Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 2535, how they are used in real life, and tips to learn them quickly.
The numbers that divide 2535 evenly are known as factors of 2535.
A factor of 2535 is a number that divides the number without leaving a remainder.
The factors of 2535 are 1, 3, 5, 15, 169, 507, 845, and 2535.
Negative factors of 2535: -1, -3, -5, -15, -169, -507, -845, and -2535.
Prime factors of 2535: 3, 5, and 169.
Prime factorization of 2535: 3 × 5 × 169.
The sum of factors of 2535: 1 + 3 + 5 + 15 + 169 + 507 + 845 + 2535 = 4080
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 2535. Identifying the numbers which are multiplied to get the number 2535 is the multiplication method.
Step 1: Multiply 2535 by 1, 2535 × 1 = 2535.
Step 2: Check for other numbers that give 2535 after multiplying
3 × 845 = 2535
5 × 507 = 2535
15 × 169 = 2535
Therefore, the positive factor pairs of 2535 are: (1, 2535), (3, 845), (5, 507), and (15, 169).
All these factor pairs result in 2535.
For every positive factor, there is a negative factor.
Dividing the given number with whole numbers until the remainder becomes zero and listing out the numbers which result in whole numbers as factors. Factors can be calculated by following a simple division method -
Step 1: Divide 2535 by 1, 2535 ÷ 1 = 2535.
Step 2: Continue dividing 2535 by the numbers until the remainder becomes 0.
2535 ÷ 1 = 2535
2535 ÷ 3 = 845
2535 ÷ 5 = 507
2535 ÷ 15 = 169
Therefore, the factors of 2535 are: 1, 3, 5, 15, 169, 507, 845, 2535.
The factors can be found by dividing it with prime numbers. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 2535 divide the number to break it down into the multiplication form of prime factors till the remainder becomes 1.
2535 ÷ 3 = 845
845 ÷ 5 = 169
169 ÷ 13 = 13
13 ÷ 13 = 1
The prime factors of 2535 are 3, 5, and 13.
The prime factorization of 2535 is: 3 × 5 × 13 × 13.
The factor tree is a graphical representation of breaking down any number into prime factors. The following step shows -
Step 1: Firstly, 2535 is divided by 3 to get 845.
Step 2: Now divide 845 by 5 to get 169.
Step 3: Then divide 169 by 13 to get 13.
Step 4: Divide 13 by 13 to get 1.
Here, 13 is a prime number, that cannot be divided anymore.
So, the prime factorization of 2535 is: 3 × 5 × 13 × 13.
Factor Pairs Two numbers that are multiplied to give a specific number are called factor pairs.
Both positive and negative factors constitute factor pairs.
Positive factor pairs of 2535: (1, 2535), (3, 845), (5, 507), and (15, 169).
Negative factor pairs of 2535: (-1, -2535), (-3, -845), (-5, -507), and (-15, -169).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
There are 15 teams and 2535 players. How will they distribute the players equally?
They will get 169 players each.
To distribute the players equally, we need to divide the total players by the number of teams.
2535/15 = 169
A park is rectangular, the length of the park is 15 meters and the total area is 2535 square meters. Find the width?
169 meters.
To find the width of the park, we use the formula,
Area = length × width
2535 = 15 × width
To find the value of width, we need to shift 15 to the left side.
2535/15 = width
Width = 169.
There are 507 bags and 2535 candies. How many candies will be in each bag?
Each bag will have 5 candies.
To find the candies in each bag, divide the total candies by the bags.
2535/507 = 5
In a class, there are 2535 students, and 3 groups. How many students are there in each group?
There are 845 students in each group.
Dividing the students by the total groups, we will get the number of students in each group.
2535/3 = 845
2535 books need to be arranged in 5 shelves. How many books will go on each shelf?
Each of the shelves has 507 books.
Divide total books by shelves.
2535/5 = 507
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.