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Last updated on September 27, 2025
We use the derivative of cos(3x), which is -3sin(3x), as a tool for measuring how the cosine function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of cos(3x) in detail.
We now understand the derivative of cos 3x. It is commonly represented as d/dx (cos 3x) or (cos 3x)', and its value is -3sin(3x). The function cos 3x has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Cosine Function: (cos(3x) is a transformation of the basic cosine function).
Chain Rule: Rule for differentiating cos(3x) due to its composite nature.
Sine Function: sin(x) is the derivative of cos(x).
The derivative of cos 3x can be denoted as d/dx (cos 3x) or (cos 3x)'.
The formula we use to differentiate cos 3x is: d/dx (cos 3x) = -3sin(3x) (or) (cos 3x)' = -3sin(3x) The formula applies to all x.
We can derive the derivative of cos 3x using proofs. To show this, we will use the trigonometric identities along with the rules of differentiation.
There are several methods we use to prove this, such as:
The derivative of cos 3x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of cos 3x using the first principle, we will consider f(x) = cos 3x. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = cos 3x, we write f(x + h) = cos (3(x + h)). Substituting these into equation (1), f'(x) = limₕ→₀ [cos(3(x + h)) - cos 3x] / h = limₕ→₀ [-2sin(3x + 3h/2)sin(3h/2)] / h Using limit formulas, limₕ→₀ (sin(3h/2))/(h/2) = 3. f'(x) = -3sin(3x) Hence, proved.
To prove the differentiation of cos 3x using the chain rule, We use the formula: Cos 3x = cos(u) where u = 3x The derivative of cos(u) is -sin(u), and the derivative of 3x is 3. By chain rule: d/dx [cos(u)] = -sin(u) * du/dx Let’s substitute u = 3x, d/dx (cos 3x) = -sin(3x) * 3 = -3sin(3x)
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like cos(3x).
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x) Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of cos(3x), we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).
When x is 0, the derivative of cos 3x = -3sin(0), which is 0.
At points where 3x is an integer multiple of π, the derivative will also be 0 due to the sine function.
Students frequently make mistakes when differentiating cos 3x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (cos 3x · sin 3x)
Here, we have f(x) = cos 3x·sin 3x. Using the product rule, f'(x) = u′v + uv′ In the given equation, u = cos 3x and v = sin 3x. Let’s differentiate each term, u′ = d/dx (cos 3x) = -3sin(3x) v′ = d/dx (sin 3x) = 3cos(3x) Substituting into the given equation, f'(x) = (-3sin(3x)) (sin 3x) + (cos 3x)(3cos(3x)) Let’s simplify terms to get the final answer, f'(x) = -3sin²(3x) + 3cos²(3x) Thus, the derivative of the specified function is 3(cos²(3x) - sin²(3x)).
We find the derivative of the given function by dividing the function into two parts.
The first step is finding its derivative and then combining them using the product rule to get the final result.
A Ferris wheel's rotation height is represented by y = cos(3x), where y represents the height at angle x. If at x = π/6 radians, determine the rate of change of height with respect to the angle.
We have y = cos(3x) (height of the Ferris wheel)...(1) Now, we will differentiate the equation (1) Take the derivative cos(3x): dy/dx = -3sin(3x) Given x = π/6 (substitute this into the derivative) dy/dx = -3sin(3(π/6)) dy/dx = -3sin(π/2) = -3(1) = -3 Hence, the rate of change of height at x = π/6 is -3.
We find the rate of change of height at x = π/6 as -3, which means that at this point, the height is decreasing at a rate of 3 units per radian.
Derive the second derivative of the function y = cos(3x).
The first step is to find the first derivative, dy/dx = -3sin(3x)...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-3sin(3x)] Here we use the chain rule, d²y/dx² = -3 * 3cos(3x) = -9cos(3x) Therefore, the second derivative of the function y = cos(3x) is -9cos(3x).
We use the step-by-step process, where we start with the first derivative.
Using the chain rule, we differentiate -3sin(3x).
We then substitute and simplify the terms to find the final answer.
Prove: d/dx (sin²(3x)) = 6sin(3x)cos(3x).
Let’s start using the chain rule: Consider y = sin²(3x) = [sin(3x)]² To differentiate, we use the chain rule: dy/dx = 2sin(3x) * d/dx [sin(3x)] The derivative of sin(3x) is 3cos(3x), dy/dx = 2sin(3x) * 3cos(3x) = 6sin(3x)cos(3x) Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation.
Then, we replace sin(3x) with its derivative.
As a final step, we simplify to derive the equation.
Solve: d/dx (cos 3x/x)
To differentiate the function, we use the quotient rule: d/dx (cos 3x/x) = (d/dx (cos 3x) * x - cos 3x * d/dx(x)) / x² We will substitute d/dx (cos 3x) = -3sin(3x) and d/dx (x) = 1 = (-3sin(3x) * x - cos 3x * 1) / x² = (-3xsin(3x) - cos 3x) / x² Therefore, d/dx (cos 3x/x) = (-3xsin(3x) - cos 3x) / x²
In this process, we differentiate the given function using the product rule and quotient rule.
As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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