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356 LearnersLast updated on September 15, 2025

We will explore the derivative of tan³(x). It is expressed as d/dx (tan³(x)) or (tan³(x))', and its derivative involves applying the chain rule and power rule. The derivative signifies the rate of change of the function tan³(x) within its domain. Key concepts include:
Tangent Function: tan(x) = sin(x)/cos(x).
Power Rule: Used for differentiating functions raised to a power.
Chain Rule: Applied for differentiating composite functions.
The derivative of tan³(x) can be denoted as d/dx (tan³(x)) or (tan³(x))'.
Using the chain rule and power rule, the formula is: d/dx (tan³(x)) = 3 tan²(x) sec²(x).
This formula is valid for all x where cos(x) ≠ 0.
We can derive the derivative of tan³(x) using various methods. The proofs involve trigonometric identities and differentiation rules. Here are some methods used to derive this:
Let's demonstrate the derivation of the derivative of tan³(x) as 3 tan²(x) sec²(x) using these methods:
To differentiate tan³(x) using the chain rule: Consider y = (tan(x))³
We apply the chain rule: dy/dx = 3 (tan(x))² * d/dx(tan(x))
Since d/dx(tan(x)) = sec²(x), we get: dy/dx = 3 tan²(x) sec²(x)
The first principle can also be applied, but it involves more complex computations and is generally not preferred for composite functions like tan³(x).
Express tan³(x) as (tan(x))(tan(x))(tan(x)) and apply the product rule iteratively, which will ultimately result in the same derivative: 3 tan²(x) sec²(x).


Higher-order derivatives are obtained by differentiating a function multiple times. They reveal further nuances of how the function behaves.
For tan³(x): The first derivative is f′(x) = 3 tan²(x) sec²(x).
The second derivative is obtained by differentiating the first derivative.
This process continues to reveal how the rate of change itself changes, offering deeper insights into the function's behavior.
When x is π/2, the derivative is undefined due to the vertical asymptote of tan(x). When x is 0, the derivative of tan³(x) is 0, as tan(0) = 0.
Differentiating tan³(x) can lead to errors if the rules are not applied correctly. Here are common mistakes and tips to avoid them:
Calculate the derivative of tan³(x)·sec²(x)
Let f(x) = tan³(x)·sec²(x). Using the product rule, f'(x) = u′v + uv′
Here, u = tan³(x) and v = sec²(x).
Differentiate each term: u′ = d/dx (tan³(x)) = 3 tan²(x) sec²(x) v′ = d/dx (sec²(x)) = 2 sec²(x) tan(x)
Substitute into the equation: f'(x) = (3 tan²(x) sec²(x))·(sec²(x)) + (tan³(x))·(2 sec²(x) tan(x))
Simplify to get: f'(x) = 3 tan²(x) sec⁴(x) + 2 tan⁴(x) sec²(x)
We find the derivative by using the product rule. First, we differentiate each part separately and then combine them to get the final result.
XYZ Corporation is analyzing a cost function modeled by y = tan³(x) to predict production costs. If x = π/6, calculate the rate of cost change.
Given y = tan³(x), Differentiate: dy/dx = 3 tan²(x) sec²(x)
Substitute x = π/6: tan(π/6) = 1/√3 and sec(π/6) = 2/√3 dy/dx = 3 (1/√3)² (2/√3)² = 3 (1/3) (4/9) = 4/9
The rate of cost change at x = π/6 is 4/9.
We substitute x = π/6 into the derivative formula to find how the cost function changes at that point. Simplifying the trigonometric values gives us the rate of change.
Derive the second derivative of y = tan³(x).
First, find the first derivative: dy/dx = 3 tan²(x) sec²(x)
Now, find the second derivative: d²y/dx² = d/dx [3 tan²(x) sec²(x)]
Use the product rule: d²y/dx² = 3 [2 tan(x) sec²(x) sec²(x) + tan²(x) (2 sec²(x) tan(x))] = 6 tan(x) sec⁴(x) + 6 tan³(x) sec²(x)
Therefore, the second derivative is 6 tan(x) sec⁴(x) + 6 tan³(x) sec²(x).
We differentiate the first derivative using the product rule, taking care to apply the chain rule where necessary. This gives the second derivative of the function.
Prove: d/dx (tan²(x)) = 2 tan(x) sec²(x).
Start with y = tan²(x). Express as [tan(x)]².
Differentiate using the chain rule: dy/dx = 2 tan(x)·d/dx(tan(x)) Since d/dx(tan(x)) = sec²(x), dy/dx = 2 tan(x) sec²(x)
Thus, d/dx(tan²(x)) = 2 tan(x) sec²(x).
We used the chain rule to differentiate tan²(x), substituting the derivative of tan(x) into the equation, resulting in the proven formula.
Solve: d/dx (tan³(x)/x)
Use the quotient rule: d/dx (tan³(x)/x) = (d/dx (tan³(x))·x - tan³(x)·d/dx(x))/x²
Substitute: d/dx(tan³(x)) = 3 tan²(x) sec²(x) and d/dx(x) = 1 = [3 tan²(x) sec²(x)·x - tan³(x)·1]/x² = [3x tan²(x) sec²(x) - tan³(x)]/x²
Therefore, d/dx (tan³(x)/x) = [3 tan²(x) sec²(x) - tan³(x)/x].
We apply the quotient rule to differentiate the given function, carefully simplifying each term to reach the final solution.

Vikrant is a passionate Mathematics teacher with over 5 years of teaching experience in both conventional and Vedic Maths. His student-focused approach combines clear concepts with motivation and encouragement, helping students build confidence and develo
: He loves to play the quiz with kids through algebra to make kids love it.
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