Last updated on July 19th, 2025
Odd numbers are numbers that can't be divided into two equal groups without having something left over. They always end in 1, 3, 5, 7, or 9. So, numbers like 1, 3, 5, 7, 9, 11, 13, and so on are odd numbers.
Odd numbers are special numbers that can't be split into two equal groups. Odd numbers are like the solo performers in a group—they don't pair up evenly with others. So, when you try to divide them into two equal groups, there's always one left out!
Adding odd numbers is like collecting something special. When you add the first few odd numbers like 1, 3, 5, 7, you get a magical pattern. The total is always a perfect square number!
Sum of the first three odd numbers:
1 + 3 + 5 = 9 = 3²
Sum of the first four odd numbers:
1 + 3 + 5 + 7 = 16 = 4²
Sum of the first five odd numbers:
1 + 3 + 5 + 7 + 9 = 25 = 5²
Sum of the first six odd numbers:
1 + 3 + 5 + 7 + 9 + 11 = 36 = 6²
The sum of the first n odd numbers is n2
The universal form of an odd number is (2n - 1), where n ≥ 1 is an integer. In odd numbers, one thing happens or exists one after another without breaking the sequence, resulting in a difference of 2. The sum of the first n odd numbers, the sum is given by the formula: Sum = n².
Sum of First n Odd Numbers Proof
The order of odd numbers 1, 3, 5, ..., (2n - 1) is a consistent progression with:
The addition of the first n terms of a consistent progression is given by:
Sₙ = n/2 × (a + l)
Substituting the values:
Sₙ = n/2 × (1 + (2n - 1)) = n/2 × 2n = n²
As a result, the sum of the first n odd numbers is n².
The sum of odd numbers not starting from 1 follows a distinct pattern. In this case, we have to find the sum of odd numbers from 9 to 29, or
Sum of Odd Numbers from 1 to 100
Solving the sum of odd numbers starting from 9 to 29.
Step 1: List the Odd Numbers
Here are the odd numbers between 9 and 29:
9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29
Step 2: Now we will identify the Arithmetic Progression
This is the sequence of an arithmetic progression (AP) where:
First term (a) = 9
Common difference (d) = 2
Last term (l) = 29
Step 3: Here, we need to calculate the Number of Terms (n)
By using the formula for the nth term of an AP:
aₙ = a + (n - 1) × d
Now substitute the known values:
29 = 9 + (n - 1) × 2
Let’s simplify this:
29 = 9 + 2n - 2
29 = 7 + 2n
22 = 2n
n = 11
We have seen 11 terms in this sequence.
Step 4: Now, calculate the Sum of the AP
The sum (Sₙ) of the first n terms of an AP is:
Sₙ = n2 × (a + l)
Substitute the known values:
S₁₁ = 11/2 × (9 + 29)
S₁₁ = 11/2 × 38
S₁₁ = 11 × 19
S₁₁ = 209
As a result, we get the sum of the odd numbers from 9 to 29 is 209.
For calculating the sum of odd numbers from 1 to 100, we must use the formula for the sum of an arithmetic progression (AP):
Sₙ = n/2 × (a + l)
Odd numbers from 1 to 100
a = 1
l = 99
n = 50, there are 50 odd numbers from 1 to 100
Now we substitute these values into the formula:
S₅₀ =50/2× (1 + 99) = 25 × 100 = 2500
So now the sum of all odd numbers from 1 to 100 is 2500.
Let’s see a shortcut formula as well for a better understanding of the sum of the first n odd numbers:
Sum = n²
For n = 50:
Sum = 50² = 2500
The sum of odd numbers is not just something we solve in mathematics, but has real-life applications in many fields. From calculating the book pages to arranging the seating in the theater, understanding this sum increases problem-solving skills.
Learning and understanding the sum of odd numbers is a fundamental concept in mathematics. But by acknowledging the mistake, when we correct it, it helps us get the correct results. Let's see some of them:
What is the sum of the first 5 odd numbers?
The sum of the first 5 odd numbers is 25.
The sum of the first n odd numbers is given by:
Sn = n2
Where n is the number of terms.
For the first 5 odd numbers (1, 3, 5, 7, 9):
S5 = 52 = 25
How many odd numbers are there between 10 and 50?
There are 20 odd numbers between 10 and 50.
The odd numbers between 10 and 50 are 11, 13, 15, ..., 49. To find the total number, we need to use the formula for the nth term of an arithmetic progression:
Tn = a + (n − 1) · d
Where a = 11 (the first term), d = 2 (the common difference), and Tn = 49 (the last term). Solving for n:
49 = 11 + (n − 1) · 2
38 = (n − 1) · 2
n - 1 = 19 ⇒ n = 20
So, as a result, there are 20 odd numbers between 10 and 50.
What is the sum of odd numbers from 1 to 20?
1 to 20: 10 odd numbers → 102 = 100
There are 10 odd numbers between 1 and 20 (1, 3, 5, ..., 19).
Using the formula:
S10=102 = 100
What is the sum of odd numbers from 1 to 30?
1 to 30: 15 odd numbers → 152 = 225
Sum of odd numbers from 1 to 30:
What is the sum of odd numbers from 1 to 60?
1 to 60: 30 odd numbers → 302= 900
There are 30 odd numbers between 1 and 60 (1, 3, 5, ..., 59).
Using the formula:
S30=302= 900
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.