Last updated on May 26th, 2025
The divisibility rule is a way to find out whether a number is divisible by another number without using the division method. In real life, we can use the divisibility rule for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 15.
The divisibility rule for 15 is a method by which we can find out if a number is divisible by 15 or not without using the division method. Check whether 345 is divisible by 15 with the divisibility rule.
Step 1: Check if the number is divisible by 3. Add the digits of the number, 3+4+5=12. Since 12 is divisible by 3, the number passes this part of the test.
Step 2: Check if the number is divisible by 5. Since 345 ends in 5, it is divisible by 5.
Step 3: As the number passes both tests (divisible by both 3 and 5), 345 is divisible by 15.
Learning the divisibility rule will help kids master division. Let’s learn a few tips and tricks for the divisibility rule of 15.
The divisibility rule of 15 helps us quickly check if a given number is divisible by 15, but common mistakes like calculation errors lead to incorrect conclusions. Here we will understand some common mistakes and how to avoid them.
A farmer has 360 apples and wants to pack them into boxes such that each box has an equal number of apples and there are exactly 15 boxes. Is it possible to do so?
Yes, 360 is divisible by 15.
To check if 360 is divisible by 15, we use the rule that a number must be divisible by both 3 and 5.
1. Divisibility by 3: Sum the digits of 360: 3 + 6 + 0 = 9. Since 9 is divisible by 3, 360 is divisible by 3.
2. Divisibility by 5: The last digit of 360 is 0, which is divisible by 5.
Since 360 meets the criteria for divisibility by both 3 and 5, it is divisible by 15.
A baker is preparing 225 cupcakes and needs to package them into boxes such that each box contains 15 cupcakes. Can this be done without any cupcakes left over?
Yes, 225 is divisible by 15.
To check if 225 is divisible by 15, it must be divisible by both 3 and 5.
1. Divisibility by 3: Sum the digits of 225: 2 + 2 + 5 = 9. Since 9 is divisible by 3, 225 is divisible by 3.
2. Divisibility by 5: The last digit of 225 is 5, which is divisible by 5.
Since 225 is divisible by both 3 and 5, it is also divisible by 15.
A librarian has 420 books to arrange on shelves where each shelf must have exactly 15 books. Can this be arranged perfectly?
Yes, 420 is divisible by 15.
To determine if 420 is divisible by 15, it must be divisible by both 3 and 5.
1. Divisibility by 3: Sum the digits of 420: 4 + 2 + 0 = 6. Since 6 is divisible by 3, 420 is divisible by 3.
2. Divisibility by 5: The last digit of 420 is 0, which is divisible by 5.
Since 420 satisfies both conditions, it is divisible by 15.
An event planner has 310 chairs to arrange in rows with each row containing exactly 15 chairs. Is it possible to arrange them without any chairs left over?
No, 310 is not divisible by 15.
To check if 310 is divisible by 15, it must be divisible by both 3 and 5.
1. Divisibility by 3: Sum the digits of 310: 3 + 1 + 0 = 4. Since 4 is not divisible by 3, 310 is not divisible by 3.
2. Divisibility by 5: The last digit of 310 is 0, which is divisible by 5.
Since 310 is not divisible by 3, it is not divisible by 15.
A school has 150 students to organize into teams where each team has exactly 15 students. Can the students be divided evenly?
Yes, 150 is divisible by 15.
To verify if 150 is divisible by 15, check divisibility by both 3 and 5.
1. Divisibility by 3: Sum the digits of 150: 1 + 5 + 0 = 6. Since 6 is divisible by 3, 150 is divisible by 3.
2. Divisibility by 5: The last digit of 150 is 0, which is divisible by 5.
Since 150 is divisible by both 3 and 5, it is divisible by 15.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.