Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 21 and 28.
The greatest common factor of 21 and 28 is 7. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 21 and 28, a few methods are described below:
Steps to find the GCF of 21 and 28 using the listing of factors:
Step 1: Firstly, list the factors of each number:
Factors of 21 = 1, 3, 7, 21.
Factors of 28 = 1, 2, 4, 7, 14, 28.
Step 2: Now, identify the common factors of them Common factors of 21 and 28: 1, 7.
Step 3: Choose the largest factor The largest factor that both numbers have is 7.
The GCF of 21 and 28 is 7.
To find the GCF of 21 and 28 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number:
Prime Factors of 21: 21 = 3 x 7
Prime Factors of 28: 28 = 2 x 2 x 7 = 2² x 7
Step 2: Now, identify the common prime factors
The common prime factor is: 7
Step 3: Multiply the common prime factors
The Greatest Common Factor of 21 and 28 is 7.
Find the GCF of 21 and 28 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number.
Here, divide 28 by 21 28 ÷ 21 = 1 (quotient),
The remainder is calculated as 28 − (21×1) = 7
The remainder is 7, not zero, so continue the process
Step 2: Now divide the previous divisor (21) by the previous remainder (7)
Divide 21 by 7 21 ÷ 7 = 3 (quotient), remainder = 21 − (7×3) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 21 and 28 is 7.
Finding GCF of 21 and 28 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 21 apples and 28 oranges. He wants to create fruit baskets with equal numbers of fruits in each, using the largest number of fruits possible. How many fruits will be in each basket?
We should find the GCF of 21 and 28 GCF of 21 and 28 is 7.
There are 7 equal groups
21 ÷ 7 = 3
28 ÷ 7 = 4
There will be 7 baskets, and each basket gets 3 apples and 4 oranges.
As the GCF of 21 and 28 is 7, the chef can make 7 baskets.
Now divide 21 and 28 by 7.
Each basket gets 3 apples and 4 oranges.
A gardener has 21 rose bushes and 28 tulip bushes. They want to plant them in rows with the same number of bushes in each row, using the largest number of bushes per row. How many bushes will be in each row?
GCF of 21 and 28 is 7. So each row will have 7 bushes.
There are 21 rose and 28 tulip bushes.
To find the total number of bushes in each row, we should find the GCF of 21 and 28.
There will be 7 bushes in each row.
A tailor has 21 meters of green fabric and 28 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 21 and 28
The GCF of 21 and 28 is 7.
The length of each piece of fabric is 7 meters.
For calculating the longest length of the fabric first we need to calculate the GCF of 21 and 28, which is 7.
The length of each piece of fabric will be 7 meters.
A carpenter has two wooden planks, one 21 cm long and the other 28 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 21 and 28 is 7.
The longest length of each piece is 7 cm.
To find the longest length of each piece of the two wooden planks, 21 cm and 28 cm, respectively, we have to find the GCF of 21 and 28, which is 7 cm.
The longest length of each piece is 7 cm.
If the GCF of 21 and ‘b’ is 7, and the LCM is 84. Find ‘b’.
The value of ‘b’ is 28.
GCF x LCM = product of the numbers
7 × 84 = 21 × b
588 = 21b
b = 588 ÷ 21 = 28
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.