Last updated on May 26th, 2025
In math, multiples are the products we get while multiplying a number with other numbers. Multiples play a key role in construction and design, counting groups of items, sharing resources equally, and managing time effectively. In this topic, we will learn the essential concepts of multiples of 5000.
Now, let us learn more about multiples of 5000. Multiples of 5000 are the numbers you get when you multiply 5000 by any whole number, along with zero. Each number has an infinite number of multiples, including a multiple of itself. In multiplication, a multiple of 5000 can be denoted as 5000 × n, where ‘n’ represents any whole number (0, 1, 2, 3,…). So, we can summarize that:
Multiple of a number = Number × Any whole number
For example, multiplying 5000 × 1 will give us 5000 as the product. Multiples of 5000 will be larger or equal to 5000.
Multiples of 5000 include the products of 5000 and an integer. Multiples of 5000 are divisible by 5000 evenly. The first few multiples of 5000 are given below:
TABLE OF 5000 (1-10) | |
---|---|
5000 x 1 = 5000 |
5000 x 6 = 30000 |
5000 x 2 = 10000 |
5000 x 7 = 35000 |
5000 x 3 = 15000 |
5000 x 8 = 40000 |
5000 x 4 = 20000 |
5000 x 9 = 45000 |
5000 x 5 = 25000 |
5000 x 10 = 50000 |
TABLE OF 5000 (11-20) | |
---|---|
5000 x 11 = 55000 |
5000 x 16 = 80000 |
5000 x 12 = 60000 |
5000 x 17 = 85000 |
5000 x 13 = 65000 |
5000 x 18 = 90000 |
5000 x 14 = 70000 |
5000 x 19 = 95000 |
5000 x 15 = 75000 |
5000 x 20 = 100000 |
Now, we know the first few multiples of 5000. They are 0, 5000, 10000, 15000, 20000, 25000, 30000, 35000, 40000, 45000, 50000,...
Understanding the multiples of 5000 helps solve mathematical problems and boost our multiplication and division skills. When working with multiples of 5000, we need to apply it to different mathematical operations such as addition, subtraction, multiplication, and division.
5000, 10000, 15000, 20000, and 25000 are the first five multiples of 5000. When multiplying 5000 from 1 to 5, we get these numbers as the products.
So, the sum of these multiples is:
5000 + 10000 + 15000 + 20000 + 25000 = 75000
When we add the first 5 multiples of 5000, the answer will be 75000.
While we do subtraction, it improves our comprehension of how the value decreases when each multiple is subtracted from the previous one. 5000, 10000, 15000, 20000, and 25000 are the first five multiples of 5000. So, let us calculate it as given below:
5000 - 10000 = -5000
-5000 - 15000 = -20000
-20000 - 20000 = -40000
-40000 - 25000 = -65000
Hence, the result of subtracting the first 5 multiples of 5000 is -65000.
To calculate the average, we need to identify the sum of the first 5 multiples of 5000, and then divide it by the count, i.e., 5. Because there are 5 multiples presented in the calculation. Averaging helps us to understand the concepts of central tendencies and other values. We know the sum of the first 5 multiples of 5000 is 75000.
5000 + 10000 + 15000 + 20000 + 25000 = 75000
Next, divide the sum by 5:
75000 ÷ 5 = 15000
15000 is the average of the first 5 multiples of 5000.
The product of given numbers is the result of multiplying all of them together. Here, the first 5 multiples of 5000 include: 5000, 10000, 15000, 20000, and 25000. Now, the product of these numbers is:
5000 × 10000 × 15000 × 20000 × 25000 = 3.75 × 10^20
The product of the first 5 multiples of 5000 is a very large number.
While we perform division, we get to know how many times 5000 can fit into each of the given multiples. 5000, 10000, 15000, 20000, and 25000 are the first 5 multiples of 5000.
5000 ÷ 5000 = 1
10000 ÷ 5000 = 2
15000 ÷ 5000 = 3
20000 ÷ 5000 = 4
25000 ÷ 5000 = 5
The results of dividing the first 5 multiples of 5000 are: 1, 2, 3, 4, and 5.
While working with multiples of 5000, we make common mistakes. Identifying these errors and understanding how to avoid them can be helpful. Below are some frequent mistakes and tips to avoid them:
In a warehouse, boxes of products are packed in batches. Each batch contains 5000 units of a product. If the warehouse restocks its inventory every month with 3 new batches, how many units will be added to the inventory over 6 months?
90,000 units
Each month, the warehouse receives 3 batches of 5000 units each. To find the total number of units added over 6 months, multiply the number of units in a batch by the number of batches per month and the number of months.
Units in each batch = 5000
Batches per month = 3
Number of months = 6
5000 × 3 × 6 = 90,000
Therefore, 90,000 units will be added to the inventory over 6 months.
A company is hosting a series of workshops, each accommodating 5000 participants. If they plan to host workshops for the first three multiples of 5000 participants, how many participants will be accommodated in total?
30,000 participants
The first three multiples of 5000 are 5000, 10,000, and 15,000. The company will host workshops for each of these participant numbers.
5000 × 1 = 5000
5000 × 2 = 10,000
5000 × 3 = 15,000
Total participants = 5000 + 10,000 + 15,000 = 30,000
Hence, a total of 30,000 participants will be accommodated.
At an annual festival, a food stall distributes 5000 servings of snacks each day. If the festival lasts for 8 days, how many servings will be distributed by the end of the festival?
40,000 servings
To find the total number of servings distributed, multiply the number of servings per day by the number of days the festival lasts.
Servings per day = 5000
Number of days = 8
5000 × 8 = 40,000
Therefore, 40,000 servings will be distributed by the end of the festival
A factory produces 5000 gadgets every week. If the production rate remains the same, how many gadgets will the factory produce in 10 weeks?
50,000 gadgets
To find the total number of gadgets produced, multiply the weekly production rate by the number of weeks.
Gadgets per week = 5000
Number of weeks = 10
5000 × 10 = 50,000
Thus, the factory will produce 50,000 gadgets in 10 weeks.
A printing press prints 5000 copies of a book each day. If they print for 7 days continuously, how many copies will be printed in total?
35,000 copies
To determine the total number of copies printed, multiply the daily print rate by the number of days.
Copies per day = 5000
Number of days = 7
5000 × 7 = 35,000
Therefore, 35,000 copies will be printed in total.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables