Last updated on May 26th, 2025
The Least common multiple (LCM) is the smallest number that is divisible by the numbers 3 and 5. The LCM can be found using the listing multiples method, the prime factorization and/or division methods. LCM helps to solve problems with fractions and scenarios like scheduling or aligning repeating cycle of events.
The LCM of 3 and 5 is the smallest positive integer, a multiple of both numbers. By finding the LCM, we can simplify the arithmetic operations with fractions to equate the denominators.
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There are various methods to find the LCM, Listing method, prime factorization method and division method are explained below;
The LCM of 3 and 5 can be found using the following steps:
Step 1: Write down the multiples of each number
Multiples of 3 = 3,6,9,12,15 …
Multiples of 5 = 5, 10,15,20 …
Step 2:Ascertain the smallest multiple from the listed multiples
The smallest common multiple is 15.
Thus, LCM(3, 5) = 15.
The prime factors of each number are written, and then the highest power of the prime factors is multiplied to get the LCM.
Step 1:Find the prime factors of the numbers:
Prime factorization of 3 = 3
Prime factorization of 5 = 5
Take the highest powers of each prime factor:
Highest power of 3 = 3
Highest power of 5 = 5
Multiply the highest powers to get the LCM:
LCM(3, 5) = 3 × 5 = 15
This method involves dividing both numbers by their common prime factors until no further division is possible, then multiplying the divisors to find the LCM.
Step1: Write the numbers:
Step 2 : Divide by common prime factors and multiply the divisors:
3 × 5 = 15
Thus, LCM(3, 5) = 15.
Listed below are a few commonly made mistakes while attempting to ascertain the LCM of 3 and 5, make a note while practicing.
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A number n is divisible by 3 and 5. The value of n is between 20 and 40, find n.
To solve for n, we first find the LCM of the numbers 3 and 5;
Prime factorization of 3 = 31
Prime factorization of 5 = 51
LCM (3,5) = 15
15×2 = 30, a multiple of both 3 and 5.
We find a multiple of 15, that falls in the range of 20 and 40 is; 15 ×2 = 30, which is divisible by both 3 and 5.
Verify a×b = LCM (a,b) ×HCF(a,b) for 3 and 5.
a = 3, b= 5
a×b = LCM (a,b) ×HCF(a,b)
3×5 = LCM (3,5) ×HCF(3,5)
15 = 15 ×1
15 = 15
LHS = RHS in the above solution, the relationship is hence verified.
The product of a and b is 45, and the HCF is 1. a = 3, find the LCM.
We know that; a×b = LCM (a,b) ×HCF(a,b)
Given; 3×b = 45, HCF(3,b)= 1
Applying the same in the formula;
45 = LCM (3,b) ×1
LCM (3,b) = 45/1 = 45
Now we solve for b - 3×b = 45
b = 45/3 = 15
The other number is 15, LCM(3,15) = 15.
A car mechanic services a red car every 3 days and a blue car every 5 days. If the cars are serviced today, when will they be serviced next together?
The LCM of 3 and 5 is 15.
Both cars will be serviced again in 15 days, which is the smallest time interval between the digits.
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Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.