Last updated on June 26th, 2025
A calculator is a tool designed to perform both basic arithmetic operations and advanced calculations, such as those involving calculus. It is especially helpful for completing mathematical school projects or exploring complex mathematical concepts. In this topic, we will discuss the Definite Integral Calculator.
The Definite Integral Calculator is a tool designed for calculating the definite integral of a function over a specified interval. A definite integral is a way of calculating the area under a curve between two points on a graph. The integral is represented by the symbol ∫, and the limits of integration are the two points that define the interval over which the area is calculated.
For calculating the definite integral of a function using the calculator, we need to follow the steps below -
Step 1: Input: Enter the function and the limits of integration (lower limit and upper limit)
Step 2: Click: Calculate Integral. By doing so, the function and limits we have given as input will get processed
Step 3: You will see the value of the definite integral in the output column
Mentioned below are some tips to help you get the right answer using the Definite Integral Calculator.
Calculators mostly help us with quick solutions. For calculating complex math questions, students must know the intricate features of a calculator. Given below are some common mistakes and solutions to tackle these mistakes.
Help Alice find the area under the curve of f(x) = 2x from x = 1 to x = 4.
We find the area under the curve to be 15.
To find the area, we use the definite integral: ∫[1, 4] 2x dx
The antiderivative of 2x is x², so we calculate: [x²] from 1 to 4 = 4² - 1² = 16 - 1 = 15
Evaluate the integral of f(x) = 3x² from x = 0 to x = 3.
The value of the integral is 27.
To find the integral, we use: ∫[0, 3] 3x² dx
The antiderivative of 3x² is x³, so we calculate: [x³] from 0 to 3 = 3³ - 0³ = 27 - 0 = 27
Find the definite integral of f(x) = 5x - 3 from x = 2 to x = 5.
We will get the value as 36.
For the integral, we use: ∫[2, 5] (5x - 3) dx
The antiderivative is (5/2)x² - 3x, so we calculate: [(5/2)x² - 3x] from 2 to 5 = [(5/2)(5)² - 3(5)] - [(5/2)(2)² - 3(2)] = 61.5 - 25.5 = 36
Calculate the area under the curve of f(x) = x³ - x from x = -1 to x = 2.
We find the area under the curve to be 3.75.
Integral = ∫[-1, 2] (x³ - x) dx
The antiderivative is (1/4)x⁴ - (1/2)x², so we calculate: [(1/4)x⁴ - (1/2)x²] from -1 to 2 = [(1/4)(2)⁴ - (1/2)(2)²] - [(1/4)(-1)⁴ - (1/2)(-1)²] = 4 - 0.5 - (0.25 - 0.5) = 3.75
John wants to evaluate the integral of f(x) = 4x³ from x = 1 to x = 2.
The value of the integral is 15.
Integral of f(x) = ∫[1, 2] 4x³ dx
The antiderivative of 4x³ is x⁴, so we calculate: [x⁴] from 1 to 2 = 2⁴ - 1⁴ = 16 - 1 = 15
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
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