Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in various fields such as mathematics, physics, and engineering. Here, we will discuss the square root of 51.
The square root is the inverse of squaring a number. The number 51 is not a perfect square, and its square root is expressed in both radical and exponential forms.
In radical form, it is expressed as √51, whereas in exponential form it is (51)^(1/2). The square root of 51 is approximately 7.14143, which is an irrational number because it cannot be expressed as a fraction of two integers.
The prime factorization method is typically used for perfect square numbers. For non-perfect square numbers, the long-division method and approximation method are more suitable. Let's explore the following methods:
The long division method is particularly useful for non-perfect squares. It involves finding the closest perfect square number to the given number. Let's find the square root of 51 using this method, step by step:
Step 1: To begin, we group the numbers from right to left. For 51, we have a single group: 51.
Step 2: Find the largest number whose square is less than or equal to 51. The number is 7, since 7 × 7 = 49. The quotient is 7, and after subtracting 49 from 51, the remainder is 2.
Step 3: Bring down a pair of zeros, making the new dividend 200.
Step 4: Double the quotient (7), resulting in 14, which will be part of our new divisor.
Step 5: Find the largest digit x such that 14x × x is less than or equal to 200. In this case, x is 1, since 141 × 1 = 141.
Step 6: Subtract 141 from 200, leaving a remainder of 59.
Step 7: Since the remainder is less than the divisor, add a decimal point and bring down a pair of zeros, making the new dividend 5900.
Step 8: Continue this process to get a more precise decimal value.
The square root of √51 is approximately 7.14.
The approximation method offers an easy way to estimate square roots. Here's how to approximate the square root of 51:
Step 1: Identify the perfect squares near 51. The closest perfect squares are 49 (7^2) and 64 (8^2). Thus, √51 is between 7 and 8.
Step 2: Use linear interpolation: (Given number - smaller perfect square) / (larger perfect square - smaller perfect square) (51 - 49) / (64 - 49) = 2 / 15 ≈ 0.133
Step 3: Add this decimal to the smaller perfect square's root: 7 + 0.133 = 7.133
So, the approximate square root of 51 is 7.133.
Students often make mistakes when calculating square roots, such as ignoring the negative square root or skipping steps in the long division method. Let's examine some common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √51?
The area of the square is approximately 51 square units.
The area of a square is calculated as side². Given the side length is √51:
Area = (√51)² = 51.
Therefore, the area of the square box is approximately 51 square units.
A square-shaped building measuring 51 square feet is built; if each of the sides is √51, what will be the square feet of half of the building?
25.5 square feet
To find half of the building's area, simply divide the total area by 2. 51 / 2 = 25.5.
Thus, half of the building measures 25.5 square feet.
Calculate √51 x 5.
Approximately 35.70715
First, find the square root of 51, which is approximately 7.14143.
Then multiply by 5: 7.14143 x 5 ≈ 35.70715.
What will be the square root of (45 + 6)?
The square root is 7.
First, find the sum of 45 + 6 = 51.
Then, sqrt(51) ≈ 7.14143.
Therefore, the square root is approximately 7.
Find the perimeter of the rectangle if its length ‘l’ is √51 units and the width ‘w’ is 10 units.
Approximately 34.28286 units.
Perimeter of a rectangle = 2 × (length + width).
Perimeter = 2 × (√51 + 10) ≈ 2 × (7.14143 + 10) ≈ 2 × 17.14143 ≈ 34.28286 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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