Summarize this article:
Last updated on September 15, 2025
We use the derivative of e^-7x, which is -7e^-7x, to understand how the exponential function changes in response to a slight change in x. Derivatives are crucial in calculating rates of change in real-life situations. We will now discuss the derivative of e^-7x in detail.
We now understand the derivative of e^-7x. It is commonly represented as d/dx (e^-7x) or (e^-7x)', and its value is -7e^-7x. The function e^-7x has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below:
Exponential Function: e^-7x is an exponential function with a base of e.
Chain Rule: Rule for differentiating composite functions.
Constant Multiple Rule: Enables differentiation of functions multiplied by a constant.
The derivative of e^-7x can be denoted as d/dx (e^-7x) or (e^-7x)'.
The formula we use to differentiate e^-7x is: d/dx (e^-7x) = -7e^-7x
The formula applies for all x, as the exponential function is continuous everywhere.
We can derive the derivative of e^-7x using proofs. To show this, we will use the rules of differentiation, particularly the chain rule. Here is how we can prove this:
To prove the differentiation of e^-7x using the chain rule, We use the formula:
Let f(x) = e^u where u = -7x
Using the chain rule: d/dx (e^u) = e^u · du/dx
Therefore, d/dx (e^-7x) = e^-7x · d/dx(-7x) = e^-7x · (-7) = -7e^-7x
Hence, proved.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, consider how acceleration (second derivative) is the rate of change of velocity (first derivative). Higher-order derivatives can reveal the behavior of functions like e^-7x.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of e^-7x, we generally use f^(n)(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
Since e^-7x is an exponential function, it is continuous everywhere, and its derivative is defined for all x. The derivative is always negative, indicating that the function is decreasing for all real numbers.
Students frequently make mistakes when differentiating e^-7x. These mistakes can be resolved by understanding the correct methods. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (e^-7x · sin(x))
Here, we have f(x) = e^-7x · sin(x).
Using the product rule, f'(x) = u′v + uv′ In the given equation, u = e^-7x and v = sin(x).
Let’s differentiate each term, u′ = d/dx (e^-7x) = -7e^-7x v′ = d/dx (sin(x)) = cos(x) Substituting into the given equation, f'(x) = (-7e^-7x) · sin(x) + e^-7x · cos(x)
Let’s simplify terms to get the final answer, f'(x) = -7e^-7x · sin(x) + e^-7x · cos(x)
Thus, the derivative of the specified function is -7e^-7x · sin(x) + e^-7x · cos(x).
We find the derivative of the given function by dividing it into two parts. The first step is finding their derivatives and then combining them using the product rule to get the final result.
A scientist is measuring the decay of a radioactive substance, modeled by the function N(t) = e^-7t, where N(t) is the amount of substance remaining at time t. Find the rate of decay when t = 1 hour.
We have N(t) = e^-7t (decay of the substance)...(1)
Now, we will differentiate the equation (1) to find the rate of decay: dN/dt = -7e^-7t
Given t = 1 (substitute this into the derivative) dN/dt = -7e^-7(1) = -7e^-7
Hence, the rate of decay at t = 1 hour is -7e^-7.
We find the rate of decay at t = 1 hour as -7e^-7, which represents the negative rate at which the substance decays over time.
Derive the second derivative of the function y = e^-7x.
The first step is to find the first derivative, dy/dx = -7e^-7x...(1)
Now we will differentiate equation (1) to get the second derivative:
d²y/dx² = d/dx [-7e^-7x] = -7 · d/dx [e^-7x] = -7(-7e^-7x) = 49e^-7x
Therefore, the second derivative of the function y = e^-7x is 49e^-7x.
We use the step-by-step process, starting with the first derivative. By differentiating again, we find the second derivative using the constant multiple and chain rules.
Prove: d/dx (e^-7x²) = -14xe^-7x².
Let’s start using the chain rule: Consider y = e^-7x²
To differentiate, we use the chain rule: dy/dx = e^-7x² · d/dx (-7x²) = e^-7x² · (-14x) = -14xe^-7x²
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. The derivative of the inner function -7x² is -14x, which we multiply with e^-7x² to get the result.
Solve: d/dx (e^-7x/x)
To differentiate the function, we use the quotient rule: d/dx (e^-7x/x) = (d/dx (e^-7x) · x - e^-7x · d/dx(x))/x²
We will substitute d/dx (e^-7x) = -7e^-7x and d/dx(x) = 1 = (-7e^-7x · x - e^-7x · 1)/x² = (-7xe^-7x - e^-7x)/x² = -7xe^-7x - e^-7x/x²
Therefore, d/dx (e^-7x/x) = (-7xe^-7x - e^-7x)/x²
In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.