Last updated on August 12, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 30 and 70.
The greatest common factor of 30 and 70 is 10. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 30 and 70, a few methods are described below -
Steps to find the GCF of 30 and 70 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30. Factors of 70 = 1, 2, 5, 7, 10, 14, 35, 70.
Step 2: Now, identify the common factors of them Common factors of 30 and 70: 1, 2, 5, 10.
Step 3: Choose the largest factor The largest factor that both numbers have is 10. The GCF of 30 and 70 is 10.
To find the GCF of 30 and 70 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 30: 30 = 2 × 3 × 5 Prime Factors of 70: 70 = 2 × 5 × 7
Step 2: Now, identify the common prime factors The common prime factors are: 2 × 5
Step 3: Multiply the common prime factors 2 × 5 = 10. The Greatest Common Factor of 30 and 70 is 10.
Find the GCF of 30 and 70 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 70 by 30 70 ÷ 30 = 2 (quotient), The remainder is calculated as 70 − (30×2) = 10 The remainder is 10, not zero, so continue the process
Step 2: Now divide the previous divisor (30) by the previous remainder (10) Divide 30 by 10 30 ÷ 10 = 3 (quotient), remainder = 30 − (10×3) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 30 and 70 is 10.
Finding the GCF of 30 and 70 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 30 rose bushes and 70 sunflower plants. She wants to plant them in rows with an equal number of plants in each row, using the largest possible number of plants per row. How many plants will be in each row?
We should find the GCF of 30 and 70 GCF of 30 and 70 2×5 = 10. There are 10 equal rows 30 ÷ 10 = 3 70 ÷ 10 = 7 There will be 10 rows, and each row gets 3 rose bushes and 7 sunflower plants.
As the GCF of 30 and 70 is 10, the gardener can make 10 rows. Now divide 30 and 70 by 10. Each row gets 3 rose bushes and 7 sunflower plants.
A bakery has 30 chocolate cupcakes and 70 vanilla cupcakes. They want to arrange them in boxes with the same number of cupcakes in each box, using the largest possible number of cupcakes per box. How many cupcakes will be in each box?
GCF of 30 and 70 2×5 = 10. So each box will have 10 cupcakes.
There are 30 chocolate and 70 vanilla cupcakes. To find the total number of cupcakes in each box, we should find the GCF of 30 and 70. There will be 10 cupcakes in each box.
A designer has 30 meters of red fabric and 70 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 30 and 70 The GCF of 30 and 70 2×5 = 10. The fabric is 10 meters long.
For calculating the longest length of the fabric, first we need to calculate the GCF of 30 and 70, which is 10. The length of each piece of the fabric will be 10 meters.
A carpenter has two wooden planks, one 30 cm long and the other 70 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 30 and 70 2×5 = 10. The longest length of each piece is 10 cm.
To find the longest length of each piece of the two wooden planks, 30 cm and 70 cm, respectively, we have to find the GCF of 30 and 70, which is 10 cm. The longest length of each piece is 10 cm.
If the GCF of 30 and ‘a’ is 10, and the LCM is 210. Find ‘a’.
The value of ‘a’ is 70.
GCF × LCM = product of the numbers
10 × 210 = 30 × a
2100 = 30a
a = 2100 ÷ 30 = 70
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.