Last updated on July 10th, 2025
The factor theorem, a fundamental concept in algebra, determines if a binomial is a factor of a polynomial. It is also used to find polynomial roots and solve higher-degree polynomial equations, with applications in single processing and optimization
The factor theorem is particularly beneficial in polynomial divisions, graphing functions, and factoring polynomials completely.
The theorem suggests; if f(a) =0, for a polynomial f(x), then (x-a) is a factor of f(x).
The remainder theorem helps in finding remainders without going through the whole process of long division. It states that when a linear divisor (x-a) divides a polynomial f(x), the remainder is the value of the polynomial at x = a, i.e., f(a). The factor theorem is a special case of the remainder theorem
Factor Theorem |
Remainder Theorem |
Used to check if a given binomial is a factor of the given polynomial or not. |
Used to find the remainder for polynomials being divided by binomials |
Focuses on when f(a)=0 |
Focuses on calculating f(a) |
Confirms whether (x-a) is a factor or not |
Gives the exact remainder |
Factor polynomials and find exact roots |
Finds remainders without having to complete the entire division process |
Factor theorem is applied when the remainder is 0 |
Works even when the remainder is not zero |
The factor theorem states:
For a polynomial f(x), if f(a) = 0, then (x - a) is a factor of f(x).
Conversely, if (x - a) is a factor of f(x), then f(a) = 0
For instance, let f(x) = x3 -6x2 + 11x - 6.
Check f(1),
f(1) = 13 - 6(1)2 + 11(1) - 6 = 0
So, by factor theorem, (x-1) is a factor of f(x)
Proof of Factor Theorem:
According to division algorithm for polynomials:
f(x) = (x - a) q(x) + r
Where:
f(x) is the original polynomial
(x - a) is the divisor
q(x) is the quotient polynomial
r is the remainder
Substituting x=a
f(a)= (a - a) q(a) + r = r
So, f(a) = r
If f(a) = 0, then r = 0
f(x) = (x-a) q(x)
So,
(x-a) is a factor of f(x)
The factor theorem is a result of the remainder theorem.
A value that, when substituted with the variable, makes the whole polynomial value zero is the zero of that polynomial. Zeroes of a polynomial are visual representations of the point on a graph where a curve intersects with the x-axis. In other words; If f(a)=0, a is a zero of polynomial f(x).
For example: Let’s take f(x) = x2 - 4
To find the zero, set f(x) = 0
x2- 4 = 0
(x - 2) (x + 2) = 0
So, the zeroes are x= 2 and x= -2
According to the theorem, polynomial f(x) has degree 1. This means that the highest power of variable x is 1. (x - a) is a factor of f(x) if f(a)=0. Here’ a’ is a real number.
So, the formula for factor theorem is: f(x)=(x-a)q(x)
As established above, the factor theorem is generally used while solving polynomial equations.
Let’s see how to apply it, using an example:
Question: Use the factor theorem to check whether (x-3) is a factor of
f(x) - x3 -6x2 = 11x - 6
According to the theorem:
If f(3)=0, then, (x-3) is a factor of f(x)
f(3) = (3)3 - 6(3)2 + 11(3) - 6
= 27- 54 + 33 - 6
= 0
Since f(3) = 0
(x-3) is a factor of the polynomial f(x) - x3 -6x2=11x-6
To factorize a cubic polynomial:
Find zero using the trail- and-error method. Then, using synthetic division method, divide the given polynomial f(x) by the given binomial (x-a),
After division, if the remainder is not zero, then (x-a) is not a factor of f(x).
If the remainder is zero, use the division algorithm and write the given polynomial as a product of (x-a) and quadratic quotient q(x); f(x) = (x-a)q(y) + r
If possible, factor the quadratic quotient further
Then, represent the polynomial in factored form.
Let’s factor f(x) = x3 - 6x2 + 11x - 6 using the aforementioned procedure
The first step is to find a zero using the hit and try method and dividing the given polynomial
Try x=1,
f(1) = 13 - 6(1)2 + 11(1) - 6 = 1 - 6 + 11 - 6 = 0
So, x = 1 is a zero, a (x-1) is a factor.
Now, we will use synthetic division to divide f(x) by (x-1)
| 1 -6 11 -6
1 | 1 -5 6 | 0
---------------------
1 -5 6 0
The quotient is: x2 - 5x = 6
Since the remainder is zero,
X2 - 5x + 6 = (x-2) (x-3)
The polynomial, in its final factored form, is
f(x) = (x-1)(x-2)(x-3)
Thus, the zeroes of given polynomial x3 - 6x2 + 11x - 6 are 1, 2, and 3
The factor theorem is essential in finding zeroes of polynomials. Here are some common mistakes students make while using the theorem and ways to avoid them.
The factor theorem is a mathematical concept helpful in practical fields like engineering, physics, computer graphics, economics, business marketing, robotics etc. Let’s discuss how:
Given: f(x)=x3−4x2+x+6 Show that x = −1 is a root and (x+1) is a factor.
(x+1) is a factor of f(x)
f(x) = x3 - 4x2 + x + 6
Check f(-1):
f(-1) = (-1)3 - 4(-1)2 + (-1) + 6 = -1 - 4–1 + 6 = 0
Since f(-1) = 0, by factor theorem, (x+1) is a factor of f(x)
Given: f(x) = x3 + 2x2 - 5x - 6 Show that x = -3 is a root and (x + 3) is a factor.
f(−3) = 0, so (x + 3) is a factor of f(x)
f(x) = x3 + 2x2 − 5x − 6
Check f(−3):
f(−3) = (−3)2 + 2(−3)2 − 5(−3) − 6
= −27 + 18 + 15 − 6
= 0
f(−3) = 0, so (x + 3) is a factor of f(x)
Given, f(x) = 2x3 + 3x2 − 2x − 3 Prove that x =−1 is a root, and (x+1) is a factor.
f(−1) = 0 ⇒ (x + 1) is a factor of f(x)
f(x) = 2x3 + 3x2 − 2x − 3
Check f(−1)
f(−1) = 2(−1)3 + 3(−1)2 − 2(−1) − 3 = −2 + 3 + 2 − 3 = 0
f(−1) = 0 ⇒ (x + 1) is a factor of f(x)
Given: f(x) = x3 − 3x2 − 4x + 12 Show that x = 2 is a root and (x − 2) is a factor.
f(2) = 0
f(x) = x3 − 3x2 − 4x + 12
Check f(2):
f(2) = 23 − 3(2)2 − 4(2) + 12
= 8 − 12 − 8 + 12
= 0
Given, f(x) = x3 + x2 − 4x − 4. Show that x = −2 is a root and (x + 2) is a factor.
f(−2) = 0, (x = 2) is a factor of f(x)
f(x) = x3 + x2 − 4x − 4
Check f(-2)
f(-2) = -23 + (-2)2 − 4(-2) − 4
= −8 + 4 + 8 − 4
= 0
Since f(−2) = 0, (x = 2) is a factor of f(x)
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.