Last updated on June 25th, 2025
Calculators are reliable tools for solving simple mathematical problems and advanced calculations like integration. Whether you're studying calculus, solving engineering problems, or analyzing mathematical models, calculators will make your life easier. In this topic, we are going to talk about improper integral calculators.
An improper integral calculator is a tool to evaluate integrals with infinite limits or integrands that become infinite within the limits of integration. These calculators help simplify the process of calculating complex integrals, saving time and effort.
Given below is a step-by-step process on how to use the calculator:
Step 1: Enter the integral: Input the function and the limits of integration into the given fields.
Step 2: Click on calculate: Click on the calculate button to evaluate the integral and get the result.
Step 3: View the result: The calculator will display the result instantly.
To evaluate improper integrals, the calculator uses limits to handle infinite boundaries or discontinuities in the integrand.
For example, to evaluate an integral from a to ∞, you can use: [ int_a^∞ f(x) , dx = lim_{b to ∞} int_ab f(x) , dx ]
For an integral with a discontinuity at c, you can use: [ int_ab f(x) , dx = lim_{t to c} left( int_at f(x) , dx + int_tb f(x) , dx right) ]
These approaches help in evaluating integrals that would otherwise be undefined or infinite.
When using an improper integral calculator, there are a few tips and tricks to keep in mind to avoid mistakes:
While using a calculator, mistakes can still occur. Here are some common mistakes and how to avoid them.
Evaluate the integral of 1/x from 1 to ∞.
Use the limit process:
[ int_1^∞ frac{1}{x} , dx = lim_{b to ∞} int_1^b frac{1}{x} , dx = lim_{b to ∞} [ln|x|]_1^b = lim_{b to ∞} (ln b - ln 1) = ∞ ]
The integral diverges.
The integral of 1/x from 1 to ∞ does not converge to a finite number, indicating that the area under the curve is infinite.
Find the integral of e^(-x) from 0 to ∞.
Use the limit process:
[ \int_0^∞ e^{-x} , dx = lim_{b to ∞} int_0^b e^{-x} , dx = lim_{b to ∞} [-e^{-x}]_0^b = lim_{b to ∞} (0 + 1) = 1 ]
The integral converges to 1.
The integral of e^(-x) from 0 to ∞ converges to 1, indicating a finite area under the curve.
Evaluate the integral of 1/(x^2) from 1 to ∞.
Use the limit process:
[ int_1^∞ frac{1}{x^2} , dx = lim_{b to ∞} int_1^b frac{1}{x^2} , dx = lim_{b to ∞} [-frac{1}{x}]_1^b = lim_{b to ∞} (0 + 1) = 1 ]
The integral converges to 1.
The integral of 1/(x^2) from 1 to ∞ converges to 1, showing a finite area under the curve.
Calculate the integral of 1/(x - 1) from 0 to 2.
Break it into two parts at the point of discontinuity (x=1):
[ int_0^2 frac{1}{x-1} , dx = lim_{t to 1^-} int_0^t frac{1}{x-1} , dx + lim_{t to 1^+} int_t^2 frac{1}{x-1} , dx ]
Both integrals diverge, indicating the original integral does not converge.
The integral of 1/(x - 1) from 0 to 2 does not converge due to the discontinuity at x=1, leading to divergence.
Evaluate the integral of ln(x) from 0 to 1.
Use the limit process:
[ int_0^1 ln(x) , dx = lim_{a to 0^+} int_a^1 ln(x) , dx = lim_{a to 0^+} [xln(x) - x]_a^1 = lim_{a to 0^+} (0 - 1 + aln(a) - a) ]
The integral converges to -1.
The integral of ln(x) from 0 to 1 converges to -1, indicating a finite area below the x-axis.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
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