Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse operation, finding a square root, is used in various fields such as vehicle design and finance. Here, we will discuss the square root of 226.
The square root is the inverse operation of squaring a number. Since 226 is not a perfect square, its square root is expressed in both radical and exponential forms. In radical form, it is expressed as √226, whereas in exponential form it is expressed as (226)^(1/2). √226 ≈ 15.0333, which is an irrational number because it cannot be expressed as a fraction p/q, where p and q are integers and q ≠ 0.
For perfect squares, the prime factorization method is typically used. However, for non-perfect squares like 226, methods such as long division and approximation are employed. Let us delve into these methods:
The prime factorization method involves expressing a number as a product of its prime factors. Let's break down 226 into its prime factors:
Step 1: Finding the prime factors of 226 Breaking it down, we get 2 x 113: 2^1 x 113^1
Step 2: Since 226 is not a perfect square, the digits cannot be paired.
Therefore, calculating √226 using prime factorization is not feasible.
The long division method is well-suited for non-perfect squares. This method involves finding the closest perfect square for the given number. Let's find the square root using this method, step by step:
Step 1: Group the digits in pairs from right to left. For 226, consider it as 26 and 2.
Step 2: Find the largest number whose square is less than or equal to 2. Here, n = 1. Subtract 1^2 from 2, leaving a remainder of 1.
Step 3: Bring down the next pair, 26, making it 126. Double the divisor (1), giving 2, to form the new divisor.
Step 4: Find n such that 2n x n ≤ 126. Using n = 5, we have 25 x 5 = 125.
Step 5: Subtract 125 from 126, leaving a remainder of 1. The quotient is 15.
Step 6: Since the dividend is less than the divisor, add a decimal point and bring down two zeros, making it 100.
Step 7: The new divisor becomes 300 (from 2 x 15), and n is 3 since 303 x 3 = 909.
Step 8: Subtract 909 from 1000, leaving 91.
Step 9: Continue this process to achieve two decimal places.
Thus, √226 ≈ 15.03.
The approximation method provides an easy way to find the square root of a number. Here's how to find the square root of 226 using this method:
Step 1: Identify the closest perfect squares to √226. The nearest perfect square less than 226 is 225, and the nearest greater is 256. So, √226 is between 15 and 16.
Step 2: Apply the formula: (Given number - smaller perfect square)/(Greater perfect square - smaller perfect square). Using the formula (226 - 225) ÷ (256 - 225) = 1/31 ≈ 0.0323. Add this to the smaller perfect square root: 15 + 0.0323 ≈ 15.0323, so √226 ≈ 15.03.
Mistakes often occur when finding square roots, such as neglecting the negative square root or misapplying methods like long division. Let's explore common errors and how to avoid them.
Can you help Max find the area of a square box if its side length is given as √226?
The area of the square is approximately 510.9929 square units.
The area of a square = side².
With a side length of √226,
area = (√226)²
= 226 square units.
A square-shaped building measuring 226 square feet is built. If each side is √226, what will be the square feet of half the building?
113 square feet
For a square building, dividing the area by 2 gives half the building's area.
226 ÷ 2 = 113 square feet.
Calculate √226 x 5.
Approximately 75.1665
First, find √226 ≈ 15.0333, then multiply by 5: 15.0333 x 5 ≈ 75.1665.
What is the square root of 225 + 1?
The square root is 15.0333
Calculate 225 + 1 = 226,
so √226 ≈ 15.0333.
Find the perimeter of a rectangle if its length ‘l’ is √226 units and the width ‘w’ is 38 units.
The perimeter of the rectangle is approximately 106.0666 units.
Perimeter of a rectangle = 2 × (length + width).
Perimeter = 2 × (√226 + 38)
≈ 2 × (15.0333 + 38)
≈ 106.0666 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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