Last updated on August 12th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 27 and 81.
The greatest common factor of 27 and 81 is 27. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 27 and 81, a few methods are described below: -
Steps to find the GCF of 27 and 81 using the listing of factors:
Step 1: Firstly, list the factors of each number. Factors of 27 = 1, 3, 9, 27. Factors of 81 = 1, 3, 9, 27, 81.
Step 2: Now, identify the common factors of them. Common factors of 27 and 81: 1, 3, 9, 27.
Step 3: Choose the largest factor. The largest factor that both numbers have is 27. The GCF of 27 and 81 is 27.
To find the GCF of 27 and 81 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number. Prime Factors of 27: 27 = 3 x 3 x 3 = 3³ Prime Factors of 81: 81 = 3 x 3 x 3 x 3 = 3⁴
Step 2: Now, identify the common prime factors. The common prime factors are: 3 x 3 x 3 = 3³
Step 3: Multiply the common prime factors. 3³ = 27. The Greatest Common Factor of 27 and 81 is 27.
Find the GCF of 27 and 81 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number. Here, divide 81 by 27. 81 ÷ 27 = 3 (quotient), The remainder is calculated as 81 − (27×3) = 0.
Since the remainder is zero, the divisor will become the GCF. The GCF of 27 and 81 is 27.
Finding the GCF of 27 and 81 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 27 notebooks and 81 pencils. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 27 and 81. GCF of 27 and 81: 3³ = 27.
There are 27 equal groups. 27 ÷ 27 = 1 81 ÷ 27 = 3
There will be 27 groups, and each group gets 1 notebook and 3 pencils.
As the GCF of 27 and 81 is 27, the teacher can make 27 groups. Now divide 27 and 81 by 27. Each group gets 1 notebook and 3 pencils.
A school has 27 red flags and 81 blue flags. They want to arrange them in rows with the same number of flags in each row, using the largest possible number of flags per row. How many flags will be in each row?
GCF of 27 and 81: 3³ = 27. So each row will have 27 flags.
There are 27 red and 81 blue flags. To find the total number of flags in each row, we should find the GCF of 27 and 81. There will be 27 flags in each row.
A tailor has 27 meters of red fabric and 81 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 27 and 81. The GCF of 27 and 81: 3³ = 27. The fabric is 27 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 27 and 81, which is 27. The length of each piece of fabric will be 27 meters.
A carpenter has two wooden planks, one 27 cm long and the other 81 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 27 and 81: 3³ = 27. The longest length of each piece is 27 cm.
To find the longest length of each piece of the two wooden planks, 27 cm and 81 cm, respectively, we have to find the GCF of 27 and 81, which is 27 cm. The longest length of each piece is 27 cm.
If the GCF of 27 and ‘a’ is 27, and the LCM is 81. Find ‘a’.
The value of ‘a’ is 81.
GCF x LCM = product of the numbers
27 × 81 = 27 × a
2187 = 27a
a = 2187 ÷ 27 = 81
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.