire formula and perform the steps in the right order: divide both terms by 2a after evaluating the discriminant and applying the square root. The proper format to write is:

x = - b  b2 - 4ac2a
 

Mistake 5

Red Cross Icon Indicating Mistakes to Avoid in This Math Topic

Skipping the Factoring Method
 

Green Checkmark Icon Indicating Correct Solutions in This Math Topic

The quadratic formula is not always the most effective approach, even though it works for all quadratic equations. There are instances when the equation is easy enough to factor rapidly. For instance, 𝑥2 − 7x + 12 = 0 can be factored as (x − 3)(x − 4) = 0. The process may take longer than necessary if you jump directly to the quadratic formula. Therefore, before employing other techniques, it is advisable to determine whether the equation is factorable.
 

arrow-right
Max from BrightChamps Saying "Hey"

Solved Examples of Quadratic Equations

Ray, the Character from BrightChamps Explaining Math Concepts
Max, the Girl Character from BrightChamps

Problem 1

Determine the solution of the Quadratic Equation: x2 - 7x + 12 = 0

Ray, the Boy Character from BrightChamps Saying "Let’s Begin"

x = 3 and x = 4.
 

Explanation

 The quadratic expression should be factored. We will understand it through a step-by-step explanation.

 

 

Step 1: Find two numbers that add up to -7 and multiply to 12.
Those are -3 and -4.
So, x2 - 7x + 12 
= x2 - 3x - 4x + 12 
= (x - 3) (x - 4) (x will be constant)

 

 

Step 2: Use the zero-product property.
Set each factor to 0 after determining that (x−3)(x−4)=0:
       
                             x - 3 = 0;    x = 3. (We solve for 𝑥 by adding 3 to both sides of the equation.)

                             x - 4 = 0;    x = 4 (we will add 4 to both sides).

Therefore, the final answer will be x = 3 and x = 4. 
 

Max from BrightChamps Praising Clear Math Explanations
Max, the Girl Character from BrightChamps

Problem 2

Find the solution to the quadratic equation: 𝑥2 + 4x + 8 = 0

Ray, the Boy Character from BrightChamps Saying "Let’s Begin"

x = -2 +2i and x = -2-2i
 

Explanation

We will solve the equation following the steps:

 

 

Step 1: Determine the coefficients that will be, 
a = 1, b = 4, and c = 8

 

 

Step 2: Apply the quadratic formula:
      
                            x = - b  b2 - 4ac2a

                           x = - 4   42- 4  1  82  1

     
                           x = - 4   16 - 32 2    


                              = - 4   - 162
                           

 

Step 3: Make the square root simpler:

 -16  = 4i  ( the imaginary number i = (-1) )

            x = - 4  4i2   

            = - 2  2i

Therefore, the final answer is x = - 2 + 2i and x = - 2- 2i.
 

Max from BrightChamps Praising Clear Math Explanations
Max, the Girl Character from BrightChamps

Problem 3

The product of two consecutive positive numbers is 156. Find the numbers.

Ray, the Boy Character from BrightChamps Saying "Let’s Begin"

12 and 13.
 

Explanation

We will be solving the quadratic word problems as well by following the steps.

 


Step 1: Let the numbers be x and x + 1.

 


Step 2: The equation will be formed as x(x + 1) = 156

 


Step 3: Expansion of the equation by moving all the terms to one side: 
                                                x2 + x - 156 = 0 

 

 

Step 4: Calculate the quadratic factor and find two numbers that add up to one and multiply by -156.
13 and -12 are the numbers we’re looking for. So, 13  -12 = -156 and 13 + (-12) = 1.

Therefore, after solving the equation, we get x+13x-12=0 

 

 

Step 5: Solve for the value of x:

x+13 = 0  x = – 13 (which is not positive)
x-12=0 x=12 
After avoiding the negative sign, the numbers are 12 and 13.
 

Max from BrightChamps Praising Clear Math Explanations
Max, the Girl Character from BrightChamps

Problem 4

Solve x2-5x-6=0

Ray, the Boy Character from BrightChamps Saying "Let’s Begin"

x=6, and x= -1
 

Explanation

Step 1: Determine the standard form.
   
                                              x2+bx+c=0
                                            a=1, b= -5, c= -6

 

 

Step 2:  The quadratic should be factored. We search for two figures that:
To get the product, multiply ac=1(-6)= -6
To get the middle term, add b= -5

The numbers are -6 and 1 (because -61= -6 and -6+1= -5)
Therefore, 
                                    x2-5x-6=x2-6x+x-6
                                  x(x-6)+1(x-6)
                                  (x-6)(x+1)=0

 

 

Step 3: Finally, set each factor to 0.

x-6=0x=6
x+1=0x=-1

Therefore, the final answer will be x=6, x=-1.
 

Max from BrightChamps Praising Clear Math Explanations
Max, the Girl Character from BrightChamps

Problem 5

Solve x2+6x+9=0

Ray, the Boy Character from BrightChamps Saying "Let’s Begin"

-3
 

Explanation

 After identifying the ideal square, this trinomial is considered a perfect square.

                                                x2+6x+9=x+32

The second and final step involves factorization of the equation.

                                           x+32=0
                                         x+3=0
                                         x= -3
Therefore, the final answer will be x= -3 (can be a repeated or double root).  
 

Max from BrightChamps Praising Clear Math Explanations
Ray Thinking Deeply About Math Problems

FAQs on Quadratic Equations

1.What is a quadratic equation?

Math FAQ Answers Dropdown Arrow

2.What is the discriminant, and what does it tell us?

Math FAQ Answers Dropdown Arrow

3.What is the vertex of a quadratic function?

Math FAQ Answers Dropdown Arrow

4.How does a quadratic equation's graph appear?

Math FAQ Answers Dropdown Arrow

5.Is it possible to factor all quadratic equations?

Math FAQ Answers Dropdown Arrow

6.How does learning Algebra help students in Saudi Arabia make better decisions in daily life?

Math FAQ Answers Dropdown Arrow

7.How can cultural or local activities in Saudi Arabia support learning Algebra topics such as Quadratic Equations?

Math FAQ Answers Dropdown Arrow

8.How do technology and digital tools in Saudi Arabia support learning Algebra and Quadratic Equations?

Math FAQ Answers Dropdown Arrow

9.Does learning Algebra support future career opportunities for students in Saudi Arabia?

Math FAQ Answers Dropdown Arrow
Math Teacher Background Image
Math Teacher Image

Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

Max, the Girl Character from BrightChamps

Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

INDONESIA - Axa Tower 45th floor, JL prof. Dr Satrio Kav. 18, Kel. Karet Kuningan, Kec. Setiabudi, Kota Adm. Jakarta Selatan, Prov. DKI Jakarta
INDIA - H.No. 8-2-699/1, SyNo. 346, Rd No. 12, Banjara Hills, Hyderabad, Telangana - 500034
SINGAPORE - 60 Paya Lebar Road #05-16, Paya Lebar Square, Singapore (409051)
USA - 251, Little Falls Drive, Wilmington, Delaware 19808
VIETNAM (Office 1) - Hung Vuong Building, 670 Ba Thang Hai, ward 14, district 10, Ho Chi Minh City
VIETNAM (Office 2) - 143 Nguyễn Thị Thập, Khu đô thị Him Lam, Quận 7, Thành phố Hồ Chí Minh 700000, Vietnam
Dubai - BrightChamps, 8W building 5th Floor, DAFZ, Dubai, United Arab Emirates
UK - Ground floor, Redwood House, Brotherswood Court, Almondsbury Business Park, Bristol, BS32 4QW, United Kingdom