Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 1296.
The square root is the inverse of the square of the number. 1296 is a perfect square. The square root of 1296 can be expressed in both radical and exponential form. In radical form, it is expressed as √1296, whereas (1296)^(1/2) in exponential form. √1296 = 36, which is a rational number because it can be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. For non-perfect square numbers, the long division method and approximation method are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 1296 is broken down into its prime factors.
Step 1: Finding the prime factors of 1296
Breaking it down, we get 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3: 2^4 x 3^4
Step 2: Now we found out the prime factors of 1296. Since 1296 is a perfect square, we can pair the prime factors. Therefore, √1296 = (2^2 x 3^2) = 36.
The long division method is particularly used for non-perfect square numbers, but it can also verify perfect squares. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, we need to group the numbers from right to left. In the case of 1296, we group it as 12 and 96.
Step 2: Now we need to find n whose square is less than or equal to 12. We can say n is ‘3’ because 3 x 3 = 9, which is less than 12. The quotient is 3, and the remainder is 12 - 9 = 3.
Step 3: Now bring down 96, making the new dividend 396. Double the quotient (3) to get 6, which becomes part of our new divisor.
Step 4: Find a digit x such that 6x x x is less than or equal to 396. Here, x is 6, because 66 x 6 = 396.
Step 5: Subtract 396 from 396 to get a remainder of 0. The quotient is 36, which is the square root of 1296.
The approximation method is another method for finding square roots, especially for non-perfect squares. It is not necessary for perfect square 1296, but let's apply it for understanding.
Step 1: We have to find the closest perfect squares around √1296. Since 1296 is a perfect square, it's exactly 36.
Step 2: Using the approximation method is unnecessary here, as the perfect square of 1296 is exactly 36.
Students do make mistakes while finding the square root, such as forgetting about the negative square root, skipping long division steps, etc. Now let us look at a few of those mistakes that students tend to make in detail.
Can you help Max find the area of a square box if its side length is given as √169?
The area of the square is 169 square units.
The area of the square = side^2.
The side length is given as √169.
Area of the square = side^2 = √169 x √169 = 13 x 13 = 169.
Therefore, the area of the square box is 169 square units.
A square-shaped building measuring 1296 square feet is built; if each of the sides is √1296, what will be the square feet of half of the building?
648 square feet
We can just divide the given area by 2 as the building is square-shaped.
Dividing 1296 by 2, we get 648.
So half of the building measures 648 square feet.
Calculate √1296 x 5.
180
The first step is to find the square root of 1296, which is 36.
The second step is to multiply 36 by 5.
So, 36 x 5 = 180.
What will be the square root of (144 + 9)?
The square root is 12.
To find the square root, we need to find the sum of (144 + 9). 144 + 9 = 153, and then √153 cannot be simplified as a perfect square.
Therefore, the square root of (144 + 9) is approximately 12.37 (for simplicity, the nearest integer is 12).
Find the perimeter of a rectangle if its length ‘l’ is √256 units and the width ‘w’ is 40 units.
We find the perimeter of the rectangle as 96 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√256 + 40) = 2 × (16 + 40) = 2 × 56 = 112 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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