Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 5476.
The square root is the inverse of the square of the number. 5476 is a perfect square. The square root of 5476 is expressed in both radical and exponential form. In the radical form, it is expressed as √5476, whereas (5476)^(1/2) in the exponential form. √5476 = 74, which is a rational number because it can be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method can be used for perfect square numbers. For non-perfect squares, the long-division method and approximation method are used. Let us now learn the methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 5476 is broken down into its prime factors:
Step 1: Finding the prime factors of 5476 Breaking it down, we get 2 x 2 x 41 x 41: 2^2 x 41^2
Step 2: Now we found out the prime factors of 5476. The next step is to make pairs of those prime factors. Since 5476 is a perfect square, the digits of the number can be grouped in pairs.
Therefore, √5476 = 2 x 41 = 82.
The long division method is particularly used for perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, we need to group the numbers from right to left. In the case of 5476, we group it as 54 and 76.
Step 2: Now we need to find n whose square is less than or equal to 54. We can say n is 7 because 7 x 7 = 49, which is less than 54. The quotient is 7, and the remainder is 54 - 49 = 5.
Step 3: Bring down 76, making the new dividend 576. Add the old divisor with the same number 7 + 7 to get 14 as our new divisor.
Step 4: We need to find the value of n such that 14n x n ≤ 576. Let n be 4, then 144 x 4 = 576.
Step 5: Subtracting 576 - 576 gives a remainder of 0.
Step 6: The quotient is 74.
So the square root of √5476 is 74.
The approximation method is an easy method for finding the square roots. Here’s how to approximate the square root of 5476.
Step 1: Find the closest perfect square of √5476. The square root of 5476 is exactly 74, so the approximation method is not needed in this case since 5476 is a perfect square.
Students make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Let us look at a few common mistakes and how to avoid them.
Can you help Max find the area of a square box if its side length is given as √5476?
The area of the square is 5476 square units.
The area of the square = side².
The side length is given as √5476.
Area of the square = side² = (√5476) x (√5476) = 74 x 74 = 5476.
Therefore, the area of the square box is 5476 square units.
A square-shaped building measuring 5476 square feet is built; if each of the sides is √5476, what will be the square feet of half of the building?
2738 square feet
Since the building is square-shaped, we can divide the given area by 2.
Dividing 5476 by 2 = 2738.
So half of the building measures 2738 square feet.
Calculate √5476 x 5.
370
The first step is to find the square root of 5476, which is 74.
The second step is to multiply 74 by 5.
So 74 x 5 = 370.
What will be the square root of (5476 + 24)?
The square root is 75.
To find the square root, we need to find the sum of (5476 + 24). 5476 + 24 = 5500, and √5500 is approximately 74.16.
Therefore, the square root of (5476 + 24) is approximately ±74.16.
Find the perimeter of the rectangle if its length ‘l’ is √5476 units and the width ‘w’ is 38 units.
The perimeter of the rectangle is 224 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√5476 + 38) = 2 × (74 + 38) = 2 × 112 = 224 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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