Last updated on July 2nd, 2025
When a number is multiplied by itself thrice, the resultant number is called the cube of a number. Cubing is used when comparing sizes of objects or things with cubic measurements. In this topic, we shall learn about the cube of 1358.
A cube number is a value obtained by raising a number to the power of 3, or by multiplying the number by itself three times. When you cube a positive number, the result is always positive. When you cube a negative number, the result is always negative. This is because a negative number by itself three times results in a negative number. The cube of 1358 can be written as 1358³, which is the exponential form. Or it can also be written in arithmetic form as, 1358 × 1358 × 1358.
In order to check whether a number is a cube number or not, we can use the following three methods, such as multiplication method, a factor formula (a³), or by using a calculator. These three methods will help kids to cube the numbers faster and easier without feeling confused or stuck while evaluating the answers. By Multiplication Method Using a Formula Using a Calculator
The multiplication method is a process in mathematics used to find the product of two numbers or quantities by combining them through repeated addition. It is a fundamental operation that forms the basis for more complex mathematical concepts. Step 1: Write down the cube of the given number. 1358³ = 1358 × 1358 × 1358 Step 2: You get 2,502,637,512 as the answer. Hence, the cube of 1358 is 2,502,637,512.
The formula (a + b)³ is a binomial formula for finding the cube of a number. The formula is expanded as a³ + 3a²b + 3ab² + b³. Step 1: Split the number 1358 into two parts, as a and b. Let a = 1300 and b = 58, so a + b = 1358 Step 2: Now, apply the formula (a + b)³ = a³ + 3a²b + 3ab² + b³ Step 3: Calculate each term a³ = 1300³ 3a²b = 3 × 1300² × 58 3ab² = 3 × 1300 × 58² b³ = 58³ Step 4: Add all the terms together: (a + b)³ = a³ + 3a²b + 3ab² + b³ (1300 + 58)³ = 1300³ + 3 × 1300² × 58 + 3 × 1300 × 58² + 58³ 1358³ = 2,197,000,000 + 293,160,000 + 4,388,400 + 195,112 1358³ = 2,502,637,512 Step 5: Hence, the cube of 1358 is 2,502,637,512.
To find the cube of 1358 using a calculator, input the number 1358 and use the cube function (if available) or multiply 1358 × 1358 × 1358. This operation calculates the value of 1358³, resulting in 2,502,637,512. It’s a quick way to determine the cube without manual computation. Step 1: Ensure the calculator is functioning properly. Step 2: Enter 1, 3, 5, 8 Step 3: If the calculator has a cube function, press it to calculate 1358³. Step 4: If there is no cube function on the calculator, simply multiply 1358 three times manually. Step 5: The calculator will display 2,502,637,512.
The cube of any even number is always even, while the cube of any odd number is always odd. The product of two or more perfect cube numbers is always a perfect cube. A perfect cube can always be expressed as the product of three identical groups of equal prime factors.
There are some typical errors that kids might make during the process of cubing a number. Let us take a look at five of the major mistakes that kids might make:
What is the cube and cube root of 1358?
The cube of 1358 is 2,502,637,512 and the cube root of 1358 is approximately 11.015.
First, let’s find the cube of 1358. We know that the cube of a number, such that x³ = y Where x is the given number, and y is the cubed value of that number So, we get 1358³ = 2,502,637,512 Next, we must find the cube root of 1358 We know that the cube root of a number ‘x’, such that ³√x = y Where ‘x’ is the given number, and y is the cube root value of the number So, we get ³√1358 ≈ 11.015 Hence the cube of 1358 is 2,502,637,512 and the cube root of 1358 is approximately 11.015.
If the side length of the cube is 1358 cm, what is the volume?
The volume is 2,502,637,512 cm³.
Use the volume formula for a cube V = Side³. Substitute 1358 for the side length: V = 1358³ = 2,502,637,512 cm³.
How much larger is 1358³ than 1300³?
1358³ – 1300³ = 305,637,512.
First find the cube of 1358³, that is 2,502,637,512 Next, find the cube of 1300³, which is 2,197,000,000 Now, find the difference between them using the subtraction method. 2,502,637,512 – 2,197,000,000 = 305,637,512 Therefore, 1358³ is 305,637,512 larger than 1300³.
If a cube with a side length of 1358 cm is compared to a cube with a side length of 58 cm, how much larger is the volume of the larger cube?
The volume of the cube with a side length of 1358 cm is 2,502,637,512 cm³.
To find its volume, we multiply the side length by itself three times (since it’s a 3-dimensional object). Cubing 1358 means multiplying 1358 by itself three times: 1358 × 1358 = 1,844,164, and then 1,844,164 × 1358 = 2,502,637,512. The unit of volume is cubic centimeters (cm³), because we are calculating the space inside the cube. Therefore, the volume of the cube is 2,502,637,512 cm³.
Estimate the cube of 1358 using the cube of 1360.
The cube of 1358 is approximately 2,502,637,512.
First, identify the cube of 1360, The cube of 1360 is 1360³ = 2,519,936,000. Since 1358 is only a tiny bit less than 1360, the cube of 1358 will be almost the same as the cube of 1360. The cube of 1358 is approximately 2,502,637,512 because the difference between 1358 and 1360 is very small. So, we can approximate the value as 2,502,637,512.
Binomial Formula: It is an algebraic expression used to expand the powers of a number, written as (a + b)ⁿ, where ‘n’ is a positive integer raised to the base. The formula is used to find the square and cube of a number. Cube of a Number: Multiplying a number by itself three times is called the cube of a number. Exponential Form: It is a way of expressing numbers using a base and an exponent (or power), where the exponent value indicates how many times the base is multiplied by itself. For example, 2³ represents 2 × 2 × 2 equals 8. Perfect Cube: A number that can be expressed as the cube of an integer. Cube Root: The cube root of a number is a value that, when multiplied by itself three times, gives the original number.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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