Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 1369.
The square root is the inverse of the square of the number. 1369 is a perfect square. The square root of 1369 is expressed in both radical and exponential form. In the radical form, it is expressed as √1369, whereas in exponential form it is expressed as (1369)^(1/2). √1369 = 37, which is a rational number because it can be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. Since 1369 is a perfect square, we can use the prime factorization method. However, for non-perfect square numbers, long-division and approximation methods are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 1369 is broken down into its prime factors.
Step 1: Finding the prime factors of 1369
Breaking it down, we get 37 x 37: 37^2
Step 2: Now we found out the prime factors of 1369. Since 1369 is a perfect square, the digits of the number can be grouped in pairs. Therefore, calculating 1369 using prime factorization is straightforward, and the square root is 37.
The long division method can also be used for perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, we need to group the numbers from right to left. In the case of 1369, the grouping is not needed as it naturally forms pairs.
Step 2: Now we need to find n whose square is closest to 13. We can say n as '3' because 3 x 3 = 9 is lesser than or equal to 13. Now the quotient is 3, after subtracting 9 from 13 the remainder is 4.
Step 3: Bring down 69, which is the new dividend. Double the quotient to get the new divisor, 6.
Step 4: The new divisor is now 6n. Find the largest n such that 6n * n is less than or equal to 469.
Step 5: Try n = 7, so 67 x 7 = 469.
Step 6: Subtract 469 from 469, the remainder is 0, and the quotient is 37. Therefore, the square root of 1369 is 37.
The approximation method is another method for finding the square roots, and it is an easy method to find the square root of a given number. However, since 1369 is a perfect square, this method is not necessary.
Students do make mistakes while finding the square root, such as forgetting about the negative square root, skipping long division methods, etc. Now let us look at a few of those mistakes that students tend to make in detail.
Can you help Max find the area of a square box if its side length is given as √1369?
The area of the square is 1369 square units.
The area of the square = side^2.
The side length is given as √1369.
Area of the square = side^2 = √1369 x √1369 = 37 x 37 = 1369.
Therefore, the area of the square box is 1369 square units.
A square-shaped building measuring 1369 square feet is built; if each of the sides is √1369, what will be the square feet of half of the building?
684.5 square feet
We can just divide the given area by 2 as the building is square-shaped.
Dividing 1369 by 2 = we get 684.5.
So half of the building measures 684.5 square feet.
Calculate √1369 x 5.
185
The first step is to find the square root of 1369, which is 37.
The second step is to multiply 37 by 5. So 37 x 5 = 185.
What will be the square root of (1360 + 9)?
The square root is 37
To find the square root, we need to find the sum of (1360 + 9). 1360 + 9 = 1369, and then √1369 = 37.
Therefore, the square root of (1360 + 9) is ±37.
Find the perimeter of the rectangle if its length ‘l’ is √1369 units and the width ‘w’ is 38 units.
The perimeter of the rectangle is 150 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√1369 + 38) = 2 × (37 + 38) = 2 × 75 = 150 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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