Last updated on June 18th, 2025
A Paired T-Test is a type of statistical hypothesis test where the test is conducted to compare the average values or means of two related sets of observations. These observations are conducted randomly to ensure that any difference in results is due to the test itself and not other factors.
A Paired T-Test is a way of finding the mean difference between two tests conducted on the same group, an individual, object or unit. It helps in data analysis to compare two means (average) of different tests of the same group. This test is also called a dependent sample t-test. The tests are done twice in order to observe the changes that occurred before and after.
For example, a test is conducted to check if a new type of running shoes makes people run faster. The test is done for a group of people to run a track before and after using the new shoes. It helps to determine if the difference in times is just random, or if the new shoes really made a difference. The difference between the before and after test is a Paired T-test result.
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Both paired and unpaired (independent) t-test are both statistical tests used to compare the means of two groups, but they are used in different situations. Let’s understand them in detail.
Paired (dependent) T-test used when the same group of people or items is measured twice (before and after) of the tests. Whereas, an unpaired (independent) T-test are used when comparing two different groups that are unrelated.
In Paired T-test, the data sample is taken from groups which are measured twice. Whereas in Unpaired T-test, the data is taken from independent groups.
Here are some key takeaways on how to conduct a paired t-test. In order to conduct an accurate paired t-test, it is a must to follow these rules given below:
After analyzing the rules of this test, using a formula, you can find the difference between the means of the two tests conducted. The formula of the paired t-test is given below:
t = d/sd/n
Where,
d = Mean of the difference between paired values.
sd = Standard deviation of the differences
n = Number of pairs
Steps to Use this Formula:
Step 1: Find the difference (d) between each pair of values.
Step 2: Calculate the mean of these differences (d).
Step 3: Find the standard deviation of these differences (sd).
Step 4: Divide sd by the square root of n.
Step 5: Divide d by the result from Step 4 to get the t-value.
The paired t-test table helps to determine the t-value into a statement that shows whether the results are statistically significant. The following table is provided:
Two-Tailed Significance | ||||||
Degrees of Freedom (n-1) | α = 0.20 | 0.10 |
0.05 |
0.02 | 0.01 |
0.002 |
1 |
3.078 |
6.314 |
12.706 |
31.821 |
63.657 |
318.3 |
2 |
1.886 |
2.92 |
4.303 |
6.965 |
9.925 |
22.327 |
3 |
1.638 |
2.353 |
3.182 |
4.541 |
5.841 |
10.214 |
4 |
1.533 |
2.132 |
2.776 |
3.747 |
4.604 |
7.173 |
5 |
1.476 |
2.015 |
2.571 |
3.305 |
4.032 |
5.893 |
6 |
1.44 |
1.943 |
2.447 |
3.143 |
3.707 |
5.208 |
7 |
1.415 |
1.895 |
2.365 |
2.998 |
3.499 |
4.785 |
8 |
1.397 |
1.86 |
2.306 |
2.896 |
3.355 |
4.501 |
9 |
1.383 |
1.833 |
2.262 |
2.821 |
3.25 |
4.297 |
10 |
1.372 |
1.812 |
2.228 |
2.764 |
3.169 |
4.144 |
11 |
1.363 |
1.796 |
2.201 |
2.718 |
3.106 |
4.025 |
12 |
1.356 |
1.782 |
2.179 |
2.681 |
3.055 |
3.93 |
13 |
1.35 |
1.771 |
2.16 |
2.65 |
3.012 |
3.852 |
14 |
1.345 |
1.761 |
2.145 |
2.624 |
2.977 |
3.787 |
15 |
1.341 |
1.753 |
2.131 |
2.602 |
2.947 |
3.733 |
A Paired T-test is done in situations where we can compare before and after any tests, experiments, etc. Here are some of the real-life applications of Paired T-test:
The chance of making mistakes while conducting a paired T-test is very high, as the formula is sometimes daunting for students. Here are the top five mistakes that students might make and how to avoid them.
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If the p- value in a paired t-test is 0.032, and the significance level () is 0.05, what conclusion should be made?
The null hypothesis is rejected
Since p-value (0.032) < (0.05), we reject the null hypothesis, meaning there is a significant difference between the paired data.
Which of the following scenarios is suitable for a paired t-test? Measuring students’ test scores before and after a new study method. Comparing test scores of two different groups of students.
(a) Measuring student’s test scores before and after a new study method.
A paired t-test is used when the same subjects are measured before and after an event. In (b), two separate groups are compared, which requires an independent t-test.
What is the key assumption for performing a paired t-test?
The difference between paired values should follow a normal distribution.
The paired t-test assumes that the differences (not individual values) between paired observations should be normally distributed for valid results.
Which of the following is an example of paired data? (a) The weight of 50 different newborns in a hospital. (b) The weight of 10 babies before and after a new feeding formula.
(b) The weight of 10 babies before and after a new feeding formula.
Paired data involves measuring the same subjects twice under different conditions, making (b) the correct choice.
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Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!