Last updated on July 15th, 2025
A Geometric Progression (GP) is a sequence where each number is the product of the previous term and a fixed value known as the common ratio. We can find the preceding term in a GP by dividing the given term by the same common ratio. For example, 3, 6, 12, 24, 48,... is a GP with a common ratio of 2. Geometric progressions can contain a finite or an infinite number of terms. In this article, we will learn about the meaning of GP, its formulas, and different types.
The sequence in which each term is obtained by multiplying the previous term by a fixed number (common ratio) is known as a Geometric Progression. It is usually expressed as: a, ar, ar2, ar3…, where ‘a’ represents the first term and ‘r’ represents the common ratio. A common ratio can either be positive or negative. Any term in a GP can be determined using the first term and the common ratio.
Geometric progressions are mainly classified into two types based on their length.
The different types of geometric progressions are:
We will now learn about each type in detail:
Finite geometric progression
A finite geometric progression has a limited number of terms, and the last term is known.
For example: 1/2, 1/4, 1/8, 1/16,…,1/32768 is a finite geometric progression. Here, 1/32768 is the last term.
Infinite geometric progression
An infinite geometric progression has an endless number of terms. Since there is no fixed number of terms, the last term cannot be specified.
For example, the infinite series 3, −6, +12, −24, +... does not have a definite end term.
To help you identify the sequence effectively, we will now look at the key differences between GP and AP.
Geometric Progression (GP) | Arithmetic Progression (AP) |
Multiply each term by the same number (common ratio). | Adds the same number to each term (common difference). |
No common difference between the terms. | No fixed ratio between terms. |
For example: 2, 4, 8, 16,...(r = 2) | For example: 3, 6, 9, 12,...(d = 3) |
Such series can converge or diverge depending on r. | The series is always divergent unless the common difference is zero. |
Terms progress exponentially. | Terms progress linearly. |
Understanding the unique features of a progression helps us identify it more easily. Here are a few properties that geometric progressions (GP) follow.
In a GP, the sum of the terms can be calculated using the following formulas:
For a GP: a, ar, ar2, ar3, …
nth term:
an = arn–1 or an = r × an– 1
Sum of the first n terms:
Sn = a(1 − rn)/(1 − r) for r ≠ 1, and
Sn = n × a for r = 1
Sum of infinite terms:
S∞ = a/(1 - r), when |r| < 1
The sum does not exist when |r| ≥ 1.
Geometric progression has a vital role in various real-life situations. Let’s now learn how this concept can be applied outside mathematics.
Geometric progression is a simple mathematical concept, but many students struggle with its problems. Here are a few common mistakes and tips to avoid them:
Find the 5ᵗʰ term of a GP Given: First term (a) = 3 Common ratio (r) = 2
a₅ = 48
First, apply the formula for the nᵗʰ term:
aₙ = a × rⁿ⁻¹
Substituting the values into the formula:
a₅ = 3 × 2⁵⁻¹ = 3 × 2⁴
Here, we get:
a₅ = 3 × 16 = 48
Find the sum to infinity of a GP Given: a = 8, r = 1/2
S∞ = 16
Let’s first check if |r| < 1
It holds true for the infinite sum since |1/2| < 1.
Using the formula:
S∞ = a / (1 - r)
Substituting the values into the formula:
S∞ = 8 / (1 - 1/2) = 8 / (1/2)
So,
S∞ = 8 × 2 = 16
Find the sum of the first 6 terms of a GP Given: a = 5, r = 3, n = 6
S₆ = 1820
Here, we use the formula for the sum of the first n terms:
Sₙ = a(rⁿ - 1) / (r - 1)
Let’s substitute the values:
S₆ = 5(3⁶ - 1) / (3 - 1)
We now calculate powers and simplify:
3⁶ = 729
S₆ = 5(729 - 1) / 2 = 5 × 728 / 2
So,
S₆ = 3640 / 2 = 1820
Find the 8ᵗʰ term of the GP 5, 10, 20, 40,... Given: a = 5, r = 2, n = 8
a₈ = 640
Here, we apply the formula for the nᵗʰ term:
aₙ = a × rⁿ⁻¹
Substituting the values into the formula:
a₈ = 5 × 2⁸⁻¹ = 5 × 2⁷
So,
a₈ = 5 × 128 = 640
Find how many terms of the GP 3, 6, 12, 24,... are needed to make the sum 93 Given: a = 3, r = 2, Sₙ = 93
n = 5
Using the formula:
Sₙ = a(rⁿ - 1) / (r - 1)
Substituting the given values:
93 = 3(2ⁿ - 1) / (2–1)
Now, simplify to get the result:
93 = 3(2ⁿ - 1)
93 ÷ 3 = 2ⁿ - 1
31 = 2ⁿ - 1
2n = 31 + 1
2ⁿ = 32
Here, n is the exponent to which 2 needs to be raised to obtain 32.
Since 25 = 32
→ n = 5
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