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243 LearnersLast updated on October 22, 2025

We now understand the derivative of -1/x². It is commonly represented as d/dx (-1/x²) or (-1/x²)', and its value is 2/x³. The function -1/x² has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Function: -1/x² is a simple rational function.
Power Rule: Rule for differentiating functions of the form x^n.
Negative Exponents: Understanding how to handle derivatives of negative powers.
The derivative of -1/x² can be denoted as d/dx (-1/x²) or (-1/x²)'.
The formula we use to differentiate -1/x² is: d/dx (-1/x²) = 2/x³
The formula applies to all x where x ≠ 0.
We can derive the derivative of -1/x² using proofs. To show this, we will use differentiation rules. There are several methods we use to prove this, such as:
Using Power Rule
Using Chain Rule
We will now demonstrate that the differentiation of -1/x² results in 2/x³ using the above-mentioned methods:
Using Power Rule The derivative of -1/x² can be found using the Power Rule, which expresses the derivative of x^n as n*x^(n-1).
To find the derivative of -1/x², rewrite the function as f(x) = -x⁻².
Its derivative can be expressed as: f'(x) = d/dx (-x⁻²) = (-2)x^(-2-1) = 2/x³. Thus, the derivative is 2/x³. Hence, proved.
Using Chain Rule
To prove the differentiation of -1/x² using the chain rule, Consider y = -1/x² = -(x⁻²).
Using the chain rule: d/dx [u(x)^n] = n*u(x)^(n-1)*u'(x) Let u(x) = x and n = -2. dy/dx = -2*x^(-2-1). dy/dx = 2/x³.
Thus, the derivative of -1/x² is 2/x³.


When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes.
Higher-order derivatives make it easier to understand functions like -1/x². For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point.
The second derivative is derived from the first derivative, which is denoted using f′′ (x).
Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of -1/x², we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
When x is 0, the derivative is undefined because -1/x² has a vertical asymptote there.
When x is 1, the derivative of -1/x² = 2/1³, which is 2.
Students frequently make mistakes when differentiating -1/x². These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (-1/x²)·(x³)
Here, we have f(x) = (-1/x²)·(x³). Using the product rule, f'(x) = u′v + uv′
In the given equation, u = -1/x² and v = x³.
Let’s differentiate each term, u′= d/dx (-1/x²) = 2/x³ v′= d/dx (x³) = 3x²
Substituting into the given equation, f'(x) = (2/x³)·(x³) + (-1/x²)·(3x²)
Let’s simplify terms to get the final answer, f'(x) = 2 - 3 = -1.
Thus, the derivative of the specified function is -1.
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A water tank is designed as a paraboloid, and the rate of change of the water level with respect to time is represented by the function y = -1/x², where y is the water level at time x. If x = 2 hours, measure the rate of change of the water level.
We have y = -1/x² (rate of change of water level)...(1)
Now, we will differentiate the equation (1)
Take the derivative -1/x²: dy/dx = 2/x³
Given x = 2 (substitute this into the derivative) dy/dx = 2/2³ = 2/8 = 0.25
Hence, we get the rate of change of the water level at x = 2 as 0.25.
We find the rate of change of the water level at x = 2 as 0.25, which means that at a given point, the water level decreases at a rate of 0.25 per unit time.
Derive the second derivative of the function y = -1/x².
The first step is to find the first derivative, dy/dx = 2/x³...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [2/x³]
Here we use the power rule, d²y/dx² = -6/x⁴
Therefore, the second derivative of the function y = -1/x² is -6/x⁴.
We use the step-by-step process, where we start with the first derivative. Using the power rule, we differentiate 2/x³. We then simplify the terms to find the final answer.
Prove: d/dx ((-1/x²)²) = 4/x⁵.
Let’s start using the chain rule: Consider y = (-1/x²)² = [(-1)²] * (x⁻²)²
To differentiate, we use the chain rule: dy/dx = 2 * (-1/x²) * d/dx (-1/x²)
Since the derivative of -1/x² is 2/x³, dy/dx = 4/x⁵ Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace -1/x² with its derivative. As a final step, we simplify the expression to derive the equation.
Solve: d/dx (-1/x² + x)
To differentiate the function, d/dx (-1/x² + x) = d/dx (-1/x²) + d/dx (x)
We will substitute d/dx (-1/x²) = 2/x³ and d/dx (x) = 1 = 2/x³ + 1
Therefore, d/dx (-1/x² + x) = 2/x³ + 1
In this process, we differentiate the given function term by term. As a final step, we simplify the equation to obtain the final result.

Vikrant is a passionate Mathematics teacher with over 5 years of teaching experience in both conventional and Vedic Maths. His student-focused approach combines clear concepts with motivation and encouragement, helping students build confidence and develo
: He loves to play the quiz with kids through algebra to make kids love it.
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