Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 1060, how they are used in real life, and tips to learn them quickly.
The numbers that divide 1060 evenly are known as factors of 1060.
A factor of 1060 is a number that divides the number without remainder.
The factors of 1060 are 1, 2, 4, 5, 10, 20, 53, 106, 212, 265, 530, and 1060.
Negative factors of 1060: -1, -2, -4, -5, -10, -20, -53, -106, -212, -265, -530, and -1060.
Prime factors of 1060: 2, 5, and 53.
Prime factorization of 1060: 2² × 5 × 53.
The sum of factors of 1060: 1 + 2 + 4 + 5 + 10 + 20 + 53 + 106 + 212 + 265 + 530 + 1060 = 2268
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 1060. Identifying the numbers which are multiplied to get the number 1060 is the multiplication method.
Step 1: Multiply 1060 by 1, 1060 × 1 = 1060.
Step 2: Check for other numbers that give 1060 after multiplying
2 × 530 = 1060
4 × 265 = 1060
5 × 212 = 1060
10 × 106 = 1060
20 × 53 = 1060
Therefore, the positive factor pairs of 1060 are: (1, 1060), (2, 530), (4, 265), (5, 212), (10, 106), (20, 53). For every positive factor, there is a negative factor.
Dividing the given numbers by whole numbers until the remainder becomes zero and listing out the numbers which result as whole numbers as factors. Factors can be calculated by following a simple division method:
Step 1: Divide 1060 by 1, 1060 ÷ 1 = 1060.
Step 2: Continue dividing 1060 by the numbers until the remainder becomes 0.
1060 ÷ 1 = 1060
1060 ÷ 2 = 530
1060 ÷ 4 = 265
1060 ÷ 5 = 212
1060 ÷ 10 = 106
1060 ÷ 20 = 53
Therefore, the factors of 1060 are: 1, 2, 4, 5, 10, 20, 53, 106, 212, 265, 530, 1060.
The factors can be found by dividing them with prime numbers. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 1060 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
1060 ÷ 2 = 530
530 ÷ 2 = 265
265 ÷ 5 = 53
53 ÷ 53 = 1
The prime factors of 1060 are 2, 5, and 53.
The prime factorization of 1060 is: 2² × 5 × 53.
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows:
Step 1: Firstly, 1060 is divided by 2 to get 530.
Step 2: Now divide 530 by 2 to get 265.
Step 3: Then divide 265 by 5 to get 53. Here, 53 is the smallest prime number, which cannot be divided anymore.
So, the prime factorization of 1060 is: 2² × 5 × 53.
Factor Pairs: Two numbers that are multiplied to give a specific number are called factor pairs. Both positive and negative factors constitute factor pairs.
Positive factor pairs of 1060: (1, 1060), (2, 530), (4, 265), (5, 212), (10, 106), (20, 53).
Negative factor pairs of 1060: (-1, -1060), (-2, -530), (-4, -265), (-5, -212), (-10, -106), (-20, -53).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
There are 53 boxes and 1060 toys. How will they distribute them equally?
They will get 20 toys each.
To divide the toys equally, we need to divide the total toys by the number of boxes.
1060/53 = 20
A rectangular swimming pool has a length of 53 meters, and the total area is 1060 square meters. Find the width.
20 meters.
To find the width of the pool, we use the formula,
Area = length × width
1060 = 53 × width
To find the value of width, we need to shift 53 to the left side.
1060/53 = width
Width = 20.
There are 4 teams and 1060 points. How many points will each team have if distributed equally?
Each team will have 265 points.
To find the points each team will have, divide the total points by the number of teams.
1060/4 = 265
In a class, there are 53 students, and 20 groups. How many students are there in each group if arranged equally?
There are 2 students in each group.
Dividing the students by the total groups, we will get the number of students in each group.
53/20 = 2.65 (rounding to 2 because groups cannot have fractional students)
1060 books need to be arranged in 53 shelves. How many books will go on each shelf?
Each of the shelves has 20 books.
Divide total books by shelves.
1060/53 = 20
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.