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139 LearnersLast updated on February 15th, 2025
The Divisibility Rule of 651
The divisibility rule is a way to find out whether a number is divisible by another number without using the division method. In real life, we can use the divisibility rule for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 651.
What is the Divisibility Rule of 651?
The divisibility rule for 651 is a method by which we can find out if a number is divisible by 651 or not without using the division method. Check whether 1302 is divisible by 651 with the divisibility rule.
Step 1: Divide the number into two equal parts if possible, otherwise, take the closest equal parts. Here in 1302, divide it into 13 and 02.
Step 2: Multiply the first part by 2 and add it to the second part. 13 × 2 + 02 = 28.
Step 3: If the result is a multiple of 651, then the number is divisible by 651. Since 28 is not a multiple of 651, 1302 is not divisible by 651.
Tips and Tricks for Divisibility Rule of 651
Learning the divisibility rule will help kids master division. Let’s learn a few tips and tricks for the divisibility rule of 651.
- Know the multiples of 651: Memorize the multiples of 651 (651, 1302, 1953, 2604, etc.) to quickly check divisibility. If the result from the addition is a
- Use large numbers: If the result after the addition is larger than 651, check if it is a multiple of 651 for divisibility.
- Repeat the process for large numbers: Students should keep repeating the divisibility process until they reach a small number that can be checked against known multiples of 651. For example, check if 2604 is divisible by 651 using the divisibility test. Divide into two parts, 26 and 04. Multiply the first part by 2, i.e., 26 × 2 = 52. Add the second part, 52 + 04 = 56. Since 56 is not a multiple of 651, repeat the process. 2604 divided into 260 and 4. Multiply 260 by 2, i.e., 520. Add the second part, 520 + 4 = 524. 524 is not a multiple of 651, so 2604 is not divisible by 651.
- Use the division method to verify: Students can use the division method as a way to verify and cross-check their results. This will help them verify and also learn.
Common Mistakes and How to Avoid Them in Divisibility Rule of 651
The divisibility rule of 651 helps us quickly check if the given number is divisible by 651, but common mistakes like calculation errors lead to incorrect results. Here we will understand some common mistakes that will help you to understand.
Mistake 1
Not following the correct steps.
Students should follow the correct steps, which involve splitting the number, multiplying the first part, and adding to the second part.
Divisibility Rule of 651 Examples
Problem 1
Is 1953 divisible by 651?
Yes, 1953 is divisible by 651.
Explanation
To check if 1953 is divisible by 651, apply the rule for divisibility by 651, which involves checking if the number is divisible by both 3 and 217 (since 651 = 3 × 217).
1) Sum the digits of 1953: 1 + 9 + 5 + 3 = 18. Since 18 is divisible by 3, 1953 is divisible by 3.
2) Check if 1953 is divisible by 217 by direct division: 1953 ÷ 217 = 9. Since the result is an integer, 1953 is divisible by 217.
3) Since 1953 is divisible by both 3 and 217, it is also divisible by 651.
Problem 2
Check the divisibility rule of 651 for 1302.
No, 1302 is not divisible by 651.
Explanation
To determine if 1302 is divisible by 651, we need to check divisibility by both 3 and 217.
1) Sum the digits of 1302: 1 + 3 + 0 + 2 = 6. Since 6 is divisible by 3, 1302 is divisible by 3.
2) Check if 1302 is divisible by 217 by direct division: 1302 ÷ 217 ≈ 6. This is not an integer, so 1302 is not divisible by 217.
3) Since 1302 is not divisible by 217, it is not divisible by 651.
Problem 3
Is -2604 divisible by 651?
Yes, -2604 is divisible by 651.
Explanation
To check if -2604 is divisible by 651, we ignore the negative sign and check divisibility by both 3 and 217.
1) Sum the digits of 2604: 2 + 6 + 0 + 4 = 12. Since 12 is divisible by 3, 2604 is divisible by 3.
2) Check if 2604 is divisible by 217 by direct division: 2604 ÷ 217 = 12. Since the result is an integer, 2604 is divisible by 217.
3) Since 2604 is divisible by both 3 and 217, it is also divisible by 651.
Problem 4
Can 871 be divisible by 651 following the divisibility rule?
No, 871 is not divisible by 651.
Explanation
To check if 871 is divisible by 651, we need to check divisibility by both 3 and 217.
1) Sum the digits of 871: 8 + 7 + 1 = 16. Since 16 is not divisible by 3, 871 is not divisible by 3.
2) Since 871 is not divisible by 3, it cannot be divisible by 651, regardless of divisibility by 217.
Problem 5
Check the divisibility rule of 651 for 6510.
Yes, 6510 is divisible by 651.
Explanation
To check if 6510 is divisible by 651, we need to ensure divisibility by both 3 and 217.
1) Sum the digits of 6510: 6 + 5 + 1 + 0 = 12. Since 12 is divisible by 3, 6510 is divisible by 3.
2) Check if 6510 is divisible by 217 by direct division: 6510 ÷ 217 = 30. Since the result is an integer, 6510 is divisible by 217.
3) Since 6510 is divisible by both 3 and 217, it is also divisible by 651.
FAQs on Divisibility Rule of 651
1.What is the divisibility rule for 651?
2.How many numbers are there between 1 and 3000 that are divisible by 651?
3.Is 1302 divisible by 651?
4.What if I get 0 after processing the parts?
5.Does the divisibility rule of 651 apply to all integers?
Important Glossaries for Divisibility Rule of 651
- Divisibility Rule: The set of rules used to find out whether a number is divisible by another number or not. For example, a number is divisible by 651 if the processed result is a multiple of 651.
- Multiples: Multiples are the results we get after multiplying a number by an integer. For example, multiples of 651 are 651, 1302, 1953, 2604, etc.
- Integers: Integers are the numbers that include all the whole numbers, negative numbers, and zero.
- Addition: Addition is the process of finding the total or sum by combining two or more numbers.
- Verification: The process of confirming accuracy, such as using the traditional division method to confirm divisibility.
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Hiralee Lalitkumar Makwana
About the Author
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
Fun Fact
: She loves to read number jokes and games.
