Last updated on May 26th, 2025
In math, multiples are the products we get while multiplying a number with other numbers. Multiples play a key role in construction and design, counting groups of items, sharing resources equally, and managing time effectively. In this topic, we will learn the essential concepts of multiples of 81.
Now, let us learn more about multiples of 81. Multiples of 81 are the numbers you get when you multiply 81 by any whole number, along with zero. Each number has an infinite number of multiples, including a multiple of itself. In multiplication, a multiple of 81 can be denoted as 81 × n, where ‘n’ represents any whole number (0, 1, 2, 3,…). So, we can summarize that:
Multiple of a number = Number × Any whole number
For example, multiplying 81 × 1 will give us 81 as the product. Multiples of 81 will be larger or equal to 81.
Multiples of 81 include the products of 81 and an integer. Multiples of 81 are divisible by 81 evenly. The first few multiples of 81 are given below:
TABLE OF 81 (1-10) | |
---|---|
81 x 1 = 81 |
81 x 6 = 486 |
81 x 2 = 162 |
81 x 7 = 567 |
81 x 3 = 243 |
81 x 8 = 648 |
81 x 4 = 324 |
81 x 9 = 729 |
81 x 5 = 405 |
81 x 10 = 810 |
TABLE OF 81 (11-20) | |
---|---|
81 x 11 = 891 |
81 x 16 = 1296 |
81 x 12 = 972 |
81 x 17 = 1377 |
81 x 13 = 1053 |
81 x 18 = 1458 |
81 x 14 = 1134 |
81 x 19 = 1539 |
81 x 15 = 1215 |
81 x 20 = 1620 |
Now, we know the first few multiples of 81. They are 0, 81, 162, 243, 324, 405, 486, 567, 648, 729, 810,...
Understanding the multiples of 81 helps solve mathematical problems and boost our multiplication and division skills. When working with multiples of 81, we need to apply it to different mathematical operations such as addition, subtraction, multiplication, and division.
81, 162, 243, 324, and 405 are the first five multiples of 81. When multiplying 81 from 1 to 5, we get these numbers as the products.
So, the sum of these multiples is:
81 + 162 + 243 + 324 + 405 = 1215
When we add the first 5 multiples of 81, the answer will be 1215.
While we do subtraction, it improves our comprehension of how the value decreases when each multiple is subtracted from the previous one. 81, 162, 243, 324, and 405 are the first five multiples of 81. So, let us calculate it as given below:
81 - 162 = -81
-81 - 243 = -324
-324 - 324 = -648
-648 - 405 = -1053
Hence, the result of subtracting the first 5 multiples of 81 is -1053.
To calculate the average, we need to identify the sum of the first 5 multiples of 81, and then divide it by the count, i.e., 5. Because there are 5 multiples presented in the calculation. Averaging helps us to understand the concepts of central tendencies and other values. We know the sum of the first 5 multiples of 81 is 1215.
81 + 162 + 243 + 324 + 405 = 1215
Next, divide the sum by 5:
1215 ÷ 5 = 243
243 is the average of the first 5 multiples of 81.
The product of given numbers is the result of multiplying all of them together. Here, the first 5 multiples of 81 include: 81, 162, 243, 324, and 405. Now, the product of these numbers is:
81 × 162 × 243 × 324 × 405 = 10,616,424,210
The product of the first 5 multiples of 81 is 10,616,424,210.
While we perform division, we get to know how many times 81 can fit into each of the given multiples. 81, 162, 243, 324, and 405 are the first 5 multiples of 81.
81 ÷ 81 = 1
162 ÷ 81 = 2
243 ÷ 81 = 3
324 ÷ 81 = 4
405 ÷ 81 = 5
The results of dividing the first 5 multiples of 81 are: 1, 2, 3, 4, and 5.
While working with multiples of 81, we make common mistakes. Identifying these errors and understanding how to avoid them can be helpful. Below are some frequent mistakes and tips to avoid them:
In a small town, the community center holds a bingo night where every game has 81 participants. If they host bingo night 5 times a month, how many participants will there be over 3 months?
1,215 participants
Each bingo night has 81 participants. To find the total number of participants over 3 months, multiply the number of participants per game by the number of nights and then by the number of months.
Participants per game = 81
Number of bingo nights per month = 5
Number of months = 3
81 × 5 × 3 = 1,215
There will be 1,215 participants over 3 months.
At an art exhibition, a gallery displays sculptures in series of multiples of 81. The first series has 81 sculptures, the second has 162, and the third has 243. How many sculptures are there in total in these three series?
486 sculptures
The first series has 81 sculptures, the second series has 162, and the third series has 243. Adding them gives the total number of sculptures.
81 + 162 + 243 = 486
There are a total of 486 sculptures in the three series.
A factory produces boxes in batches of 81. If the factory works for 7 days, producing one batch per day, how many boxes are produced in total?
567 boxes
The factory produces 81 boxes per day. To find the total number of boxes produced over 7 days, multiply the number of boxes per day by the number of days.
Boxes per day = 81
Number of days = 7
81 × 7 = 567
The factory produces a total of 567 boxes in 7 days
In a library, every section is organized to hold a collection of books in multiples of 81. The first section has 81 books, the second has 162 books, and the third section has 243 books. How many books are there in total in these three sections?
486 books
The first section has 81 books, the second section has 162, and the third section has 243. Adding them gives the total number of books.
81 + 162 + 243 = 486
There are a total of 486 books in the three sections.
For a large conference, organizers need to arrange chairs in rows of 81. If there are 6 rows, how many chairs are there in total?
486 chairs
Each row contains 81 chairs. To find the total number of chairs, multiply the number of chairs per row by the number of rows.
Chairs per row = 81
Number of rows = 6
81 × 6 = 486
There are a total of 486 chairs for the conference.