Last updated on July 4th, 2025
Each element of a square matrix has a minor, which is the determinant of the submatrix formed by removing its row and column. The minor is found to determine the determinant, cofactors, adjoint, and inverse of a matrix.
The minor of an element in a matrix is the determinant of the submatrix obtained after the removal of its row and column. For an element aij, its minor is denoted by Mij. Let’s consider a matrix B:
B12 is in row 1, column 2, so we will remove row 1 and column 2 from the given matrix.
The minor of b12 is:
Similarly, the minor of each element bij in matrix B can be calculated and arranged to form a cofactor matrix M.
We should find the minor of an element inside a matrix. To do that, follow the steps given below:
Step 1: Identify the row and column the element belongs to and remove them from the given matrix.
Step 2: From the remaining elements, form the submatrix and compute its determinant.
Step 3: Find the determinant of the submatrix to get the minor. Using minor values, form a new matrix called matrix of a minor.
For example, consider a 3 × 3 matrix:
To find the minor of element b11 remove the first row and first column of the original matrix.
Minor of b11 = M11 = |4 5| = (4) (8) - (5) (6) = 32 - 30 = 2
|6 8|
The minor of element b23 can be found by removing the second row and third column.
Minor of b23 = M23 = |1 2| = (1) (6) - (2) (7) = 6 - 14 = -8
|7 6|
To find the minor of element b32 remove the third roe and second column.
Minor of b32 = M32 = |1 3| = (1) (5) - (3) (0) = 5 - 0 = 5
|0 5|
We can find the minor of each element in this manner. By finding minors of elements, we can form a new matrix that will be the minor of matrix B.
A matrix’s cofactor, determinant, adjoint, and inverse can be determined by finding the minor of a matrix. Let us see the applications of the minor of a matrix.
Cofactor Matrix: Cij is used to denote the cofactor of an element in a matrix. Cij is determined by multiplying the minor Mij and (-1)i + j.
Therefore, Cij = (-1)i + j Mij
We get cofactor matrix when we replace each element with its cofactor.
Determinant of a matrix: The determinant of a matrix is a single value that summarizes properties of a matrix. It is calculated using cofactor expansion. The determinant can be found by following these steps:
Pick one row or column.
Find the cofactor of each element in that row/column.
Multiply the elements with their cofactors.
Add all the products.
In a matrix D, the determinant is denoted by d or detD.
The determinant formula for the elements of the first row of matrix D will be:
d = d11C11 + d12C12.+ d13C13
Here, Cij = (-1)i+j Mij. So, the determinant of matrix D is:
Adjoint of a matrix: To find the adjoint of a 3 3 matrix:
Find the cofactor matrix of the given matrix.
Find the transpose of the cofactor matrix.
Let us consider matrix B:
The adjoint of matrix B is equal to the transpose of cofactor matrix
Inverse of a matrix: We should divide the adjoint matrix by the determinant to find the inverse of a matrix.
For a matrix D:
The inverse is D-1 = 1d Adj.D
Determinant:
d = d11C11 + d12C12 + d13C13
Where, C1j is the cofactor of element dij
Adjoint:
Using inverse formula, If det D 0 the inverse of D is:
D-1= 1d adjD
A minor is a building block for the calculation of determinants, cofactors, and matrix inverses. It can be applied to the following real-life applications:
It is possible for students to make avoidable errors while solving for the minor of a matrix. Understanding these commonly occurring errors can help avoid incorrect results.
Find the minor a11 = 4
M11 = 3
Delete row 1 and column 1
Only a22 = 3 remains.
Find the minor of a12 = 2
M12 = -6
Delete row 1 and column 2
M12 = (4) (9) - (6) (7) = 36 - 42 = -6
Find the minor of b22
M22 = - 10
Delete row 2, column 2:
M22 = (2) (7) - (4) (6) = 14 - 24 = -10
Find the minor of C13 = 2
M13 = - 20
Delete row 1 and column 3
M13 = (0) (6) - (5) (4) = 0 - 20 = -20
Find the minor of d21, = 4
M21 = - 65
Delete row 2 and column 1:
M21 = 0 · (9 · 5 - 0 · 4) - 2 · (8 · 5 - 0 · 3) + 3 · (8 · 4 - 9 · 3)
= 0 - 2(40) + 3(32-27)
= 0 - 80 +3(5)
= -80 + 15
= -65
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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