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127 LearnersLast updated on December 11, 2025

A pyramid with a square base consists of a square base and triangular lateral faces. The lateral surface area is the sum of the areas of these triangular faces. Let's take an example of a tent. The fabric covering the tent represents the lateral surface area, excluding the ground. The base square is not included because it is the base of the pyramid.
The lateral surface area can be found by using the slant height “l” and the side length “s” of the square base.
The lateral surface area is calculated by using the formula: Area = 2sl where s is the side length of the base and l is the slant height of the pyramid.
To find the lateral surface area of a pyramid with a square base, follow these steps:
Step 1: Take note of the given parameters.
Step 2: Ensure that all the measurements are in the same unit before calculation.
Step 3: Use the equation, Area = 2sl, to find the lateral surface area. If the slant height (l) is not given, calculate it using the relation between the height of the pyramid, the slant height, and half the side length of the base using the Pythagorean theorem. Once the slant height is known, substitute it into the formula to calculate the lateral surface area.
Step 4: Provide the calculated answer in square units.


There are a few typical mistakes people make while calculating the lateral surface area of a pyramid with a square base.
Some of them are listed below:
What is the lateral surface area of a pyramid with a square base having a side length of 8 cm and a slant height of 10 cm?
160 cm²
Given: Side length = 8 cm, Slant height = 10 cm
LSA = 2sl = 2×8×10 = 160 cm²
If the side length of a square base is q cm, with a slant height of 6 cm and a lateral surface area of 48 cmยฒ, find the value of q.
4 cm
Given: Side length (s) = q cm Slant height (l) = 6 cm LSA = 48 cm²
Using the formula: LSA = 2sl 48 = 2×q×6
Simplify it: 48 = 12q
Identify the value of q: q = 48/12
q = 4 cm
Calculate the lateral surface area of a pyramid with a square base having a side length of 5 cm and a height of 12 cm.
130 cm²
Given: Side length s = 5 cm Height h = 12 cm
To find slant height l: l² = (s/2)² + h²
l² = (5/2)² + 12²
l = √(6.25 + 144)
l = √150.25 ≈ 12.26 cm
Since LSA = 2sl = 2×5×12.26 = 130 cm²
Evaluate the height of a pyramid if its base side length is 9 units and its lateral surface area is 162 square units.
Height of the pyramid = 7.5 units.
Given: Base side length (s) = 9 units
Lateral surface area = 162 square units
Let the slant height = l.
LSA = 2sl
162 = 2×9×l
18l = 162
l = 162/18 = 9 units
Using the relation: l² = (s/2)² + h²
9² = (9/2)² + h²
81 = 20.25 + h²
h² = 60.75
h = √60.75 ≈ 7.5 units
The lateral surface area of a pyramid with a square base is 200 cmยฒ. If its base side length is 10 cm, find its slant height.
10 cm
Let the slant height be “l” cm.
We know that LSA = 2sl ⇒ 200 = 2×10×l ⇒ l = 200/20 ⇒ l = 10 cm

Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables






