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Last updated on July 31st, 2025

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GCF of 22 and 55

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The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 22 and 55.

GCF of 22 and 55 for Filipino Students
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What is the GCF of 22 and 55?

The greatest common factor of 22 and 55 is 11. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.

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How to find the GCF of 22 and 55?

To find the GCF of 22 and 55, a few methods are described below:

 

  • Listing Factors

 

  • Prime Factorization

 

  • Long Division Method / by Euclidean Algorithm
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GCF of 22 and 55 by Using Listing of Factors

Steps to find the GCF of 22 and 55 using the listing of factors:

 

Step 1: Firstly, list the factors of each number:

Factors of 22 = 1, 2, 11, 22

Factors of 55 = 1, 5, 11, 55

 

Step 2: Now, identify the common factors of them.

Common factors of 22 and 55: 1, 11

 

Step 3: Choose the largest factor

The largest factor that both numbers have is 11.

The GCF of 22 and 55 is 11.

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GCF of 22 and 55 Using Prime Factorization

To find the GCF of 22 and 55 using the Prime Factorization Method, follow these steps:

 

Step 1: Find the prime factors of each number:

Prime factors of 22: 22 = 2 x 11

Prime factors of 55: 55 = 5 x 11

 

Step 2: Now, identify the common prime factors.

The common prime factor is: 11

 

Step 3: Multiply the common prime factors.

The Greatest Common Factor of 22 and 55 is 11.

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GCF of 22 and 55 Using Division Method or Euclidean Algorithm Method

Find the GCF of 22 and 55 using the division method or Euclidean Algorithm Method. Follow these steps:

 

Step 1: First, divide the larger number by the smaller number

 

Here, divide 55 by 22 55 ÷ 22 = 2 (quotient)

 

The remainder is calculated as 55 − (22×2) = 11

 

The remainder is 11, not zero, so continue the process

 

Step 2: Now divide the previous divisor (22) by the previous remainder (11)

 

Divide 22 by 11 22 ÷ 11 = 2 (quotient), remainder = 22 − (11×2) = 0

 

The remainder is zero, the divisor will become the GCF.

 

The GCF of 22 and 55 is 11.

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Common Mistakes and How to Avoid Them in GCF of 22 and 55

Finding GCF of 22 and 55 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.

Mistake 1

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Listing Incorrect Factors

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Students may sometimes list incorrect factors.

 

For example, while listing factors of 22, students may mention 10, which is incorrect. To avoid this, students should carefully divide the number and list the factors correctly.

Mistake 2

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Choosing the wrong common factor

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Students may sometimes select the smallest common factor instead of the largest one. To avoid this confusion, students should list all the common factors and find the greatest one.

Mistake 3

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Forgetting to include 1 as a factor

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Sometimes students may forget 1 as a common factor of the numbers. However, it does not affect the GCF, but it reflects an incomplete understanding of the factors. Students should include 1 as a factor.

Mistake 4

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Using Multiples instead of factors

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Students confuse between factors and multiples. In that confusion, sometimes they may write multiples instead of factors. To avoid this confusion, students should know the definitions of multiples and factors clearly.

Mistake 5

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Assuming GCF is always an even number

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Students may assume that the GCF of two numbers will always be an even number. But it's not true; a GCF can also be an odd number. To avoid this, students should focus on common factors rather than focusing on even and odd numbers.

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Greatest Common Factor of 22 and 55 Examples

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Problem 1

A teacher has 22 apples and 55 oranges. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?

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We should find the GCF of 22 and 55.

 

GCF of 22 and 55 is 11.

 

There are 11 equal groups.

22 ÷ 11 = 2

55 ÷ 11 = 5

 

There will be 11 groups, and each group gets 2 apples and 5 oranges.

Explanation

As the GCF of 22 and 55 is 11, the teacher can make 11 groups.

 

Now divide 22 and 55 by 11.

 

Each group gets 2 apples and 5 oranges.

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Problem 2

A school has 22 red chairs and 55 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?

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GCF of 22 and 55 is 11. So each row will have 11 chairs.

Explanation

There are 22 red and 55 blue chairs.

 

To find the total number of chairs in each row, we should find the GCF of 22 and 55.

 

There will be 11 chairs in each row.

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Problem 3

A tailor has 22 meters of red ribbon and 55 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?

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For calculating the longest equal length, we have to calculate the GCF of 22 and 55.

 

The GCF of 22 and 55 is 11.

 

The ribbon is 11 meters long.

Explanation

For calculating the longest length of the ribbon, first we need to calculate the GCF of 22 and 55, which is 11. The length of each piece of the ribbon will be 11 meters.

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Problem 4

A carpenter has two wooden planks, one 22 cm long and the other 55 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?

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The carpenter needs the longest piece of wood.

 

GCF of 22 and 55 is 11.

 

The longest length of each piece is 11 cm.

Explanation

To find the longest length of each piece of the two wooden planks, 22 cm and 55 cm, respectively, we have to find the GCF of 22 and 55, which is 11 cm. The longest length of each piece is 11 cm.

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Problem 5

If the GCF of 22 and ‘a’ is 11, and the LCM is 110. Find ‘a’.

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The value of ‘a’ is 55.

Explanation

GCF × LCM = product of the numbers

 

11 × 110 = 22 × a

 

1210 = 22a

 

a = 1210 ÷ 22 = 55

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FAQs on the Greatest Common Factor of 22 and 55

1.What is the LCM of 22 and 55?

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2.Is 22 divisible by 2?

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3.What will be the GCF of any two prime numbers?

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4.What is the prime factorization of 55?

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5.Are 22 and 55 prime numbers?

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6.How can children in Philippines use numbers in everyday life to understand GCF of 22 and 55?

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7.What are some fun ways kids in Philippines can practice GCF of 22 and 55 with numbers?

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8.What role do numbers and GCF of 22 and 55 play in helping children in Philippines develop problem-solving skills?

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9.How can families in Philippines create number-rich environments to improve GCF of 22 and 55 skills?

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Important Glossaries for GCF of 22 and 55

  • Factors: Factors are numbers that divide the target number completely. For example, the factors of 11 are 1 and 11.

 

  • Multiple: Multiples are the products we get by multiplying a given number by another. For example, the multiples of 11 are 11, 22, 33, 44, and so on.

 

  • Prime Factors: These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 22 are 2 and 11.

 

  • Remainder: The value left after division when the number cannot be divided evenly. For example, when 15 is divided by 4, the remainder is 3 and the quotient is 3.

 

  • LCM: The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 22 and 55 is 110.
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Hiralee Lalitkumar Makwana

About the Author

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.

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Fun Fact

: She loves to read number jokes and games.

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