Last updated on May 26th, 2025
Learning the table of 120 aids in quick calculations in real life scenarios that entail distributing items, organizing events and solving mathematical problems efficiently and improves one's problem-solving and logic building abilities. In the article below, we will learn more about the same in detail.
The table of 120 is one of the advanced two-digit multiplication tables.
To make learning of the table of 120 easier, one must understand the pattern and practice it regularly.
Below is the table of 120 from the multiples of 1 to 10 followed by 11 to 20.
TABLE OF 120 (1-10) | |
---|---|
120 x 1 = 120 |
120 x 6 = 720 |
120 x 2 = 240 |
120 x 7 = 840 |
120 x 3 = 360 |
120 x 8 = 960 |
120 x 4 = 480 |
120 x 9 = 1080 |
120 x 5 = 600 |
120 x 10 = 1200 |
TABLE OF 120 (11-20) | |
---|---|
120 x 11 = 1320 |
120 x 16 = 1920 |
120 x 12 = 1440 |
120 x 17 = 2040 |
120 x 13 = 1560 |
120 x 18 = 2160 |
120 x 14 = 1680 |
120 x 19 = 2280 |
120 x 15 = 1800 |
120 x 20 = 2400 |
Some tips and tricks to learn the table of 120 are listed below;
Mentioned here are the common mistakes that one can commit while learning the table of 120. You can avoid them by making a note of the below;
The production unit of a factory generates an output of 120 units each day. The production rate increases by 25% on Saturday and Sunday. Find the total number of units produced on Saturday and Sunday.
First, we find the 25% of 120
I.e., 120×25/100 = 30
So on Saturday and Sunday 120+30 units are produced, i.e., 150 units.
In one weekend, 150×2 = 300 units are produced.
150 units are produced in a single day over the weekend so 300 units are produced in total.
Calculate 120×5 using distributive property.
120×5 = 120(3+2)
= (120×3)+(120×2)
= 360+240
=600
the distributive property breaks the multiplicand, 5 into 2 and 3 to simplify the multiplication.
6(2x-10)=720, find x.
To solve for x, we first divide both LHS and RHS by 6;
2x-10 = 720/6 = 120
Now we solve for 2x;
2x= 120+10 = 130
Now x;
x= 130/2 = 65
By dividing and isolating x, we simplify the given equation.
There are three consecutive multiples of 120 whose sum is 1080. Find the numbers.
Let the three consecutive multiples be; 120n, 120(n+1), 120(n+2).
120n+120(n+1)+120(n+2) = 1080
Simplify the above;
120n+120n+120+120n+240 = 1080
360n+360 = 1080
Now we subtract 360 from both LHS and RHS;
360n=720
n= 720/360
n=2
120n → 120×2 = 240
120(n+1) → 120(2+1) = 120×3 = 360
120(n+2) → 120(2+2) = 120×4 = 480
Verify the same;
240+360+480 =1080
The three consecutive multiples are 240,360 and 480, and we find the same as explained above.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables