Last updated on July 10th, 2025
The scalar triple product is the dot product of a vector with the cross product of two other vectors. It is represented as a · (b × c), where a, b, c are vectors. It is also known as the box product or scalar triple product.
The mathematical operation involving a vector operation in a three-dimensional space is the scalar triple product. It involves the dot product of one vector with the cross product of two others. The result is a scalar value. Mathematically, the scalar triple product of the vectors a, b, and c can be represented as:
a · (b × c)
The two vector operations are the scalar triple product and vector triple product are two distinct vector operations. In this section, we will learn the difference between the scalar triple product and the vector triple product.
Scalar Triple Product |
Vector Triple Product |
For vectors a, b, and c, the scalar triple product is represented as a · (b × c) |
For vectors a, b, and c, the vector triple product is represented as a × (b × c) |
The result will be a scalar |
The result will be a vector |
In geometric interpretation, the scalar triple product represents the volume of the parallelepiped formed by vectors a, b, and c. |
The geometric interpretation of the vector triple product gives the directed volume of a parallelepiped |
It is antisymmetric as the sign changes with the order of the vectors |
The vector triple product is not antisymmetric; changing the order of vectors alters the resulting vector. |
In this section, we will learn the properties of scalar triple products. Understanding these properties helps students calculate volumes and analyze vector orientation and relationships in three-dimensional spaces.
For any three vectors, a, b, and c, the scalar triple product is represented as a · (b × c). The result of this operation is scalar, and it can be calculated using the determinant of a 3 × 3 matrix formed by the components of the vectors:
The vectors in component form:
a = a1 i +a2 j +a3 k
b = b1 i +b2 j +b3 k
c = c1 i +c2 j +c3 k
Finding the scalar triple product a · (b × c) is:
Finding the cross product of b × c
b × c is calculated using the determinant:
(b2c3 - c2b3) i - (b1c3 - c1b3) j + (b1c2 - c1b2) k
Finding the dot product with vector a:
[(b2c3 - c2b3) i - (b1c3 - c1b3) j + (b1c2 - c1b2) k] · (a1i + a2j + a3k)
a1(b2c3 - b3c2 )- a2(b3c1 - b1c3) + a3(b1c2 - b2c1)
The scalar triple product (a b × c)represents the signed volume of the parallelepiped formed by three vectors (a, b, c) as adjacent edges. The base of the parallelepiped is defined by the vectors b and c, their cross product b × c, gives a vector perpendicular to this base, and its magnitude equals the area of the base. The vector a is the height, (b × c) · a is the volume of the parallelepiped:
|a · (b × c)| = |b × c| · |a| · cosθ, where θ is the angle between the vector a and b × c.
The scalar triple product is used in various fields such as mathematics, physics, geometry, and computer graphics. In this section, we will explore some real-life applications of scalar triple products.
We use the scalar triple product for vector algebra calculations. However, students often make mistakes due to confusion in operations, misinterpreting properties, or calculation errors. Here, we will discuss the common mistakes and how to avoid them.
Find the scalar triple product of the vectors: i, j, k
i (j × k) = 1
Here, we first find the cross product of j and k and then their dot product with i.
Cross product: j × k = i
Dot product: i i = 1
Determine the scalar triple product of the vectors i + j, 2i + 2j, i - j
The scalar triple product is 0
Given,
A =i + j
B =2i + 2j
C = i - j
Writing in component form:
A = (1, 1, 0)
B = (2, 2, 0)
C = (1, -1, 0)
Finding B × C
= i (2 0 - 0 (-1)) - j (2 0 - 0 1) + k (2 (-1) - 2 1)
= 0i - 0j + (-4)k
= -4k
Finding the dot product with A
A (B × C) = (1, 1, 0) · (0, 0, -4) = 1 · 0 + 1 · 0 + 0 · -4
= 0
Calculate the volume of the parallelepiped formed by the vectors A = (2, -1, 3), B =4, 0, -2 and C = -1, 2, 1
The volume of the parallelepiped is 34 cubic units.
Finding the scalar triple product using the formula:
A (B × C) =
= 2(0 · 1 - (-2) · 2) - (-1)(4 · 1 - (-2) (-1)) + 3(4 · 2 - 0 · (-1))
= 8 + 2 + 24 = 34.
Find the scalar triple product of the vectors, A = (3, 0, -1), B = (-2, 5, 1), and C = (4, 1, -3)
The scalar triple product is -26
The formula to find the scalar triple product is:
A (B × C) =
= 3 (5 · (-3) - 1 · 1) - 0(-2 · (-3) - 1 · 4) + (-1)(-2 · 1 - 5 · 4)
= 3(-16) + 0 + (-1)(-2 - 20)
= -48 + 22
= -26
Determine the volume of a parallelepiped whose adjacent edges are A = i + j + k C = i + j - k
The volume of a parallelepiped is 4 cubic units.
To find the volume of a parallelepiped, we use the formula:
A = i + j + k = (1, 1, 1)
B = i - j + k = (1, -1, 1)
C = i + j - k = (1, 1, -1)
A (B × C) =
= 1((-1)(-1) - 1 · 1) - 1(1 · (-1) - 1 · 1) + 1(1 · 1 - (-1) · 1)
= 1(0) - 1(-2) + 1(2)
= 0 - (-2) + 2
= 4
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