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Last updated on July 4th, 2025

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Derivative of Tan x

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We use the derivative of tan(x), which is sec2(x), as a measuring tool for how the tangent function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of tan(x) in detail.

Derivative of Tan x for Bahraini Students
Professor Greenline from BrightChamps

What is the Derivative of Tan x?

We now understand the derivative of tan x. It is commonly represented as d/dx (tan x) or (tan x)', and its value is sec²x. The function tan x has a clearly defined derivative, indicating it is differentiable within its domain.

 

The key concepts are mentioned below:

Tangent Function: (tan(x) = sin(x)/cos(x)).

Quotient Rule: Rule for differentiating tan(x) (since it consists of sin(x)/cos(x)).

Secant Function: sec(x) = 1/cos(x).

 

Professor Greenline from BrightChamps

Derivative of Tan x Formula

The derivative of tan x can be denoted as d/dx (tan x) or (tan x)'. The formula we use to differentiate tan x is:

d/dx (tan x) = sec2 x (or) 

(tan x)' = sec2 x

The formula applies to all x where cos(x) ≠ 0

Professor Greenline from BrightChamps

Proofs of the Derivative of Tan x

We can derive the derivative of tan x using proofs. To show this, we will use the trigonometric identities along with the rules of differentiation. There are several methods we use to prove this, such as:

 

  • By First Principle
     
  • Using Chain Rule
     
  • Using Product Rule

 

We will now demonstrate that the differentiation of tan x results in sec²x using the above-mentioned methods:

Professor Greenline from BrightChamps

By First Principle

The derivative of tan x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. 

 

To find the derivative of tan x using the first principle, we will consider f(x) = tan x. Its derivative can be expressed as the following limit.

 

f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)

Given that f(x) = tan x, we write f(x + h) = tan (x + h).

Substituting these into equation (1),

f'(x) = limₕ→₀ [tan(x + h) - tan x] / h

= limₕ→₀ [ [sin (x + h) / cos (x + h)] - [sin x / cos x] ] / h

= limₕ→₀ [ [sin (x + h ) cos x - cos (x + h) sin x] / [cos x · cos(x + h)] ]/ h

We now use the formula sin A cos B - cos A sin B = sin (A - B).

f'(x) = limₕ→₀ [ sin (x + h - x) ] / [ h cos x · cos(x + h)]

= limₕ→₀ [ sin h ] / [ h cos x · cos(x + h)]

= limₕ→₀ (sin h)/ h · limₕ→₀ 1 / [cos x · cos(x + h)]

Using limit formulas, limₕ→₀ (sin h)/ h = 1.

f'(x) = 1 [ 1 / (cos x · cos(x + 0))] = 1/cos2 x

As the reciprocal of cosine is secant, we have,

f'(x) = sec2 x.

Hence, proved.

Professor Greenline from BrightChamps

Using Chain Rule

To prove the differentiation of tan x using the chain rule,
We use the formula:

 

Tan x = sin x/ cos x

Consider f(x) = sin x and g (x)= cos x

So we get, tan x = f (x)/ g(x)

By quotient rule: d/dx [f(x) / g(x)] = [f '(x) g(x) - f(x) g'(x)] /  [g(x)]2… (1)

Let’s substitute f(x) = sin x and g (x) = cos x in equation (1),

d/ dx (tan x) = [(cos x) (cos x)- (sin x) (- sin x)]/ (cos x)2
  
 (cos2 x + sin2 x)/ cos2 x …(2)

Here, we use the formula:

(cos2 x) + (sin2 x) = 1 (Pythagorean identity)

Substituting this into (2),

d/dx (tan x) = 1/ (cos x)2  

Since sec x = 1/cos x, we write:

d/dx(tan x) = sec2 x

Professor Greenline from BrightChamps

Using Product Rule

We will now prove the derivative of tan x using the product rule. The step-by-step process is demonstrated below:

 

Here, we use the formula,

Tan x = sin x/ cos x

 tan x = (sin x). (cos x)-1  

Given that, u = sin x and v = (cos x)-1

Using the product rule formula: d/dx [u.v] = u'. v + u. v'

u' = d/dx (sin x) = cos x.  (substitute u = sin x)

Here we use the chain rule:

v =  (cos x)-1 = (cos x)-1 (substitute v = (cos x)-1)

⇒ v' = -1. (cos)-2. d/dx (cos x) 

v' = sin x/ (cos x)2  

Again, use the product rule formula:

d/dx (tan x) = u'. v + u. V'

Let’s substitute u = sin x, u' = cos x, v = (cos x)-1, and v' = sin x/ (cos x)2
 
When we simplify each term:

We get, d/dx (tan x) = 1 + sin2x / (cos x)2

Sin2 x/ (cos x)2 = tan2 x (we use the identity sin2 x + cos2 x =1)

Thus: 

d/dx (tan x) = 1 + tan2 x

Since, 1 + tan2 x = sec2 x

⇒ d/dx (tan x) = sec2 x.

Professor Greenline from BrightChamps

Higher-Order Derivatives of Tan x

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like tan (x).

 

  • For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point.

 

  • The second derivative is derived from the first derivative, which is denoted using f′′ (x)

 

  • Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.

 

  • For the nth Derivative of tan(x), we generally use f n(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).

 

Special Cases:

When the x is π/2, the derivative is undefined because tan (x) has a vertical asymptote there.
When the x is 0, the derivative of tan x = sec2 (0), which is 1.

Max Pointing Out Common Math Mistakes

Common Mistakes and How to Avoid Them in Derivatives of Tan x

Students frequently make mistakes when differentiating tan x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not simplifying the equation

Students may forget to simplify the equation, which can lead to incomplete or incorrect results. They often skip steps and directly arrive at the result, especially when solving using the product or chain rule.

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Ensure that each step is written in order. Students might think it is awkward, but it is important to avoid errors in the process.

Mistake 2

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Forgetting the Undefined Points of Tan x

They might not remember that tan x is undefined at the points such as (x = π/2, 3π/2,...).

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Keep in mind that you should consider the domain of the function that you differentiate. It will help you understand that the function is not continuous at such certain points.

Mistake 3

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Incorrect use of Quotient Rule

While differentiating functions such as tan x/ x, students misapply the quotient rule. For example: Incorrect differentiation: d/dx (tan x / x) = sec2 x/ x2

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d/dx (u/v) = (v . u’- u . v’)/ v2  (where u = tan x and v = x)
Applying the quotient rule,
d/dx (tan x/ x) = (x. Sec2 x - tan x)/ x2
 

To avoid this mistake, write the quotient rule without errors. Always check for errors in the calculation and ensure it is properly simplified.

Mistake 4

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Not writing Constants and Coefficients

There is a common mistake that students at times forget to multiply the constants placed before tan x.

For example, they incorrectly write d/dx (5 tan x) ≠ sec2 x.

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Students should check the constants in the terms and ensure they are multiplied properly.

 

For e.g., the correct equation is d/dx (5 tan x) = 5 sec2 x.

Mistake 5

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Not Applying the Chain Rule

Students often forget to use the chain rule. This happens when the derivative of the inner function is not considered.

For example: Incorrect:  d/dx (tan (2x))  sec2 (2x).

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To fix this error, students should divide the functions into inner and outer parts. Then, make sure that each function is differentiated.

 

For example, d/dx (tan (2x)) = 2 sec2(2x).

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Examples Using the Derivative of Tan x

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Problem 1

Calculate the derivative of (tan x·sec² x)

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Here, we have f(x) = tan x·sec²x.

Using the product rule,

f'(x) = u′v + uv′

In the given equation, u = tan x and v = sec2 x.

Let’s differentiate each term,

 u′= d/dx (tan x) = sec2 x

 v′= d/dx (sec2 x) = 2 sec2 x tan x

substituting into the given equation,

⇒ f'(x) = (sec2 x). (sec2 x) + (tan x). (2 sec2 x tan x)
 
Let’s simplify terms to get the final answer,

f'(x) = sec4 x + 2 sec2 x tan2 x

Thus, the derivative of the specified function is sec4 x + 2 sec2 x tan2 x.

Explanation

We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.

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Problem 2

AXB International School sponsored the construction of a road. The slope is represented by the function y = tan(x) where y represents the elevation of the road at a distance x. If x = π/4 meters, measure the slope of the road.

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We have y = tan (x) (slope of the road)...(1)

Now, we will differentiate the equation (1)

Take the derivative tan(x):

dy/ dx = sec2(x)

We know that, ​sec2 (x) = 1 + tan2 (x)

Given x = π/4 (substitute this into the derivative)

​sec2 (π/4) = 1 + tan2 (π/4)

​sec2 (π/4) = 1 + 12 = 2  (since tan (π/4) = 1)

Hence, we get the slope of the road at a distance x= π/4 as 2.

Explanation

We find the slope of the road at x= π/4 as 2, which means that at a given point, the height of the road would rise at a rate twice the horizontal distance.

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Problem 3

Derive the second derivative of the function y = tan (x).

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The first step is to find the first derivative,

dy/dx = sec2 (x)...(1)

Now we will differentiate equation (1) to get the second derivative:

d2y/ dx2 = d/dx [sec2 (x)]

Here we use the product rule,

d2y / dx2 = 2 sec (x). d/dx [sec (x)]

d2y / dx2 = 2 sec (x). [ sec (x) tan (x)]
 
⇒ 2 sec2(x) tan (x)

Therefore, the second derivative of the function y = tan (x) is 2 sec2(x) tan (x).

Explanation

We use the step-by-step process, where we start with the first derivative. Using the product rule, we differentiate sec2(x).  We then substitute the identity and simplify the terms to find the final answer. 

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Problem 4

Prove: d/dx (tan² (x)) = 2 tan(x) sec² (x).

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Let’s start using the chain rule:

Consider y = tan2 (x)

⇒ [tan (x)]2

To differentiate, we use the chain rule:

dy/dx = 2 tan (x). d/dx [tan (x)]

Since the derivative of tan (x) is sec2 (x),

dy/dx = 2 tan (x). sec2(x)

Substituting y = tan2(x),

d/dx (tan2(x)) = 2 tan (x). sec2(x)

Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace tan (x) with its derivative. As a final step, we substitute y = tan2(x) to derive the equation. 

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Problem 5

Solve: d/dx (tan x/x)

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To differentiate the function, we use the quotient rule:

d/dx (tan x/x) = (d/dx (tan x). X - tan x. d/dx(x))/ x2

We will substitute d/dx (tan x) = sec2x and d/dx (x) = 1

 (sec2 x. x – tan x .1) / x2

= (x sec2 x – tan x) / x2

= x sec2 x – tan x / x2

Therefore, d/dx (tan x/x) = x sec2 x – tan x / x2

Explanation

In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of Tan x

1.Find the derivative of tan x.

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2.Can we use the derivative of tan x in real life?

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3.Is it possible to take the derivative of tan x at the point where x = π/2?

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4.What rule is used to differentiate tan x/ x?

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5.Are the derivatives of tan x and tan⁻¹x the same?

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6.Can we find the derivative of the tan x formula?

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7.How can children in Bahrain use numbers in everyday life to understand Derivative of Tan x?

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8.What are some fun ways kids in Bahrain can practice Derivative of Tan x with numbers?

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9.What role do numbers and Derivative of Tan x play in helping children in Bahrain develop problem-solving skills?

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10.How can families in Bahrain create number-rich environments to improve Derivative of Tan x skills?

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Professor Greenline from BrightChamps

Important Glossaries for the Derivative of Tan x

  • Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x.

 

  • Tangent Function: The tangent function is one of the primary six trigonometric functions and is written as tan x.

 

  • Secant Function: A trigonometric function that is the reciprocal of the cosine function. It is typically represented as sec x.

 

  • First Derivative: It is the initial result of a function, which gives us the rate of change of a specific function.

 

  • Asymptote: The function goes near a line without intersecting or crossing it. This line is known as an asymptote.
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